anonymous
  • anonymous
If sin θ = 1/4 and tan θ > 0, what is the value of cos θ?
Mathematics
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anonymous
  • anonymous
If sin θ = 1/4 and tan θ > 0, what is the value of cos θ?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
A) negative square root of 15 B) square root of 15 C) square root of 15 over 4 D) negative square root of 15 over 4
Nayef
  • Nayef
I will give you a hint: \[\theta is \in the first quadrant. That means \between 0 and 90 degree.\]
anonymous
  • anonymous
and im lost

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Nayef
  • Nayef
hhhha
Nayef
  • Nayef
Okey you know: \[\cos^2\theta+\sin^2\theta=1\]
anonymous
  • anonymous
sure
Nayef
  • Nayef
\[\cos^2\theta+(\frac{ 1 }{ 4 })^2=1\]
Nayef
  • Nayef
Do you know how to solve the previus eauation!
anonymous
  • anonymous
nope
anonymous
  • anonymous
look i appreciate ur helping me but i just want the answer plz
Nayef
  • Nayef
You have to learn :)
Nayef
  • Nayef
\[\cos \theta=\sqrt{1-\frac{ 1 }{ 16 }}\]
Nayef
  • Nayef
insert it in the calc!
anonymous
  • anonymous
ok
anonymous
  • anonymous
0.96?
Nayef
  • Nayef
\[\frac{ \sqrt{15} }{ 4 }\]
anonymous
  • anonymous
i should learn to read it says the SINE
anonymous
  • anonymous
|dw:1438368638170:dw|
anonymous
  • anonymous
adjacent sides is \(\sqrt{4^2-1^2}=\sqrt{15}\)
anonymous
  • anonymous
oh
anonymous
  • anonymous
so the cosine is \(\frac{\sqrt{15}}{4}\) same answer as the other way, just a different perspective

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