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anonymous
 one year ago
If sin θ = 1/4 and tan θ > 0, what is the value of cos θ?
anonymous
 one year ago
If sin θ = 1/4 and tan θ > 0, what is the value of cos θ?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A) negative square root of 15 B) square root of 15 C) square root of 15 over 4 D) negative square root of 15 over 4

nayef
 one year ago
Best ResponseYou've already chosen the best response.2I will give you a hint: \[\theta is \in the first quadrant. That means \between 0 and 90 degree.\]

nayef
 one year ago
Best ResponseYou've already chosen the best response.2Okey you know: \[\cos^2\theta+\sin^2\theta=1\]

nayef
 one year ago
Best ResponseYou've already chosen the best response.2\[\cos^2\theta+(\frac{ 1 }{ 4 })^2=1\]

nayef
 one year ago
Best ResponseYou've already chosen the best response.2Do you know how to solve the previus eauation!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0look i appreciate ur helping me but i just want the answer plz

nayef
 one year ago
Best ResponseYou've already chosen the best response.2\[\cos \theta=\sqrt{1\frac{ 1 }{ 16 }}\]

nayef
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ \sqrt{15} }{ 4 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i should learn to read it says the SINE

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438368638170:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0adjacent sides is \(\sqrt{4^21^2}=\sqrt{15}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the cosine is \(\frac{\sqrt{15}}{4}\) same answer as the other way, just a different perspective
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