HELP ME PLEASE The function f(x) = −x2 + 48x − 432 models the profit, in dollars, a game developer makes for selling a new game, where x is the number of games sold and f(x) is the amount of profit. Part A: Determine the vertex. What does this calculation mean in the context of the problem? (5 points) Part B: Determine the x-intercepts. What do these values mean in the context of the problem? (5 points)

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HELP ME PLEASE The function f(x) = −x2 + 48x − 432 models the profit, in dollars, a game developer makes for selling a new game, where x is the number of games sold and f(x) is the amount of profit. Part A: Determine the vertex. What does this calculation mean in the context of the problem? (5 points) Part B: Determine the x-intercepts. What do these values mean in the context of the problem? (5 points)

Mathematics
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Use \(\sf -\dfrac{b}{2a}\) to find the x-value of the vertex.
The function is in the form of \(\sf ax^2 + bx + c\).

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do you know how to complete the square to put the function in vertex form? a(x-h)^2 + k = 0 h = -b/(2a) the vertex will be (h, k)
ok
@triciaal We don't nee it in vertex form to use \(\sf -\dfrac{b}{2a}\)
need*
Alright .-.
the vertex is at is the highest or lowest y-value when a is negative the parabola opens down so your vertex is at the maximum y
@iGreen -b/(2a) is your h
\(\sf \color{red}ax^2 + \color{blue}bx + \color{lime} c\) \(\sf \color{red}{-1}x^2 + \color{blue}{48}x \color{lime}{- 432}\)
Yes, then after we find 'h', we can plug it back into \(\sf -x^2 + 48x - 432\).
To find 'k'
OK :D
Yep, just plug in the values into \(\sf -\dfrac{b}{2a}\) first.
@DarkMoonZ do you have any questions about my response?
No I have none thanks guys
Triciall give Igreen a medal for me XD
There's no need. If you want, you can tag us back to check your work.
Ok thanks
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