## -Welp- one year ago http://i.imgur.com/3dAFKoJ.png since it looks like an equilateral triangle but it's not so I have no idea sure if I should use sin or cos.

1. -Welp-

"Find the area of the triangle"

2. -Welp-

Forgot to add that in there

3. Astrophysics

It's not equilateral as the sides are not congruent. We know that $A = \frac{ 1 }{ 2 }bh$ but this is for a right angle triangle |dw:1438328568192:dw| so using this as a reference to draw a new picture

4. Astrophysics

|dw:1438328622099:dw| so for a non right angle triangle we can use the area $A = \frac{ 1 }{ 2 }absinC$

5. Astrophysics

|dw:1438328714694:dw|

6. Astrophysics

Now you just have to plug and chug.

7. -Welp-

thanks

8. Astrophysics

Np

9. Astrophysics

$A = \frac{ 1 }{ 2 }acsinB$ so for you use this

10. anonymous

This isn't equilateral triangle. An equilateral triangle has 60 degrees angle on each sides