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- YanaSidlinskiy

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- YanaSidlinskiy

\[2x^2+20x+18\]

- YanaSidlinskiy

I got:
(x+1)(x+9)

- jim_thompson5910

let's expand out (x+1)(x+9) to see what we get
|dw:1438385037947:dw|

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## More answers

- jim_thompson5910

fill out the table by multiplying the headers
|dw:1438385069259:dw|

- jim_thompson5910

then you add up all the terms
x^2 + x + 9x + 9 = x^2 + 10x + 9
that shows us x^2 + 10x + 9 factors to (x+1)(x+9)

- YanaSidlinskiy

Yeah, but the original equation is what I've posted first and factored out and came out to as (x+1)(x+9)

- YanaSidlinskiy

Wait, so I factored it wrong?

- jim_thompson5910

if you have a 2 outside, then it works because
2(x+1)(x+9) = 2(x^2 + 10x + 9) = 2x^2 + 20x + 18

- YanaSidlinskiy

Ohh! Ok! I think that's what I was missing..For this problem: \[2x^2+6x-36\]
I got: 2(x-3)(x+6)
Is that correct?

- jim_thompson5910

yes it is

- YanaSidlinskiy

Whee! \[s^2-s-56\]
MY ANSWER:
(s-8)(s+7)

- jim_thompson5910

very good

- YanaSidlinskiy

\[m^2+13m+12\]
My answer:
(m+1)(m+12)

- anonymous

That's right!

- jim_thompson5910

agreed, you are correct

- YanaSidlinskiy

\[x^2-x-72\]
My answer:
(x-9)(x+8)

- jim_thompson5910

also correct

- YanaSidlinskiy

Anyways.... I need help with this one: \[x^2-20x-13\]
I'm guessing it could be prime?

- jim_thompson5910

ways to multiply to -13
-1*13
1*(-13)
none of those pairs add to -20
-1+13 = 12
1+(-13) = -12
so yes it is prime

- anonymous

You can use the quadratic formula.

- jim_thompson5910

specifically you can use the discriminant formula
D = b^2 - 4ac
if D is a positive number and a perfect square, then you can factor

- YanaSidlinskiy

I know I can, but I do not want to take it that far alongside, that's not what I'm required to do..

- anonymous

Oh okay I thought you were trying to solve for x for all of them

- YanaSidlinskiy

\[3x^2-27x+54\]
This can be factored out, right?
No, all I need to do is factor not solving any further..

- anonymous

Yes it can

- jim_thompson5910

yes that can be factored. if you're stuck, try factoring out the GCF 3

- YanaSidlinskiy

Ok, lemme see what I can get lol. I thought so about 3 lol.. Don't do the problem for me.. I wanna do it haha.

- YanaSidlinskiy

Ok, so I got: \[3(x^2-9x+18)\]
Does this seem right? If it does, not all of it has been factored out, correct?

- jim_thompson5910

so far so good. can you factor the inside stuff at all?

- YanaSidlinskiy

Yes, I think so.. A 2?

- YanaSidlinskiy

3

- jim_thompson5910

try to find two numbers that multiply to 18 and add to -9

- anonymous

Yes a 3

- YanaSidlinskiy

(x-3)(x-6)?

- jim_thompson5910

correct

- anonymous

You still need a number before the parentheses

- jim_thompson5910

yes don't forget about the 3 out front

- anonymous

Since you factored out a 3.

- YanaSidlinskiy

Wheee! Thanks guys! Haha! Yes, definitely! I appreciate you guys helping out. I seriously can't thank you enough! Again thanks for the help put in!

- jim_thompson5910

you're welcome

- anonymous

Your welcome :)

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