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anonymous
 one year ago
Solve the following system of equations using any method
3x+14y=−78
12x+12y=84
anonymous
 one year ago
Solve the following system of equations using any method 3x+14y=−78 12x+12y=84

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do you think the solution is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have no clue, can you help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Have you done simultaneous equations before?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Have you solved simple equations like 4x = 8?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You'll be fine then.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0well... if you haven't covered "system of equations", how are you expected to solve it then?

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0or using what "method" are you expected to solve it, that is, what chapter is this covering?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What you need to do is simple, you just rearrange one of the equations so you have y or x on one side of the equation. Can you do that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then I can take you through the next step after that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Lets solve for y first 3x+14y=−78 12x+12y=84 Times the top equation by 4 3x+14y=−78 4(3x+14y)=−78 *4 12x  56y= 312 Now you have a new equation and you can use the cancellation method to solve. Solve for y. Can you finish? 12x  56y = 312 12x + 12y = 84

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0if you haven't covered the material, I'd think this exercise doesn't apply to you then and your teacher should know better than to assign material he/she hasn't covered so... you may want to do that first

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.0can we do it for you? sure, do we know how to? yes does that help you? nope

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@lindsey_quick are you still with me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We have this now. 12x  56y = 312 12x + 12y = 84 To solve for y we can use the cancellation method. 12x and 12x will cancel out because 12x + 12x = 0x = 0 so now we have the following equations 56y = 312 12y = 84 Can you finish solving for y ???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.056y = 312 12y = 84 What does 56y + 12y = ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Correct!! Now what does 312 + 84 = ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Correct!!! So 56y = 312 12y = 84 56y + 12y = 44 and 312 + 84 = 396 so we have now 44y = 396 Now we need to get y by its self. since 44y is multiplication, we divide each side by  44 \( \huge \frac{44y}{44} = \frac{396}{44} \) \( \huge y = \frac{396}{44} \) What do you get when you divide 396 by 44?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Close, you forgot your  symbol but yes 9. Ok we found our y value to the solution now to find the x value just put the y value into one of the original equation and solve for x. I am going to use 3x+14y=−78 3x+14(9)=−78 Can you solve for x or do you still need a little help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think i got it from here , thanks

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03x+14(9)=−78 3x 126 =  78 3x 126 + 126 =  78 + 126 3x = 78 + 126 3x = 48 \( \huge \frac{3x}{3} = \frac{48}{3} \) \( \huge x = \frac{48}{3} \) \( \huge x = 16 \) So the solution is ( 16, 9) Good job! Practice makes perfect. Keep working at them and you will be a pro at them!!!
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