WILL AWARD MEDAL AND WILL FAN HELP PLS
What are the zeroes of f(x) = x2 − x − 2?
x = −2, 1
x = 2, −1
x = −2, −1
x = 2, 1

- anonymous

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- schrodinger

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- anonymous

B

- anonymous

How did you get that?

- anonymous

Okay so I do these kinds of problems differently so tell me when you get lost okay?

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## More answers

- anonymous

Okay

- anonymous

|dw:1438386272376:dw| These do not mean fractions okay? They just mean to multiply. If you see the 1/2 that means 1*2 = 2 (the same 2 from the equation)

- anonymous

Did you get that?

- anonymous

Kind of

- anonymous

Okay probably I should use the quadratic formula then

- jdoe0001

hint: \(\large \begin{array}{ccllll}
f(x)=x^2&-x&-2\\
&\uparrow &\uparrow \\
&-2+1&-2\cdot 1
\end{array}\)

- Nnesha

okay
so for that method
factor out first and last term then cross multiply you should get the middle term

- anonymous

Ya that's what I use @jdoe0001 but it's soo hard to explain that.

- anonymous

I think I understand now

- Nnesha

|dw:1438386492743:dw|
it should 1 times -2
and don't forget the x

- jdoe0001

@sofialauren I was going to ask for the autograph, but I notice is not sofia loren, so that's ok, but I'd settle for 2 binomials

- anonymous

the quadratic formula: \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

- anonymous

\[ax^2 + bx +c\]

- anonymous

Ugh... Another person to mix up our names

- anonymous

And thanks guys

- anonymous

I get it now

- anonymous

Did you understand how to do it?

- Nnesha

now cross multiply |dw:1438386562007:dw|

- anonymous

You almost got it! There's no x after 2.

- anonymous

Yes

- Nnesha

who?

- anonymous

Oh I see you were solving the blue circle in the picture above right?

- anonymous

1x-2x=-x

- anonymous

Lol @Nnesha I thought sofia drew that pic. Turns out it was you.

- anonymous

You still there sofia?

- anonymous

Yes

- anonymous

Can you help me out with another question?

- Nnesha

ohh okay i just explained the method you were doing
nice!!

- anonymous

Ya sure! And lol ya :)

- anonymous

Factor x2 − 8x + 9.
(x − 9)(x − 1)
(x + 9)(x + 1)
Prime
(x + 9)(x − 1)

- anonymous

Is it prime because it has an addition symbol?

- anonymous

(x+1)(x-9)

- anonymous

This is what I got but I don't see that answer....

- anonymous

And what do you mean by prime?

- anonymous

I don't know the exact definition

- anonymous

Well prime is an exact number. Like 3/2 equals 1.5 that answer would be prime. but i don't know how equations can be prime.

- anonymous

Unless it's (x+3)^2

- anonymous

But it isn't

- anonymous

(x+3)^2 might be prime I guess.....I'm not really sure.

- anonymous

@Nnesha

- anonymous

I tried distributing the answer choices to see if it would bring me back to the original equation

- anonymous

Did any of them work?

- anonymous

No

- anonymous

Then I would choose prime especially if you know that the other choices don't work.

- anonymous

@Nnesha do you know what they mean by prime in this problem?

- Nnesha

well if leading coefficient is one then apply easy method *headphone* method :D
find two number when you multiply them you should get product of AC and if you add or subtract them you should get middle term \[\huge\rm Ax^2+Bx+C=0\] where
a =leading coefficient
b=middle term
c= constant term

- Nnesha

so in that question a=1 b=-8 c= 9
ac = 9
what two number you should multiply to get 9 BUT when you add them or subtract them you should get middle term which is -8

- anonymous

Who are you asking?

- Nnesha

good question hmm

- Nnesha

sofia i guess :3

- anonymous

Lol not trying to be obvious! :P Just wondering

- Nnesha

prime means : when there is only *one* factor
in other words a number which only divided by one

- anonymous

Sorry I'm trying to multitask. I have to hurry so I'm trying to get everything done

- Nnesha

there aren't any number you can multiply to get 9 and add or subtract to get middle term
9 times 1= 9
9-1= 8( but middle term is negative ) so 9 and 1 are not factors

- anonymous

Okay

- Nnesha

so that's the reason x^2-8x+9 is not factorable

- anonymous

You can factor -9 and 1 though

- Nnesha

okay
multiply -9 times 1= -9 ( but we need POSITIVE 9 ) \[\huge\rm x^2-8x\color{ReD}{+9}\]

- anonymous

Ohhhh!!! Lol sorry I didn't see that. Ya nnesha is right on that :)

- anonymous

Sorry guys I have to go and I just put the answer as prime. Thank you for your help!

- anonymous

No problem! :)

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