anonymous
  • anonymous
WILL AWARD MEDAL AND WILL FAN HELP PLS What are the zeroes of f(x) = x2 − x − 2? x = −2, 1 x = 2, −1 x = −2, −1 x = 2, 1
Mathematics
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anonymous
  • anonymous
WILL AWARD MEDAL AND WILL FAN HELP PLS What are the zeroes of f(x) = x2 − x − 2? x = −2, 1 x = 2, −1 x = −2, −1 x = 2, 1
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
B
anonymous
  • anonymous
How did you get that?
anonymous
  • anonymous
Okay so I do these kinds of problems differently so tell me when you get lost okay?

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anonymous
  • anonymous
Okay
anonymous
  • anonymous
|dw:1438386272376:dw| These do not mean fractions okay? They just mean to multiply. If you see the 1/2 that means 1*2 = 2 (the same 2 from the equation)
anonymous
  • anonymous
Did you get that?
anonymous
  • anonymous
Kind of
anonymous
  • anonymous
Okay probably I should use the quadratic formula then
jdoe0001
  • jdoe0001
hint: \(\large \begin{array}{ccllll} f(x)=x^2&-x&-2\\ &\uparrow &\uparrow \\ &-2+1&-2\cdot 1 \end{array}\)
Nnesha
  • Nnesha
okay so for that method factor out first and last term then cross multiply you should get the middle term
anonymous
  • anonymous
Ya that's what I use @jdoe0001 but it's soo hard to explain that.
anonymous
  • anonymous
I think I understand now
Nnesha
  • Nnesha
|dw:1438386492743:dw| it should 1 times -2 and don't forget the x
jdoe0001
  • jdoe0001
@sofialauren I was going to ask for the autograph, but I notice is not sofia loren, so that's ok, but I'd settle for 2 binomials
anonymous
  • anonymous
the quadratic formula: \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]
anonymous
  • anonymous
\[ax^2 + bx +c\]
anonymous
  • anonymous
Ugh... Another person to mix up our names
anonymous
  • anonymous
And thanks guys
anonymous
  • anonymous
I get it now
anonymous
  • anonymous
Did you understand how to do it?
Nnesha
  • Nnesha
now cross multiply |dw:1438386562007:dw|
anonymous
  • anonymous
You almost got it! There's no x after 2.
anonymous
  • anonymous
Yes
Nnesha
  • Nnesha
who?
anonymous
  • anonymous
Oh I see you were solving the blue circle in the picture above right?
anonymous
  • anonymous
1x-2x=-x
anonymous
  • anonymous
Lol @Nnesha I thought sofia drew that pic. Turns out it was you.
anonymous
  • anonymous
You still there sofia?
anonymous
  • anonymous
Yes
anonymous
  • anonymous
Can you help me out with another question?
Nnesha
  • Nnesha
ohh okay i just explained the method you were doing nice!!
anonymous
  • anonymous
Ya sure! And lol ya :)
anonymous
  • anonymous
Factor x2 − 8x + 9. (x − 9)(x − 1) (x + 9)(x + 1) Prime (x + 9)(x − 1)
anonymous
  • anonymous
Is it prime because it has an addition symbol?
anonymous
  • anonymous
(x+1)(x-9)
anonymous
  • anonymous
This is what I got but I don't see that answer....
anonymous
  • anonymous
And what do you mean by prime?
anonymous
  • anonymous
I don't know the exact definition
anonymous
  • anonymous
Well prime is an exact number. Like 3/2 equals 1.5 that answer would be prime. but i don't know how equations can be prime.
anonymous
  • anonymous
Unless it's (x+3)^2
anonymous
  • anonymous
But it isn't
anonymous
  • anonymous
(x+3)^2 might be prime I guess.....I'm not really sure.
anonymous
  • anonymous
anonymous
  • anonymous
I tried distributing the answer choices to see if it would bring me back to the original equation
anonymous
  • anonymous
Did any of them work?
anonymous
  • anonymous
No
anonymous
  • anonymous
Then I would choose prime especially if you know that the other choices don't work.
anonymous
  • anonymous
@Nnesha do you know what they mean by prime in this problem?
Nnesha
  • Nnesha
well if leading coefficient is one then apply easy method *headphone* method :D find two number when you multiply them you should get product of AC and if you add or subtract them you should get middle term \[\huge\rm Ax^2+Bx+C=0\] where a =leading coefficient b=middle term c= constant term
Nnesha
  • Nnesha
so in that question a=1 b=-8 c= 9 ac = 9 what two number you should multiply to get 9 BUT when you add them or subtract them you should get middle term which is -8
anonymous
  • anonymous
Who are you asking?
Nnesha
  • Nnesha
good question hmm
Nnesha
  • Nnesha
sofia i guess :3
anonymous
  • anonymous
Lol not trying to be obvious! :P Just wondering
Nnesha
  • Nnesha
prime means : when there is only *one* factor in other words a number which only divided by one
anonymous
  • anonymous
Sorry I'm trying to multitask. I have to hurry so I'm trying to get everything done
Nnesha
  • Nnesha
there aren't any number you can multiply to get 9 and add or subtract to get middle term 9 times 1= 9 9-1= 8( but middle term is negative ) so 9 and 1 are not factors
anonymous
  • anonymous
Okay
Nnesha
  • Nnesha
so that's the reason x^2-8x+9 is not factorable
anonymous
  • anonymous
You can factor -9 and 1 though
Nnesha
  • Nnesha
okay multiply -9 times 1= -9 ( but we need POSITIVE 9 ) \[\huge\rm x^2-8x\color{ReD}{+9}\]
anonymous
  • anonymous
Ohhhh!!! Lol sorry I didn't see that. Ya nnesha is right on that :)
anonymous
  • anonymous
Sorry guys I have to go and I just put the answer as prime. Thank you for your help!
anonymous
  • anonymous
No problem! :)

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