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- anonymous

Can someone please help me with this problem? Thanks! :)

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- anonymous

Can someone please help me with this problem? Thanks! :)

- schrodinger

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- triciaal

question/problem?

- anonymous

It's in the attachment!

- welshfella

i cant see any attachment

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- anonymous

The conical tank below is filled with liquid. How much liquid has poured from the top of the cone if the water level is 9 feet from the tip?
Radius=4 ft
Height=12 ft
A) 67pi ft^3
B) 57 pi ft^3
C) 47pi ft^3
D) 37pi ft^3
E) 27pi ft^3

- welshfella

|dw:1438356099057:dw|

- welshfella

|dw:1438356185212:dw|

- welshfella

basically here we have 2 cones and the amount of liquid pored out is the difference in volumes of the large and small cones

- welshfella

Volume of large cone = 1/3 pi r^2 h = (1/3) pi 4^2 * 12
Now we need to find the radius of the small cone
can you do that?

- anonymous

How would you do that?

- welshfella

|dw:1438356403629:dw|

- anonymous

Ah....I get it now! So after setting up a ratio proportion, I can subtract the volume of the smaller cone from that of the larger cone, right?

- welshfella

yes

- welshfella

9 /12 = x /8

- anonymous

Ok! Thank you so much for your help! I really appreciated it!

- triciaal

I think the first sketch is correct 9 ft from the top

- welshfella

x would be the diameter so you need to half that to get radius to work out the volume

- welshfella

- oh yea - i took the tip to mean the point of the cone

- welshfella

if you dont get one of the options the you'll have to change the values

- anonymous

ok...got it! thanks for the reminder!

- triciaal

so sorry I read top

- welshfella

- yes - I thought it was top too

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