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It's in the attachment!
i cant see any attachment
The conical tank below is filled with liquid. How much liquid has poured from the top of the cone if the water level is 9 feet from the tip? Radius=4 ft Height=12 ft A) 67pi ft^3 B) 57 pi ft^3 C) 47pi ft^3 D) 37pi ft^3 E) 27pi ft^3
basically here we have 2 cones and the amount of liquid pored out is the difference in volumes of the large and small cones
Volume of large cone = 1/3 pi r^2 h = (1/3) pi 4^2 * 12 Now we need to find the radius of the small cone can you do that?
How would you do that?
Ah....I get it now! So after setting up a ratio proportion, I can subtract the volume of the smaller cone from that of the larger cone, right?
9 /12 = x /8
Ok! Thank you so much for your help! I really appreciated it!
I think the first sketch is correct 9 ft from the top
x would be the diameter so you need to half that to get radius to work out the volume
- oh yea - i took the tip to mean the point of the cone
if you dont get one of the options the you'll have to change the values
ok...got it! thanks for the reminder!
so sorry I read top
- yes - I thought it was top too