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anonymous

  • one year ago

HELP ME PLEASE The function f(x) = −x2 + 48x − 432 models the profit, in dollars, a game developer makes for selling a new game, where x is the number of games sold and f(x) is the amount of profit. Part A: Determine the vertex. What does this calculation mean in the context of the problem? (5 points) Part B: Determine the x-intercepts. What do these values mean in the context of the problem? (5 points)

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  1. anonymous
    • one year ago
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    @laughoutloud

  2. iGreen
    • one year ago
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    Use \(\sf -\dfrac{b}{2a}\) to find the x-value of the vertex.

  3. iGreen
    • one year ago
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    The function is in the form of \(\sf ax^2 + bx + c\).

  4. triciaal
    • one year ago
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    do you know how to complete the square to put the function in vertex form? a(x-h)^2 + k = 0 h = -b/(2a) the vertex will be (h, k)

  5. anonymous
    • one year ago
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    ok

  6. iGreen
    • one year ago
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    @triciaal We don't nee it in vertex form to use \(\sf -\dfrac{b}{2a}\)

  7. iGreen
    • one year ago
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    need*

  8. anonymous
    • one year ago
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    Alright .-.

  9. triciaal
    • one year ago
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    the vertex is at is the highest or lowest y-value when a is negative the parabola opens down so your vertex is at the maximum y

  10. triciaal
    • one year ago
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    @iGreen -b/(2a) is your h

  11. iGreen
    • one year ago
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    \(\sf \color{red}ax^2 + \color{blue}bx + \color{lime} c\) \(\sf \color{red}{-1}x^2 + \color{blue}{48}x \color{lime}{- 432}\)

  12. iGreen
    • one year ago
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    Yes, then after we find 'h', we can plug it back into \(\sf -x^2 + 48x - 432\).

  13. iGreen
    • one year ago
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    To find 'k'

  14. anonymous
    • one year ago
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    OK :D

  15. iGreen
    • one year ago
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    Yep, just plug in the values into \(\sf -\dfrac{b}{2a}\) first.

  16. triciaal
    • one year ago
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    @DarkMoonZ do you have any questions about my response?

  17. anonymous
    • one year ago
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    No I have none thanks guys

  18. anonymous
    • one year ago
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    Triciall give Igreen a medal for me XD

  19. iGreen
    • one year ago
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    There's no need. If you want, you can tag us back to check your work.

  20. anonymous
    • one year ago
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    Ok thanks

  21. triciaal
    • one year ago
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  22. triciaal
    • one year ago
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    |dw:1438360807312:dw|

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