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anonymous
 one year ago
If g(x) = sqrt(x3) and k(x) = x^2 + 5 then determine: (g*k)(7)
anonymous
 one year ago
If g(x) = sqrt(x3) and k(x) = x^2 + 5 then determine: (g*k)(7)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just multiply the two functions and evaluate at x=7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do you multiply them?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(x3) * (x^4 + 25). Is this what you are suppose to get when you multiply them?\[x ^{5}3x ^{4}+25x75\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you forgot the square root over the x3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1(g*k)(7) is the same as g(7) * k(7)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I squared the both equations so I can get rid of the square root.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1find g(7) and k(7). Then multiply those results

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1squaring x^2 + 5 does not give x^4 + 25 also, squaring can only be done when you square both sides of an equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Would the answer be 216 then?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh I keep forgetting some steps. But I got the answer doing what you said.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^2 + 5 = 7^2 + 5 = 49 + 5 = 54 sqrt(x  3) = sqrt(7  3) = sqrt(4) = 2 54 * 2 = 108 I forgot to sqrt the 4 earlier.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1108 is correct
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