YanaSidlinskiy
  • YanaSidlinskiy
Help? Need some checked and answered as well... NO SPAMMING!
Mathematics
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
YanaSidlinskiy
  • YanaSidlinskiy
\[2x^2+20x+18\]
YanaSidlinskiy
  • YanaSidlinskiy
I got: (x+1)(x+9)
jim_thompson5910
  • jim_thompson5910
let's expand out (x+1)(x+9) to see what we get |dw:1438385037947:dw|

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jim_thompson5910
  • jim_thompson5910
fill out the table by multiplying the headers |dw:1438385069259:dw|
jim_thompson5910
  • jim_thompson5910
then you add up all the terms x^2 + x + 9x + 9 = x^2 + 10x + 9 that shows us x^2 + 10x + 9 factors to (x+1)(x+9)
YanaSidlinskiy
  • YanaSidlinskiy
Yeah, but the original equation is what I've posted first and factored out and came out to as (x+1)(x+9)
YanaSidlinskiy
  • YanaSidlinskiy
Wait, so I factored it wrong?
jim_thompson5910
  • jim_thompson5910
if you have a 2 outside, then it works because 2(x+1)(x+9) = 2(x^2 + 10x + 9) = 2x^2 + 20x + 18
YanaSidlinskiy
  • YanaSidlinskiy
Ohh! Ok! I think that's what I was missing..For this problem: \[2x^2+6x-36\] I got: 2(x-3)(x+6) Is that correct?
jim_thompson5910
  • jim_thompson5910
yes it is
YanaSidlinskiy
  • YanaSidlinskiy
Whee! \[s^2-s-56\] MY ANSWER: (s-8)(s+7)
jim_thompson5910
  • jim_thompson5910
very good
YanaSidlinskiy
  • YanaSidlinskiy
\[m^2+13m+12\] My answer: (m+1)(m+12)
anonymous
  • anonymous
That's right!
jim_thompson5910
  • jim_thompson5910
agreed, you are correct
YanaSidlinskiy
  • YanaSidlinskiy
\[x^2-x-72\] My answer: (x-9)(x+8)
jim_thompson5910
  • jim_thompson5910
also correct
YanaSidlinskiy
  • YanaSidlinskiy
Anyways.... I need help with this one: \[x^2-20x-13\] I'm guessing it could be prime?
jim_thompson5910
  • jim_thompson5910
ways to multiply to -13 -1*13 1*(-13) none of those pairs add to -20 -1+13 = 12 1+(-13) = -12 so yes it is prime
anonymous
  • anonymous
You can use the quadratic formula.
jim_thompson5910
  • jim_thompson5910
specifically you can use the discriminant formula D = b^2 - 4ac if D is a positive number and a perfect square, then you can factor
YanaSidlinskiy
  • YanaSidlinskiy
I know I can, but I do not want to take it that far alongside, that's not what I'm required to do..
anonymous
  • anonymous
Oh okay I thought you were trying to solve for x for all of them
YanaSidlinskiy
  • YanaSidlinskiy
\[3x^2-27x+54\] This can be factored out, right? No, all I need to do is factor not solving any further..
anonymous
  • anonymous
Yes it can
jim_thompson5910
  • jim_thompson5910
yes that can be factored. if you're stuck, try factoring out the GCF 3
YanaSidlinskiy
  • YanaSidlinskiy
Ok, lemme see what I can get lol. I thought so about 3 lol.. Don't do the problem for me.. I wanna do it haha.
YanaSidlinskiy
  • YanaSidlinskiy
Ok, so I got: \[3(x^2-9x+18)\] Does this seem right? If it does, not all of it has been factored out, correct?
jim_thompson5910
  • jim_thompson5910
so far so good. can you factor the inside stuff at all?
YanaSidlinskiy
  • YanaSidlinskiy
Yes, I think so.. A 2?
YanaSidlinskiy
  • YanaSidlinskiy
3
jim_thompson5910
  • jim_thompson5910
try to find two numbers that multiply to 18 and add to -9
anonymous
  • anonymous
Yes a 3
YanaSidlinskiy
  • YanaSidlinskiy
(x-3)(x-6)?
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
You still need a number before the parentheses
jim_thompson5910
  • jim_thompson5910
yes don't forget about the 3 out front
anonymous
  • anonymous
Since you factored out a 3.
YanaSidlinskiy
  • YanaSidlinskiy
Wheee! Thanks guys! Haha! Yes, definitely! I appreciate you guys helping out. I seriously can't thank you enough! Again thanks for the help put in!
jim_thompson5910
  • jim_thompson5910
you're welcome
anonymous
  • anonymous
Your welcome :)

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