Math question. Please explain how to get the answer.

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- anonymous

Math question. Please explain how to get the answer.

- jamiebookeater

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- anonymous

\[\frac{ 3(n+1)! }{ 5n! }\]

- anonymous

Need Help?

- anonymous

Yes please

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## More answers

- anonymous

Okay let me see.

- triciaal

do you have answer choices ?

- anonymous

What are the answer choices for this problem?

- anonymous

By the way this is a really good site to use.
https://www.mathway.com/

- anonymous

It shows you the steps..

- anonymous

No I don't have any answer choices @triciaal

- anonymous

and @AnonymousHelper

- anonymous

Ok

- anonymous

Have you ever tried that site.

- triciaal

|dw:1438355786042:dw|

- Nnesha

1st step) subtract one

- anonymous

No I haven's tried that site. I just tried and it said I had to upgrade. Would I need to pay? @AnonymousHelper

- anonymous

How did you get (n) (n-1) (n-2)? @triciaal

- anonymous

I don't think so.. @200205650

- anonymous

@Nnesha What am I subtracting 1 from?

- anonymous

I do have to pay @AnonymousHelper

##### 1 Attachment

- Nnesha

at the numerator n+1 by
n+1-1 = n
subtract one again n-1
one more time n-1-1 = n -2 right
you need to keep subtracting by one ntill you get anything to divide with at the denominator

- Nnesha

that's a calculator
if you want step then YES you have to pay :D

- anonymous

Ya I just noticed that. And so I just need to subtract 1 until I get n-5?

- Nnesha

if you do simple question like
5! \[5 \times 4 \times 3 \times 2 \times 1\]
here you are subtracting one right so same method for that one too

- Nnesha

well for this question subtract one 't the denominator and t the numerator

- anonymous

So triciaal did it right then. You are suppose to keep multiplying both the numerator and denominator so you can get rid of like terms?

- Nnesha

yes right you need *LIke terms * to cancel out

- anonymous

So the answer is 3(n+1)/5?

- anonymous

Ohh okay sorry about that.. @200205650

- anonymous

That's fine @AnonymousHelper

- Nnesha

\[\frac{ 3(n+1)! }{ 5n!} = \frac{ 3(n+1\color{reD}{-1}) (n\color{ReD}{-1})(n-1\color{reD}{-1}) }{ 5(n\color{ReD}{-1})(n-1\color{reD}{-1}) }\]

- Nnesha

yes that's right

- anonymous

Okay thanks!

- Nnesha

np

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