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- anonymous

1.) The area of a parallelogram is 240 cm2 and the height is 20 cm. Find the corresponding base.
My answer is: 12cm. Is that correct?
2.) In trapezoid PQRS, line PQ is parallel to line SR. Find the area of PQRS. Leave your answer is simplest radical form.
http://assets.openstudy.com/updates/attachments/55bac812e4b0aa1bfb5cf0df-lollygirl217-1438359455247-as.jpg
My answer: 144+72 3. Is that correct?
3.) A kite has diagonals 5.3 ft and 6 ft. What is the area of the kite?
My answer: 5.65 ft squared. Is that correct?

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- anonymous

- jamiebookeater

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- anonymous

- AaronAndyson

First:Correct.
Second:I've no clue.
And for the third...
Area = \[\frac{ 5.3 \times 6 }{ 2 }\]

- taramgrant0543664

I was thinking the same thing as Aaron actually but when I tried that second one I didn't get that answer what did you do to get that answer?

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- anonymous

for second,
\[A={1\over2}(\text{sum of parallel sides})\times{\rm height}\]
You need to calculate the length of SR and the height using the right triangle on the right

- anonymous

Am I right guys??

- phi

1) is ok
2) is the area of the trapezoid + area of triangle on the right
using 30-60-90 triangle, the height of the triangle (and trapezoid) is 1/2 they hypotenuse
so h= 12
area of trap is 1/2(18+6)* 12 = 6*24= 144
area of tri is 1/2 ( 12 sqr(3) * 12)= 72 sqr3
added: \( 144 + 72 \sqrt{3} \)
3) area is product of the diagonals divided by 2, so 3*5.3 = 15.9

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