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moazzam07

  • one year ago

Amelia rolls two fair number cubes numbered from 1 to 6. She first defines the sample space as shown below: (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6) (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6) (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6) (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6) (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6) Based on the sample space, what is the probability of getting a total of 4? 6 over 36 5 over 36 4 over 36 3 over 36

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  1. moazzam07
    • one year ago
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    @taramgrant0543664

  2. taramgrant0543664
    • one year ago
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    So there are 36 options in total and we need to figure out which options are equal to four so 3+1 2+2 1+3 All equal 4 so there are three options so there is a 3/36 chance of rolling numbers that equal out to 4

  3. moazzam07
    • one year ago
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    I dont get it

  4. moazzam07
    • one year ago
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    OH WAIT I SEE

  5. taramgrant0543664
    • one year ago
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    I'm assuming that when it says a total of 4 then the two numbers add up to 4

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