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anonymous

  • one year ago

WILL AWARD MEDAL AND WILL FAN HELP PLS What are the zeroes of f(x) = x2 − x − 2? x = −2, 1 x = 2, −1 x = −2, −1 x = 2, 1

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  1. anonymous
    • one year ago
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    B

  2. anonymous
    • one year ago
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    How did you get that?

  3. anonymous
    • one year ago
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    Okay so I do these kinds of problems differently so tell me when you get lost okay?

  4. anonymous
    • one year ago
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    Okay

  5. anonymous
    • one year ago
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    |dw:1438386272376:dw| These do not mean fractions okay? They just mean to multiply. If you see the 1/2 that means 1*2 = 2 (the same 2 from the equation)

  6. anonymous
    • one year ago
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    Did you get that?

  7. anonymous
    • one year ago
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    Kind of

  8. anonymous
    • one year ago
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    Okay probably I should use the quadratic formula then

  9. jdoe0001
    • one year ago
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    hint: \(\large \begin{array}{ccllll} f(x)=x^2&-x&-2\\ &\uparrow &\uparrow \\ &-2+1&-2\cdot 1 \end{array}\)

  10. Nnesha
    • one year ago
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    okay so for that method factor out first and last term then cross multiply you should get the middle term

  11. anonymous
    • one year ago
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    Ya that's what I use @jdoe0001 but it's soo hard to explain that.

  12. anonymous
    • one year ago
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    I think I understand now

  13. Nnesha
    • one year ago
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    |dw:1438386492743:dw| it should 1 times -2 and don't forget the x

  14. jdoe0001
    • one year ago
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    @sofialauren I was going to ask for the autograph, but I notice is not sofia loren, so that's ok, but I'd settle for 2 binomials

  15. anonymous
    • one year ago
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    the quadratic formula: \[\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

  16. anonymous
    • one year ago
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    \[ax^2 + bx +c\]

  17. anonymous
    • one year ago
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    Ugh... Another person to mix up our names

  18. anonymous
    • one year ago
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    And thanks guys

  19. anonymous
    • one year ago
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    I get it now

  20. anonymous
    • one year ago
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    Did you understand how to do it?

  21. Nnesha
    • one year ago
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    now cross multiply |dw:1438386562007:dw|

  22. anonymous
    • one year ago
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    You almost got it! There's no x after 2.

  23. anonymous
    • one year ago
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    Yes

  24. Nnesha
    • one year ago
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    who?

  25. anonymous
    • one year ago
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    Oh I see you were solving the blue circle in the picture above right?

  26. anonymous
    • one year ago
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    1x-2x=-x

  27. anonymous
    • one year ago
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    Lol @Nnesha I thought sofia drew that pic. Turns out it was you.

  28. anonymous
    • one year ago
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    You still there sofia?

  29. anonymous
    • one year ago
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    Yes

  30. anonymous
    • one year ago
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    Can you help me out with another question?

  31. Nnesha
    • one year ago
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    ohh okay i just explained the method you were doing nice!!

  32. anonymous
    • one year ago
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    Ya sure! And lol ya :)

  33. anonymous
    • one year ago
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    Factor x2 − 8x + 9. (x − 9)(x − 1) (x + 9)(x + 1) Prime (x + 9)(x − 1)

  34. anonymous
    • one year ago
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    Is it prime because it has an addition symbol?

  35. anonymous
    • one year ago
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    (x+1)(x-9)

  36. anonymous
    • one year ago
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    This is what I got but I don't see that answer....

  37. anonymous
    • one year ago
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    And what do you mean by prime?

  38. anonymous
    • one year ago
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    I don't know the exact definition

  39. anonymous
    • one year ago
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    Well prime is an exact number. Like 3/2 equals 1.5 that answer would be prime. but i don't know how equations can be prime.

  40. anonymous
    • one year ago
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    Unless it's (x+3)^2

  41. anonymous
    • one year ago
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    But it isn't

  42. anonymous
    • one year ago
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    (x+3)^2 might be prime I guess.....I'm not really sure.

  43. anonymous
    • one year ago
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    @Nnesha

  44. anonymous
    • one year ago
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    I tried distributing the answer choices to see if it would bring me back to the original equation

  45. anonymous
    • one year ago
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    Did any of them work?

  46. anonymous
    • one year ago
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    No

  47. anonymous
    • one year ago
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    Then I would choose prime especially if you know that the other choices don't work.

  48. anonymous
    • one year ago
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    @Nnesha do you know what they mean by prime in this problem?

  49. Nnesha
    • one year ago
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    well if leading coefficient is one then apply easy method *headphone* method :D find two number when you multiply them you should get product of AC and if you add or subtract them you should get middle term \[\huge\rm Ax^2+Bx+C=0\] where a =leading coefficient b=middle term c= constant term

  50. Nnesha
    • one year ago
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    so in that question a=1 b=-8 c= 9 ac = 9 what two number you should multiply to get 9 BUT when you add them or subtract them you should get middle term which is -8

  51. anonymous
    • one year ago
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    Who are you asking?

  52. Nnesha
    • one year ago
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    good question hmm

  53. Nnesha
    • one year ago
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    sofia i guess :3

  54. anonymous
    • one year ago
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    Lol not trying to be obvious! :P Just wondering

  55. Nnesha
    • one year ago
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    prime means : when there is only *one* factor in other words a number which only divided by one

  56. anonymous
    • one year ago
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    Sorry I'm trying to multitask. I have to hurry so I'm trying to get everything done

  57. Nnesha
    • one year ago
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    there aren't any number you can multiply to get 9 and add or subtract to get middle term 9 times 1= 9 9-1= 8( but middle term is negative ) so 9 and 1 are not factors

  58. anonymous
    • one year ago
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    Okay

  59. Nnesha
    • one year ago
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    so that's the reason x^2-8x+9 is not factorable

  60. anonymous
    • one year ago
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    You can factor -9 and 1 though

  61. Nnesha
    • one year ago
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    okay multiply -9 times 1= -9 ( but we need POSITIVE 9 ) \[\huge\rm x^2-8x\color{ReD}{+9}\]

  62. anonymous
    • one year ago
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    Ohhhh!!! Lol sorry I didn't see that. Ya nnesha is right on that :)

  63. anonymous
    • one year ago
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    Sorry guys I have to go and I just put the answer as prime. Thank you for your help!

  64. anonymous
    • one year ago
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    No problem! :)

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