A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

If sin θ = 1/4 and tan θ > 0, what is the value of cos θ?

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    A) negative square root of 15 B) square root of 15 C) square root of 15 over 4 D) negative square root of 15 over 4

  2. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    I will give you a hint: \[\theta is \in the first quadrant. That means \between 0 and 90 degree.\]

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and im lost

  4. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hhhha

  5. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Okey you know: \[\cos^2\theta+\sin^2\theta=1\]

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    sure

  7. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\cos^2\theta+(\frac{ 1 }{ 4 })^2=1\]

  8. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Do you know how to solve the previus eauation!

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    nope

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    look i appreciate ur helping me but i just want the answer plz

  11. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    You have to learn :)

  12. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\cos \theta=\sqrt{1-\frac{ 1 }{ 16 }}\]

  13. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    insert it in the calc!

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

  15. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    0.96?

  16. nayef
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    \[\frac{ \sqrt{15} }{ 4 }\]

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i should learn to read it says the SINE

  18. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1438368638170:dw|

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    adjacent sides is \(\sqrt{4^2-1^2}=\sqrt{15}\)

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh

  21. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so the cosine is \(\frac{\sqrt{15}}{4}\) same answer as the other way, just a different perspective

  22. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.