## anonymous one year ago 1.) The area of a parallelogram is 240 cm2 and the height is 20 cm. Find the corresponding base. My answer is: 12cm. Is that correct? 2.) In trapezoid PQRS, line PQ is parallel to line SR. Find the area of PQRS. Leave your answer is simplest radical form. http://assets.openstudy.com/updates/attachments/55bac812e4b0aa1bfb5cf0df-lollygirl217-1438359455247-as.jpg My answer: 144+72 3. Is that correct? 3.) A kite has diagonals 5.3 ft and 6 ft. What is the area of the kite? My answer: 5.65 ft squared. Is that correct?

1. anonymous

@mathmath333

2. AaronAndyson

First:Correct. Second:I've no clue. And for the third... Area = $\frac{ 5.3 \times 6 }{ 2 }$

3. taramgrant0543664

I was thinking the same thing as Aaron actually but when I tried that second one I didn't get that answer what did you do to get that answer?

4. anonymous

for second, $A={1\over2}(\text{sum of parallel sides})\times{\rm height}$ You need to calculate the length of SR and the height using the right triangle on the right

5. anonymous

Am I right guys??

6. phi

1) is ok 2) is the area of the trapezoid + area of triangle on the right using 30-60-90 triangle, the height of the triangle (and trapezoid) is 1/2 they hypotenuse so h= 12 area of trap is 1/2(18+6)* 12 = 6*24= 144 area of tri is 1/2 ( 12 sqr(3) * 12)= 72 sqr3 added: $$144 + 72 \sqrt{3}$$ 3) area is product of the diagonals divided by 2, so 3*5.3 = 15.9