anonymous
  • anonymous
Can someone please help me with this problem? Thanks! :)
Mathematics
schrodinger
  • schrodinger
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triciaal
  • triciaal
question/problem?
anonymous
  • anonymous
It's in the attachment!
welshfella
  • welshfella
i cant see any attachment

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anonymous
  • anonymous
The conical tank below is filled with liquid. How much liquid has poured from the top of the cone if the water level is 9 feet from the tip? Radius=4 ft Height=12 ft A) 67pi ft^3 B) 57 pi ft^3 C) 47pi ft^3 D) 37pi ft^3 E) 27pi ft^3
welshfella
  • welshfella
|dw:1438356099057:dw|
welshfella
  • welshfella
|dw:1438356185212:dw|
welshfella
  • welshfella
basically here we have 2 cones and the amount of liquid pored out is the difference in volumes of the large and small cones
welshfella
  • welshfella
Volume of large cone = 1/3 pi r^2 h = (1/3) pi 4^2 * 12 Now we need to find the radius of the small cone can you do that?
anonymous
  • anonymous
How would you do that?
welshfella
  • welshfella
|dw:1438356403629:dw|
anonymous
  • anonymous
Ah....I get it now! So after setting up a ratio proportion, I can subtract the volume of the smaller cone from that of the larger cone, right?
welshfella
  • welshfella
yes
welshfella
  • welshfella
9 /12 = x /8
anonymous
  • anonymous
Ok! Thank you so much for your help! I really appreciated it!
triciaal
  • triciaal
I think the first sketch is correct 9 ft from the top
welshfella
  • welshfella
x would be the diameter so you need to half that to get radius to work out the volume
welshfella
  • welshfella
- oh yea - i took the tip to mean the point of the cone
welshfella
  • welshfella
if you dont get one of the options the you'll have to change the values
anonymous
  • anonymous
ok...got it! thanks for the reminder!
triciaal
  • triciaal
so sorry I read top
welshfella
  • welshfella
- yes - I thought it was top too

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