anonymous
  • anonymous
1.) The area of a parallelogram is 240 cm2 and the height is 20 cm. Find the corresponding base. My answer is: 12cm. Is that correct? 2.) In trapezoid PQRS, line PQ is parallel to line SR. Find the area of PQRS. Leave your answer is simplest radical form. http://assets.openstudy.com/updates/attachments/55bac812e4b0aa1bfb5cf0df-lollygirl217-1438359455247-as.jpg My answer: 144+72 3. Is that correct? 3.) A kite has diagonals 5.3 ft and 6 ft. What is the area of the kite? My answer: 5.65 ft squared. Is that correct?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@mathmath333
AaronAndyson
  • AaronAndyson
First:Correct. Second:I've no clue. And for the third... Area = \[\frac{ 5.3 \times 6 }{ 2 }\]
taramgrant0543664
  • taramgrant0543664
I was thinking the same thing as Aaron actually but when I tried that second one I didn't get that answer what did you do to get that answer?

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anonymous
  • anonymous
for second, \[A={1\over2}(\text{sum of parallel sides})\times{\rm height}\] You need to calculate the length of SR and the height using the right triangle on the right
anonymous
  • anonymous
Am I right guys??
phi
  • phi
1) is ok 2) is the area of the trapezoid + area of triangle on the right using 30-60-90 triangle, the height of the triangle (and trapezoid) is 1/2 they hypotenuse so h= 12 area of trap is 1/2(18+6)* 12 = 6*24= 144 area of tri is 1/2 ( 12 sqr(3) * 12)= 72 sqr3 added: \( 144 + 72 \sqrt{3} \) 3) area is product of the diagonals divided by 2, so 3*5.3 = 15.9

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