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anonymous
 one year ago
1.) The area of a parallelogram is 240 cm2 and the height is 20 cm. Find the corresponding base.
My answer is: 12cm. Is that correct?
2.) In trapezoid PQRS, line PQ is parallel to line SR. Find the area of PQRS. Leave your answer is simplest radical form.
http://assets.openstudy.com/updates/attachments/55bac812e4b0aa1bfb5cf0dflollygirl2171438359455247as.jpg
My answer: 144+72 3. Is that correct?
3.) A kite has diagonals 5.3 ft and 6 ft. What is the area of the kite?
My answer: 5.65 ft squared. Is that correct?
anonymous
 one year ago
1.) The area of a parallelogram is 240 cm2 and the height is 20 cm. Find the corresponding base. My answer is: 12cm. Is that correct? 2.) In trapezoid PQRS, line PQ is parallel to line SR. Find the area of PQRS. Leave your answer is simplest radical form. http://assets.openstudy.com/updates/attachments/55bac812e4b0aa1bfb5cf0dflollygirl2171438359455247as.jpg My answer: 144+72 3. Is that correct? 3.) A kite has diagonals 5.3 ft and 6 ft. What is the area of the kite? My answer: 5.65 ft squared. Is that correct?

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AaronAndyson
 one year ago
Best ResponseYou've already chosen the best response.0First:Correct. Second:I've no clue. And for the third... Area = \[\frac{ 5.3 \times 6 }{ 2 }\]

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.0I was thinking the same thing as Aaron actually but when I tried that second one I didn't get that answer what did you do to get that answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for second, \[A={1\over2}(\text{sum of parallel sides})\times{\rm height}\] You need to calculate the length of SR and the height using the right triangle on the right

phi
 one year ago
Best ResponseYou've already chosen the best response.11) is ok 2) is the area of the trapezoid + area of triangle on the right using 306090 triangle, the height of the triangle (and trapezoid) is 1/2 they hypotenuse so h= 12 area of trap is 1/2(18+6)* 12 = 6*24= 144 area of tri is 1/2 ( 12 sqr(3) * 12)= 72 sqr3 added: \( 144 + 72 \sqrt{3} \) 3) area is product of the diagonals divided by 2, so 3*5.3 = 15.9
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