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anonymous

  • one year ago

If g(x) = sqrt(x-3) and k(x) = x^2 + 5 then determine: (g*k)(7)

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  1. anonymous
    • one year ago
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    just multiply the two functions and evaluate at x=7

  2. anonymous
    • one year ago
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    How do you multiply them?

  3. anonymous
    • one year ago
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    (x-3) * (x^4 + 25). Is this what you are suppose to get when you multiply them?\[x ^{5}-3x ^{4}+25x-75\]

  4. jim_thompson5910
    • one year ago
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    you forgot the square root over the x-3

  5. jim_thompson5910
    • one year ago
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    (g*k)(7) is the same as g(7) * k(7)

  6. anonymous
    • one year ago
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    I squared the both equations so I can get rid of the square root.

  7. jim_thompson5910
    • one year ago
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    find g(7) and k(7). Then multiply those results

  8. jim_thompson5910
    • one year ago
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    squaring x^2 + 5 does not give x^4 + 25 also, squaring can only be done when you square both sides of an equation

  9. anonymous
    • one year ago
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    Would the answer be 216 then?

  10. anonymous
    • one year ago
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    Oh I keep forgetting some steps. But I got the answer doing what you said.

  11. jim_thompson5910
    • one year ago
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    it's not 216

  12. anonymous
    • one year ago
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    x^2 + 5 = 7^2 + 5 = 49 + 5 = 54 sqrt(x - 3) = sqrt(7 - 3) = sqrt(4) = 2 54 * 2 = 108 I forgot to sqrt the 4 earlier.

  13. jim_thompson5910
    • one year ago
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    108 is correct

  14. anonymous
    • one year ago
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    Thanks!

  15. jim_thompson5910
    • one year ago
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    no problem

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