anonymous
  • anonymous
find dy/dx for y = 3cos(x) + csc(x)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Do you know your derivative rules for trig functions? If not, you can find some here: http://www.sosmath.com/calculus/diff/der03/der03.html
anonymous
  • anonymous
Heere is also a list of basic rules. This is a simple example where you have two functons added together. http://tutorial.math.lamar.edu/pdf/Common_Derivatives_Integrals.pdf
anonymous
  • anonymous
okay so do i just ignore the fact that its dy/dx because the y is already isolated?

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anonymous
  • anonymous
Can you tell me what \[\Large \frac{ dy }{ dx } 3\cos(x)= ?\]
anonymous
  • anonymous
-3sin(x)
anonymous
  • anonymous
Ok and what is \[\Large \frac{dy}{dx} \csc(x)? \]
anonymous
  • anonymous
-csc(x)cot(x)
anonymous
  • anonymous
And when you get that, you add the two together. When you do a derivative of something in the dorm of \[\Large y=f(x)\] You actually have \[\Large \frac{ dy }{ dx }= f'(x)\] This is known as implicit differentiation. You will learn it later on. It is the underlying concept as to what you are doing.
anonymous
  • anonymous
So your final answer is -3sin(x)-csc(x)cot(x)
anonymous
  • anonymous
okay so then its just -3sin(x)-csc(x)cot(x)
anonymous
  • anonymous
It's actually -3sin(x) + (-csc(x)cot(x)) but a positive plus a minus is a minus
anonymous
  • anonymous
thank you very much !!
anonymous
  • anonymous
Great job! Np

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