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anonymous
 one year ago
For fun
anonymous
 one year ago
For fun

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which of the following are eigenpairs (λ,x) of the 2×2 zero matrix: \[\left[\begin{matrix}0 & 0 \\ 0 & 0\end{matrix}\right]=\]where \[\chi \neq0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\left[\begin{matrix}0 & 0 \\ 0 & 0\end{matrix}\right]\chi= \lambda \chi\]where \[\chi \neq0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A. \[(1,\left(\begin{matrix}0 \\ 0\end{matrix}\right))\]B.\[(0,\left(\begin{matrix}1 \\ 0\end{matrix}\right))\]C\[(0,\left(\begin{matrix}0 \\ 1\end{matrix}\right))\]D\[(0,\left(\begin{matrix}1 \\ 1\end{matrix}\right))\]E\[(0,\left(\begin{matrix}1 \\ 1\end{matrix}\right))\]F\[(0,\left(\begin{matrix}0 \\ 0\end{matrix}\right)\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2\[\left[\begin{matrix}0 & 0 \\ 0 & 0\end{matrix}\right]\chi= \lambda \chi\]where \[\chi \neq0\] Notice that the left hand side evaluates to zero vector no matter what the vector \(\chi \) is, so it follows that \(\lambda = 0\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know the answers actually so just for fun :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0pick the options which are eigenpairs

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2By definition, eigenvector cannot be zero, so the last option can be eliminated

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you mean first and last, both are 0

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2Ahh right, first and last options are eliminated

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2remaining all options look good to me!
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