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anonymous
 one year ago
PLEASE HELP!!!!!! I can't quite understand how to do this.
anonymous
 one year ago
PLEASE HELP!!!!!! I can't quite understand how to do this.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The probability distribution of the number of accidents in a week at an intersection, based on past data, is given below. Find the expected number of accidents in one week. Round your answer to the nearest hundredth.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0number of accidents (n) 0  1 2 3 Probability of n accidents 0.75 0.15 0.08 0.02

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what kinda distribution do ya use?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's where I am at a loss. I'm not quite sure. I'm getting confused because of the past problems I have been doing

freckles
 one year ago
Best ResponseYou've already chosen the best response.2since it is discrete \[E(\text{ accidents in one week })=\sum_{n=0}^{3} n \cdot p(n)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0probability mass function?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2aka also known as mean value

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh! That makes sense! I was over complicating it again...

freckles
 one year ago
Best ResponseYou've already chosen the best response.2have you found the sum of the products that I mentioned?

freckles
 one year ago
Best ResponseYou've already chosen the best response.2that is have you computed: 0*.75+1*.15+2*.08+3*.02

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, indeed I was working on that. cx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dayum probability magics

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for my final answer I got 0.37

freckles
 one year ago
Best ResponseYou've already chosen the best response.2that is what I have gotten too
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