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- moazzam07

oy is giving ice cream cones to some children at a carnival. She has 8 chocolate ice cream cones, 10 vanilla ice cream cones, and 6 strawberry ice cream cones. If Joy selects an ice cream cone randomly without looking, what is the probability that she will give a chocolate ice cream cone to the first child and then a vanilla ice cream cone to the second child?
8 over 24 plus 10 over 24 is equal to 18 over 24
8 over 24 plus 10 over 23 is equal to 424 over 552
8 over 24 multiplied by 10 over 23 is equal to 80 over 552
8 over 24 multiplied by 10 over 24 is equal to 80 over 576

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- moazzam07

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- moazzam07

- anonymous

i am here

- moazzam07

You are the best

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- anonymous

add all the ice cream cones up

- anonymous

lol thanks

- moazzam07

24

- anonymous

which is 24

- moazzam07

ok

- anonymous

so there will be 8 over 24 for the chocolate ice cream cones

- moazzam07

Correct

- anonymous

and since one cone was taken out, the denominator for the next fraction probability would be 23

- anonymous

and there are 10 vanilla ice cream cones

- anonymous

so 10/23

- anonymous

so 8 over 24 * 10 over 23

- moazzam07

So its not A and D

- moazzam07

CCC

- anonymous

correct, it's C

- anonymous

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