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focus on "b^2 -4ac " as you need to take its square root.....

Well, I'm not sure how to solve it. Can you teach me? @IrishBoy123

what is b and what is c in your original quadratic?

No, I'm unsure on how to solve this question...

that's my question....you are trying to find the value of x where the quadratic = 0, is that right?

and I guess it's asking to solve also.. So yeah. solving for x

clearly if \(b^2 - 4ac \lt 0\) you might have an issue (ie complex roots) but run with it first....

Well, I'm sorta confused on how to plug it in and solve it... Can you help me on that?

@IrishBoy123 you there?

what do you get?

|dw:1438365369887:dw|

Okay.

yep?

Yeah. Thank you.