anonymous
  • anonymous
Is this anwer right?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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taramgrant0543664
  • taramgrant0543664
So for the bottom it can't be 4 imp for you put 4 in there it will equal 0 for the top you can't but -5 in or else the top will be 0
anonymous
  • anonymous
its the 3rd one

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anonymous
  • anonymous
Need explanation?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
btw can you medal her so i medal you.
anonymous
  • anonymous
Your denominator can never be 0. \[\frac{ (-4)+5 }{ (4)^2+4(4) -32}=\frac{ 1 }{ 16+16-32 } = \frac{ 1 }{ 0 }\] \[\frac{ (-8)+5 }{ (-8)^2+4(-8)-32 } = \frac{ -3 }{ 64-32-32 } = \frac{ -3 }{ 0 }\]
anonymous
  • anonymous
so i would factor the bottom?
anonymous
  • anonymous
yea, your numerator can be 0 but not your denominator

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