anonymous
  • anonymous
pleas can anyone helm me prove that arbitrary intersection of open set is not open????
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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jtvatsim
  • jtvatsim
Are you working with topological spaces or metric spaces in this assignment? Basically, what is the definition of open set that you are to use?
anonymous
  • anonymous
metric space sir
jtvatsim
  • jtvatsim
OK. Thanks, that helps us know what to focus on.

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jtvatsim
  • jtvatsim
After consulting my textbook, it seems that all you need is a counterexample to prove this.
Loser66
  • Loser66
Let A, B are open set then \(A\cup B\) is an open set also Suppose \(A\cap B \) is not empty consider compliment of \(A\cap B\) that is the set of element in A or in B and we know that that set is open, hence \(A\cap B\) is closed.
anonymous
  • anonymous
ok sir but what textbook do you thick should be the best to study metic space for a dummie like me ?
jtvatsim
  • jtvatsim
I like that @Loser66. Very elegant.
anonymous
  • anonymous
@Loser66 can you be specific using the real line R here sir , please
Loser66
  • Loser66
hey @jtvatsim now is your turn :)
anonymous
  • anonymous
because i get more confuse trying to understand my text book.
jtvatsim
  • jtvatsim
But sometimes the intersection of two open sets IS open. :) Consider (0,3) and (1,2). The intersection is (1,2) which is still open. It is arbitrary intersections that cause problems.
jtvatsim
  • jtvatsim
Anyways, to answer your question @GIL.ojei I have yet to find a good introduction to metric spaces. I've struggled with almost all textbooks on the subject. But, I did find this example for the real line.
Michele_Laino
  • Michele_Laino
I think that the arbitrary union of open sets is open
jtvatsim
  • jtvatsim
Consider the set of open intervals centered around the point 0. That is, the family (-1/i, 1/i). Then, consider the infinite intersection \[\cap_{i = 1}^\infty (-1/i, 1/i)\] You will see that as this proceeds to infinity the intervals converge to (0,0) or just the single point {0}. Since a single point is not open, we have shown that an arbitrary intersection of open intervals need not be open.
anonymous
  • anonymous
here is a link @Michele_Laino ,@jtvatsim and @Loser66 ,,, please hepl explain page 17 and 18(remark 1 and 2)
anonymous
  • anonymous
http://nou.edu.ng/uploads/NOUN_OCL/pdf/edited_pdf3/MTH%20301.pdf
anonymous
  • anonymous
any help sirs?
Loser66
  • Loser66
Go to this page , read section 2.1. It is wayyyyyyyyyyy clearer than your text book https://books.google.com/books?id=mMBY5jdjGfoC&printsec=frontcover&source=gbs_ge_summary_r&cad=0#v=onepage&q&f=false
Michele_Laino
  • Michele_Laino
according to the observation of @jtvatsim if the result of an arbitrary intersection, for example an infinite intersection, is a one point set, then we can show that in a metric space, which is also a topological space, any one point set is a closed set
anonymous
  • anonymous
@Loser66 can't find a way to read the text book
Loser66
  • Loser66
oh, you are not in America. That's why you can't open that site. Am I right?
anonymous
  • anonymous
yes sir @Loser66
Loser66
  • Loser66
How about this? watch section 14 topology. https://www.youtube.com/watch?v=FHL4udeLf9Q&index=14&list=PLZzHxk_TPOStgPtqRZ6KzmkUQBQ8TSWVX
jtvatsim
  • jtvatsim
This one is different than Loser66's but I've heard good things about this one: http://www.topologywithouttears.net/topbook.pdf
anonymous
  • anonymous
ok hard that before but he did not explain matric space in dept
Michele_Laino
  • Michele_Laino
metric space is a set equipped with a function, called distance
anonymous
  • anonymous
ok thanks @Michele_Laino
anonymous
  • anonymous
thanks @Loser66 and thats @jtvatsim .. you guys have been helpful

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