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anonymous

  • one year ago

I need help guys with the elimination method for 4y+2x=18 3x+6y=26

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  1. jdoe0001
    • one year ago
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    \(\bf \begin{array}{llll} 4y+2x=18\\ 3x+6y=26 \end{array}\implies \begin{array}{llll} 2x+4y=18\\ 3x+6y=26 \end{array}\impliedby \textit{arranging the variables} \\ \quad \\ \begin{array}{llll} 2x+4y=18&{\color{brown}{ \times 3}}\\ 3x+6y=26&{\color{brown}{ \times -2}} \end{array}\) if you multiply those expressions, by THAT MUCH, what do they become?

  2. jdoe0001
    • one year ago
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    that is, you mutiply the top by 3 and the bottom one by -2

  3. anonymous
    • one year ago
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    what if I add both equations down like.. 2x+4y=18 +3x+6y=26 equals 5x+10y=44? is this a right step?

  4. anonymous
    • one year ago
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    Is this an option?

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