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anonymous

  • one year ago

Math Question. Please explain!

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  1. anonymous
    • one year ago
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    \[\frac{ 4xy ^{-2} }{ 12x ^{1/3}y ^{-5} }\]

  2. imqwerty
    • one year ago
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    x^a/x^b = x^(a-b)

  3. anonymous
    • one year ago
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    So the next step would look like this?\[\frac{ x ^{\frac{ 2 }{ 3 }} }{ 3 y ^{7}}\]

  4. skullpatrol
    • one year ago
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    Look at the exponent of y again please.

  5. anonymous
    • one year ago
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    Was that suppose to be -7?

  6. mathmath333
    • one year ago
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    i mean y should be in numerator

  7. phi
    • one year ago
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    follow the rule y^(-2 - - 5)

  8. skullpatrol
    • one year ago
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    -2 - (-5) = ?

  9. imqwerty
    • one year ago
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    y^(-2)/y^(-5) = y^(-2-(-5))

  10. anonymous
    • one year ago
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    \[\frac{ x ^\frac{ 2 }{ 3 }y ^{3} }{ 3 }\]

  11. skullpatrol
    • one year ago
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    Correct :-)

  12. mathmath333
    • one year ago
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    its corect

  13. anonymous
    • one year ago
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    Okay thanks!

  14. imqwerty
    • one year ago
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    :)

  15. skullpatrol
    • one year ago
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    Good job @200205650

  16. anonymous
    • one year ago
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    Thanks!

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