A juggler is performing her act using several balls. She throws the balls up at an initial height of 4 feet, with a speed of 15 feet per second. If the juggler doesn't catch one of the balls, about how long does it take the ball to hit the floor?
Hint: Use H(t) = −16t2 + vt + s.
7.52 seconds
1.15 seconds
0.47 second
0.22 second

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- lalaland_lauren

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- anonymous

\[H(t)=-16t^2+15t+4\] set
\[-16t^2+15t+4=0\] and solve for \(t\)

- anonymous

on account of when it hits the floor, the height is zero

- anonymous

you can solve by
a) using the quadratic formula or
b) cheating
i prefer cheating
http://www.wolframalpha.com/input/?i=-16t^2%2B15t%2B4%3D0

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## More answers

- anonymous

actually it is NOT D

- anonymous

beware of answers with no explanation
they are often wrong and you have no way of knowing

- lalaland_lauren

Yeah I've learned my lesson from those :P I enjoy option b and wolframalpha as well :)

- anonymous

lol yeah B

- lalaland_lauren

That's what I was just about to say, it took me a while but I noticed it's close to 1.2 and the only answer close to that was 1.15

- lalaland_lauren

Funny how we chose option b and the answer ended up being b xD

- lalaland_lauren

I'm confused by that...

- anonymous

my bad i thought this was physics

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