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anonymous

  • one year ago

Math question. Please explain how to get the answer.

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  1. anonymous
    • one year ago
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    \[\frac{ 3(n+1)! }{ 5n! }\]

  2. anonymous
    • one year ago
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    Need Help?

  3. anonymous
    • one year ago
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    Yes please

  4. anonymous
    • one year ago
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    Okay let me see.

  5. triciaal
    • one year ago
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    do you have answer choices ?

  6. anonymous
    • one year ago
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    What are the answer choices for this problem?

  7. anonymous
    • one year ago
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    By the way this is a really good site to use. https://www.mathway.com/

  8. anonymous
    • one year ago
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    It shows you the steps..

  9. anonymous
    • one year ago
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    No I don't have any answer choices @triciaal

  10. anonymous
    • one year ago
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    and @AnonymousHelper

  11. anonymous
    • one year ago
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    Ok

  12. anonymous
    • one year ago
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    Have you ever tried that site.

  13. triciaal
    • one year ago
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    |dw:1438355786042:dw|

  14. Nnesha
    • one year ago
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    1st step) subtract one

  15. anonymous
    • one year ago
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    No I haven's tried that site. I just tried and it said I had to upgrade. Would I need to pay? @AnonymousHelper

  16. anonymous
    • one year ago
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    How did you get (n) (n-1) (n-2)? @triciaal

  17. anonymous
    • one year ago
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    I don't think so.. @200205650

  18. anonymous
    • one year ago
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    @Nnesha What am I subtracting 1 from?

  19. anonymous
    • one year ago
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    I do have to pay @AnonymousHelper

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  20. Nnesha
    • one year ago
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    at the numerator n+1 by n+1-1 = n subtract one again n-1 one more time n-1-1 = n -2 right you need to keep subtracting by one ntill you get anything to divide with at the denominator

  21. Nnesha
    • one year ago
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    that's a calculator if you want step then YES you have to pay :D

  22. anonymous
    • one year ago
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    Ya I just noticed that. And so I just need to subtract 1 until I get n-5?

  23. Nnesha
    • one year ago
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    if you do simple question like 5! \[5 \times 4 \times 3 \times 2 \times 1\] here you are subtracting one right so same method for that one too

  24. Nnesha
    • one year ago
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    well for this question subtract one 't the denominator and t the numerator

  25. anonymous
    • one year ago
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    So triciaal did it right then. You are suppose to keep multiplying both the numerator and denominator so you can get rid of like terms?

  26. Nnesha
    • one year ago
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    yes right you need *LIke terms * to cancel out

  27. anonymous
    • one year ago
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    So the answer is 3(n+1)/5?

  28. anonymous
    • one year ago
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    Ohh okay sorry about that.. @200205650

  29. anonymous
    • one year ago
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    That's fine @AnonymousHelper

  30. Nnesha
    • one year ago
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    \[\frac{ 3(n+1)! }{ 5n!} = \frac{ 3(n+1\color{reD}{-1}) (n\color{ReD}{-1})(n-1\color{reD}{-1}) }{ 5(n\color{ReD}{-1})(n-1\color{reD}{-1}) }\]

  31. Nnesha
    • one year ago
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    yes that's right

  32. anonymous
    • one year ago
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    Okay thanks!

  33. Nnesha
    • one year ago
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    np

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