I need help!! Find the volume for the regular pyramid. V=

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

I need help!! Find the volume for the regular pyramid. V=

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
are all sides 4 units long? right?
yes

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

we have to understand where is the intersection point P|dw:1438359138429:dw| between the height of your pyramid and its base. Have you any idea about that?
I think that P is the common point of the three bisectors of the triangle
i have no clue
|dw:1438359407990:dw| it is the base triangle
|dw:1438359464896:dw|
oh.....
Still clueless lol
we have to find the measure of the height of your pyramid
oh ok
would it be 8
I don't know, in order to find the height of yopur pyramid I have to find this length: |dw:1438359730025:dw| namely the distance between each vertex of the triangle and the point P
oh ummmm is it 4
because it looks like it may be 4
we have to compute it first
ok
I'm pondering...
lol okay me too
There exists a theorem which states that the distance x is given by the subsequent formula: \[\Large x = \frac{{4\sqrt 3 }}{3}\]
thats okay i finished the lesson
so, in order to compute the height of your pyramid we can apply the theorem of Pitagora: |dw:1438360380159:dw|
there fore we can write this: \[\Large h = \sqrt {{4^2} - {x^2}} = \sqrt {16 - \frac{{16 \times 3}}{9}} = ...?\]
oops..therefore*
hint: \[\Large h = \sqrt {{4^2} - {x^2}} = \sqrt {16 - \frac{{16 \times 3}}{9}} = 4\sqrt {\frac{2}{3}} \] so being the base area A equal to: \[\Large A = \frac{{4 \times 2\sqrt 3 }}{2} = 4\sqrt 3 \] the requested volume V is: \[\Large V = \frac{{A \times h}}{3} = \frac{1}{3} \times 4\sqrt 3 \times 4\sqrt {\frac{2}{3}} = ...?\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question