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anonymous

  • one year ago

What are the factors of 3x2 + 10x + 3

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  1. anonymous
    • one year ago
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    use the quadratic formula to solve this one

  2. pooja195
    • one year ago
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    @Serenaishurting you can also use factoring is you wish

  3. pooja195
    • one year ago
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    *if

  4. anonymous
    • one year ago
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    how?

  5. pooja195
    • one year ago
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    Does it specify which method to use?

  6. anonymous
    • one year ago
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    \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ }\] where \[ax^2+bx+c=0\]

  7. anonymous
    • one year ago
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    no it doesnt

  8. pooja195
    • one year ago
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    ok so you can use the formula then since @saseal typed it out ;p \[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ }\] where \[ax^2+bx+c=0\]

  9. pooja195
    • one year ago
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    Start by listing your abc values

  10. anonymous
    • one year ago
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    \[x=\frac{ -b \pm \sqrt{b^2-4ac}}{ 2a }\]

  11. anonymous
    • one year ago
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    sorry lagged and the 2a didnt show up

  12. anonymous
    • one year ago
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    okay thanks i got it.

  13. anonymous
    • one year ago
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    yw

  14. radar
    • one year ago
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    Another way is possible.....just factor it by noting that both the coefficient of the squared term "3" and the numeric constant is "3" both are prime numbers. This means less trial and error.

  15. radar
    • one year ago
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    It factors quite nicely: (x + 3) (3x + 1)

  16. anonymous
    • one year ago
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    can yall help with another?

  17. anonymous
    • one year ago
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    sure

  18. anonymous
    • one year ago
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    Graph of a cubic polynomial that falls to the left and rises to the right with x intercepts negative 2, negative 1, and 2 Which of the following functions best represents the graph?

  19. anonymous
    • one year ago
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    Which of the following functions best represents the graph? f(x) = x3 + x2 − 4x − 4 f(x) = x3 + 4x2 − x − 4 f(x) = x3 + 3x2 − 4x − 12 f(x) = x3 + 2x2 − 4x − 8

  20. anonymous
    • one year ago
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    your best bet is to graph it out, cubic stuff is pretty messy

  21. anonymous
    • one year ago
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    okay

  22. anonymous
    • one year ago
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    lemme try teaching you how to factor this without graphing

  23. anonymous
    • one year ago
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    okay

  24. radar
    • one year ago
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    This problem is providing you the factors. Just multiply them and get the answer.

  25. anonymous
    • one year ago
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    we take this 1st option\[f(x)=x^3+x^2-4x-4\] we can rewrite this as \[f(x)=x^2(x+1)-4(x-1)\]

  26. radar
    • one year ago
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    |dw:1438351445649:dw|

  27. Nnesha
    • one year ago
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    for directions:when highest degree is an odd number then if leading coefficient is *positive * right end will rise and left end fall and if leading coefficient is *negative* right end will fall and left end will rise

  28. anonymous
    • one year ago
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    oh i got the answer. i just finished the test thanks for yalls help.

  29. anonymous
    • one year ago
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    waddup nnesha

  30. Nnesha
    • one year ago
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    @saseal ??

  31. anonymous
    • one year ago
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    nothing just bored doge

  32. Nnesha
    • one year ago
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    oh

  33. anonymous
    • one year ago
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    whale then.. o.o

  34. pooja195
    • one year ago
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    have more questions? on that test?

  35. pooja195
    • one year ago
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    nvm u finished ;p heres a refrence for next time http://pages.citebite.com/a4o3b6r4a2tjy

  36. anonymous
    • one year ago
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    no i finished it. im gonna have to redo it later though.

  37. pooja195
    • one year ago
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    \(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Huge\bf\color{#FF0000}W\color{#FF4900}e\color{#FF9200}l\color{#FFDB00}c\color{#FFff00}o\color{#B6ff00}m\color{#6Dff00}e\color{#24ff00}~\color{#00ff00}t\color{#00ff49}o\color{#00ff92}~\color{#00ffDB}O\color{#00ffff}p\color{#00DBff}e\color{#0092ff}n\color{#0049ff}S\color{#0000ff}t\color{#2400ff}u\color{#6D00ff}d\color{#B600ff}y\color{#FF00ff}!\)\(~~~~~~~~~~~~~~~~~~~~~~~~~~\Huge{\color{red}{\heartsuit}\color{orange}{\bigstar}\color{yellow}{\heartsuit}\color{green}{\bigstar}\color{blue}{\heartsuit}\color{purple}{\bigstar}\color{hotpink}{\heartsuit}}\)\(\Large\bf\color{Lime}{Please,\ don't\ hesitate\ to\ ask\ questions!}\)\(\Large\bf\color{magenta}{We're\ here\ to\ help!}\Large\color{magenta}{\ddot\smile}\)

  38. pooja195
    • one year ago
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    Since you are new im sure you werent aware of the anti cheating policy so please dont ask any test questions on that site we dont want u to get banned

  39. anonymous
    • one year ago
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    how do u do that @pooja195

  40. anonymous
    • one year ago
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    okay..others do it though...

  41. pooja195
    • one year ago
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    Just because others do it doesnt mean u have to do it

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