anonymous
  • anonymous
If g(x) = sqrt(x-3) and k(x) = x^2 + 5 then determine: (g*k)(7)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
just multiply the two functions and evaluate at x=7
anonymous
  • anonymous
How do you multiply them?
anonymous
  • anonymous
(x-3) * (x^4 + 25). Is this what you are suppose to get when you multiply them?\[x ^{5}-3x ^{4}+25x-75\]

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jim_thompson5910
  • jim_thompson5910
you forgot the square root over the x-3
jim_thompson5910
  • jim_thompson5910
(g*k)(7) is the same as g(7) * k(7)
anonymous
  • anonymous
I squared the both equations so I can get rid of the square root.
jim_thompson5910
  • jim_thompson5910
find g(7) and k(7). Then multiply those results
jim_thompson5910
  • jim_thompson5910
squaring x^2 + 5 does not give x^4 + 25 also, squaring can only be done when you square both sides of an equation
anonymous
  • anonymous
Would the answer be 216 then?
anonymous
  • anonymous
Oh I keep forgetting some steps. But I got the answer doing what you said.
jim_thompson5910
  • jim_thompson5910
it's not 216
anonymous
  • anonymous
x^2 + 5 = 7^2 + 5 = 49 + 5 = 54 sqrt(x - 3) = sqrt(7 - 3) = sqrt(4) = 2 54 * 2 = 108 I forgot to sqrt the 4 earlier.
jim_thompson5910
  • jim_thompson5910
108 is correct
anonymous
  • anonymous
Thanks!
jim_thompson5910
  • jim_thompson5910
no problem

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