## anonymous one year ago Math question. Please explain how to get the answer.

1. anonymous

$\frac{ 3(n+1)! }{ 5n! }$

2. anonymous

Need Help?

3. anonymous

4. anonymous

Okay let me see.

5. triciaal

do you have answer choices ?

6. anonymous

What are the answer choices for this problem?

7. anonymous

By the way this is a really good site to use. https://www.mathway.com/

8. anonymous

It shows you the steps..

9. anonymous

No I don't have any answer choices @triciaal

10. anonymous

and @AnonymousHelper

11. anonymous

Ok

12. anonymous

Have you ever tried that site.

13. triciaal

|dw:1438355786042:dw|

14. Nnesha

1st step) subtract one

15. anonymous

No I haven's tried that site. I just tried and it said I had to upgrade. Would I need to pay? @AnonymousHelper

16. anonymous

How did you get (n) (n-1) (n-2)? @triciaal

17. anonymous

I don't think so.. @200205650

18. anonymous

@Nnesha What am I subtracting 1 from?

19. anonymous

I do have to pay @AnonymousHelper

20. Nnesha

at the numerator n+1 by n+1-1 = n subtract one again n-1 one more time n-1-1 = n -2 right you need to keep subtracting by one ntill you get anything to divide with at the denominator

21. Nnesha

that's a calculator if you want step then YES you have to pay :D

22. anonymous

Ya I just noticed that. And so I just need to subtract 1 until I get n-5?

23. Nnesha

if you do simple question like 5! $5 \times 4 \times 3 \times 2 \times 1$ here you are subtracting one right so same method for that one too

24. Nnesha

well for this question subtract one 't the denominator and t the numerator

25. anonymous

So triciaal did it right then. You are suppose to keep multiplying both the numerator and denominator so you can get rid of like terms?

26. Nnesha

yes right you need *LIke terms * to cancel out

27. anonymous

So the answer is 3(n+1)/5?

28. anonymous

Ohh okay sorry about that.. @200205650

29. anonymous

That's fine @AnonymousHelper

30. Nnesha

$\frac{ 3(n+1)! }{ 5n!} = \frac{ 3(n+1\color{reD}{-1}) (n\color{ReD}{-1})(n-1\color{reD}{-1}) }{ 5(n\color{ReD}{-1})(n-1\color{reD}{-1}) }$

31. Nnesha

yes that's right

32. anonymous

Okay thanks!

33. Nnesha

np