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anonymous

  • one year ago

Will medal and fan!!! Need help quick Create a quadratic polynomial function f(x) and a linear binomial in the form (x − a). Part 1. Show all work using long division to divide your polynomial by the binomial. Part 2. Show all work to evaluate f(a) using the function you created. Part 3. Use complete sentences to explain how the remainder theorem is used to determine whether your linear binomial is a factor of your polynomial function

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  1. anonymous
    • one year ago
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    @ganeshie8 @triciaal @nincompoop

  2. anonymous
    • one year ago
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    @ganeshie8 @triciaal @nincompoop

  3. triciaal
    • one year ago
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    quadratic highest power is 2 a(x-h)^2 + k

  4. anonymous
    • one year ago
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    so do i just plug in numbers?

  5. triciaal
    • one year ago
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    linear from a line power of x is 1

  6. triciaal
    • one year ago
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    yes

  7. anonymous
    • one year ago
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    ok

  8. triciaal
    • one year ago
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    ax^2 + bx + c is your quadratic polynomial standard form

  9. anonymous
    • one year ago
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    so a=2 h=3 k=5 x=1

  10. triciaal
    • one year ago
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    hint let a be a factor of c

  11. anonymous
    • one year ago
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    ok so a=2 b=8 c=4

  12. triciaal
    • one year ago
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    |dw:1438357525560:dw|

  13. anonymous
    • one year ago
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    so whats the answer

  14. anonymous
    • one year ago
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    i see it now @triciaal thx

  15. triciaal
    • one year ago
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    in my example

  16. triciaal
    • one year ago
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    when x-a is a factor there is no remainder

  17. anonymous
    • one year ago
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    um but what about part 2

  18. triciaal
    • one year ago
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    |dw:1438357829613:dw|

  19. anonymous
    • one year ago
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    so that is the real answer

  20. anonymous
    • one year ago
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    is that the real Answer @triciaal

  21. triciaal
    • one year ago
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    read the question slowly

  22. anonymous
    • one year ago
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    um so is that the answer

  23. triciaal
    • one year ago
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    1. make up your function 2. do the long division 3. Part 2 find f(a) let x = a and substitute in your function to find the value 4. Part 3 I already answered above (if a factor no remainder ....)

  24. anonymous
    • one year ago
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    so the equation above is not the answer

  25. triciaal
    • one year ago
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    |dw:1438358332305:dw|

  26. triciaal
    • one year ago
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    |dw:1438358641303:dw|

  27. triciaal
    • one year ago
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    do you have any questions about the steps?

  28. anonymous
    • one year ago
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    um so the one above is the answer

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