anonymous
  • anonymous
use the law of cosines to find the value of 2⋅3⋅4 cosθ
Geometry
chestercat
  • chestercat
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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
what do you mean by 2⋅3⋅4 cosθ You mean \[\cos 2\theta\quad,\cos3\theta,\quad \cos3\theta\]?

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taramgrant0543664
  • taramgrant0543664
Do you have a triangle that corresponds to this question?
anonymous
  • anonymous
|dw:1438361201942:dw|
taramgrant0543664
  • taramgrant0543664
This is the law c^2=A^2+b^2−2abcosC
anonymous
  • anonymous
21
taramgrant0543664
  • taramgrant0543664
4=16+9-2(4)(3)cosC 21=24cosC 0.875=cosC C= 28.96
anonymous
  • anonymous
A. 24 B. 21 C. -24 D. -21
taramgrant0543664
  • taramgrant0543664
I just understood the whole 2,3,4 thing and ya it is equal to 21 I just assume you had to solve for the angle
anonymous
  • anonymous
so is it 21 then
taramgrant0543664
  • taramgrant0543664
Yes it is
anonymous
  • anonymous
thanks
anonymous
  • anonymous
can you help me with another question please? @taramgrant0543664
taramgrant0543664
  • taramgrant0543664
I can try!
anonymous
  • anonymous
ok
anonymous
  • anonymous
|dw:1438362470160:dw|
anonymous
  • anonymous
true or false
anonymous
  • anonymous
anonymous
  • anonymous
nvm
anonymous
  • anonymous
wrong problem
anonymous
  • anonymous
Suppose a triangle has sides a, b, and c, and that a2 + b2 > c2. Let be the measure of the angle opposite the side of length c. Which of the following must be true? Check all that apply.
anonymous
  • anonymous
A. cos < 0 B. cos > 0 C. is an acute angle. D. The triangle in question is a right triangle.
anonymous
  • anonymous
taramgrant0543664
  • taramgrant0543664
I'd like to think it would be D but I'm not certain
anonymous
  • anonymous
its more than 1 answer
anonymous
  • anonymous
i think its a and d
anonymous
  • anonymous
what do you think
taramgrant0543664
  • taramgrant0543664
A and D that's what I'm thinking
anonymous
  • anonymous
yup yup
anonymous
  • anonymous
Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true?
anonymous
  • anonymous
how about this one
anonymous
  • anonymous
A. b2 + c2 < a2 B. a2 + c2 > b2 C. a2 + c2 < b2 D. a2 + b2 < c2
anonymous
  • anonymous
anonymous
  • anonymous
i think it a @taramgrant0543664
taramgrant0543664
  • taramgrant0543664
Ya I was trying to think it out and I was thinking it was A but I was testing out the other options too to double check
anonymous
  • anonymous
that good
anonymous
  • anonymous
it wasnt a
anonymous
  • anonymous
its aight
phi
  • phi
Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true? they tell you about angle B (opposite side b) is bigger than 90 degrees (i.e. obtuse) I would write down the law of cosines in the form that uses angle B (because that is the angle we know about) b^2 = a^2 + c^2 - 2 a c cos B next, we (should!) know cos of an angle bigger than 90 (but less than 180) is negative in other words - 2 ac cos B will turn into a positive number (because -2 * neg cos will be positive) in other words, we can say b^2 = a^2 + c^2 + more if we subtract off more from the right side, the right side will no longer be equal to the left side ... it will be too small. we can say b^2 > a^2 + c^2 or (means the same thing) a^2 + c^2 < b^2

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