-Welp-
  • -Welp-
http://i.imgur.com/3dAFKoJ.png since it looks like an equilateral triangle but it's not so I have no idea sure if I should use sin or cos.
Geometry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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-Welp-
  • -Welp-
"Find the area of the triangle"
-Welp-
  • -Welp-
Forgot to add that in there
Astrophysics
  • Astrophysics
It's not equilateral as the sides are not congruent. We know that \[A = \frac{ 1 }{ 2 }bh\] but this is for a right angle triangle |dw:1438328568192:dw| so using this as a reference to draw a new picture

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Astrophysics
  • Astrophysics
|dw:1438328622099:dw| so for a non right angle triangle we can use the area \[A = \frac{ 1 }{ 2 }absinC\]
Astrophysics
  • Astrophysics
|dw:1438328714694:dw|
Astrophysics
  • Astrophysics
Now you just have to plug and chug.
-Welp-
  • -Welp-
thanks
Astrophysics
  • Astrophysics
Np
Astrophysics
  • Astrophysics
\[A = \frac{ 1 }{ 2 }acsinB\] so for you use this
anonymous
  • anonymous
This isn't equilateral triangle. An equilateral triangle has 60 degrees angle on each sides

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