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itsmichelle29

  • one year ago

help medal and fan thanks help plz The ages of students in a school are normally distributed with a mean of 15 years and a standard deviation of 2 years. Approximately what percent of the students are between 14 and 18 years old? 24.17% 62.47% 30.85% 93.32%

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  1. Michele_Laino
    • one year ago
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    hint: you have to use the table of the "erf" function, with these limits: (15-14)/2 = 0.5 standard deviations below the mean (18-15)/2= 1.5 standard deviations above the mean

  2. Michele_Laino
    • one year ago
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    |dw:1438374302528:dw|

  3. itsmichelle29
    • one year ago
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    How do u do that'

  4. Michele_Laino
    • one year ago
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    have you the tables of the "erf" function?

  5. itsmichelle29
    • one year ago
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    Yes

  6. itsmichelle29
    • one year ago
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    is that the z score chart

  7. Michele_Laino
    • one year ago
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    yes!

  8. itsmichelle29
    • one year ago
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    okay so now what do i do

  9. Michele_Laino
    • one year ago
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    I refer to this tables: |dw:1438374528068:dw|

  10. Michele_Laino
    • one year ago
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    if z= 1.5, then I got: area=43.32% please check on your tables

  11. itsmichelle29
    • one year ago
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    0.93

  12. itsmichelle29
    • one year ago
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    is that answer 62.47%

  13. Michele_Laino
    • one year ago
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    I prefer to explain step by step

  14. Michele_Laino
    • one year ago
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    if z=0.5, I got: area = 19.15%

  15. Michele_Laino
    • one year ago
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    so, we have: |dw:1438374751642:dw|

  16. itsmichelle29
    • one year ago
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    so im right thanks

  17. Michele_Laino
    • one year ago
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    yes! since: 19.15+43.2=62.47 %

  18. Michele_Laino
    • one year ago
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    oops..19.15+43.32=62.47%

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