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what do you mean by 2⋅3⋅4 cosθ You mean \[\cos 2\theta\quad,\cos3\theta,\quad \cos3\theta\]?
Do you have a triangle that corresponds to this question?
This is the law c^2=A^2+b^2−2abcosC
4=16+9-2(4)(3)cosC 21=24cosC 0.875=cosC C= 28.96
A. 24 B. 21 C. -24 D. -21
I just understood the whole 2,3,4 thing and ya it is equal to 21 I just assume you had to solve for the angle
so is it 21 then
Yes it is
I can try!
true or false
Suppose a triangle has sides a, b, and c, and that a2 + b2 > c2. Let be the measure of the angle opposite the side of length c. Which of the following must be true? Check all that apply.
A. cos < 0 B. cos > 0 C. is an acute angle. D. The triangle in question is a right triangle.
I'd like to think it would be D but I'm not certain
its more than 1 answer
i think its a and d
what do you think
A and D that's what I'm thinking
Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true?
how about this one
A. b2 + c2 < a2 B. a2 + c2 > b2 C. a2 + c2 < b2 D. a2 + b2 < c2
Ya I was trying to think it out and I was thinking it was A but I was testing out the other options too to double check
it wasnt a
Suppose a triangle has sides a, b, and c, and the angle opposite the side of length b is obtuse. What must be true? they tell you about angle B (opposite side b) is bigger than 90 degrees (i.e. obtuse) I would write down the law of cosines in the form that uses angle B (because that is the angle we know about) b^2 = a^2 + c^2 - 2 a c cos B next, we (should!) know cos of an angle bigger than 90 (but less than 180) is negative in other words - 2 ac cos B will turn into a positive number (because -2 * neg cos will be positive) in other words, we can say b^2 = a^2 + c^2 + more if we subtract off more from the right side, the right side will no longer be equal to the left side ... it will be too small. we can say b^2 > a^2 + c^2 or (means the same thing) a^2 + c^2 < b^2