Hey guys I need help with Elimination method of
4y+2x=18
3x+6y=26

- anonymous

Hey guys I need help with Elimination method of
4y+2x=18
3x+6y=26

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- anonymous

what do you have to find?

- anonymous

I have to solve using the elimination method.

- anonymous

What you need to do to start with is arrange one of the equations into the form y=... or x=... and then substitute it into the other equation. which one would you like to start with?

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- anonymous

So far I know I multiply
3 to the top equation
And -2 to the bottom equation

- anonymous

cool, do you know why you do this multiplication?

- anonymous

I have
3*2x+4y=18*3
Equals
6x+4y=54

- anonymous

No ..I don't :/

- anonymous

The point is to eliminate one of the x's or y's from the equation, then it makes it easy to solve it right?

- anonymous

Ok I got you .

- anonymous

You multiply the whole equations so that you get the same number of x or the same number of y on each line, then they can cancel each other out.

- anonymous

so if you multiply the top by 3, you get 12y+6x=54
and the bottom by -2 you get -6x -12y = -52

- anonymous

which is where you were at.. still following?

- anonymous

Ok I know for the 2nd equation they cancel out
-2*3x+6y=26*-2
Equals
6x+6y=24y
And they cancel out

- anonymous

Wait I'm wrong aren't i..

- anonymous

yeah i'm just trying to follow your math, hold on

- anonymous

this one is tricky because both the x's and y's cancel each other out. are you sure you have it written down right?

- anonymous

Yes question #4

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- anonymous

are you sure its elimination? substitution would be much easier

- anonymous

It says "solve using the elimination method"

- anonymous

Are you able to help me ?

- anonymous

it has me stumped. can you show me whole of the question?

- anonymous

it looks like it says substitution up the top

- anonymous

Question # 4

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- anonymous

ok, so the way i can see this working if you start back with this:
so if you multiply the top by 3, you get 12y+ 6x = 54
and the bottom by -2 you get -6x -12y = -52
you followed up to this point right?

- anonymous

My conclusion is that there is no solution. I'll post my working shortly.

- anonymous

Ok because I am so confused lol

- anonymous

uploaded below. perhaps there is a typo in the question.

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- anonymous

Oh wow . Ok , so is that what I tell my instructor ?

- anonymous

do you know how to draw graphs?

- anonymous

Not really .. I'm sorry I'm just now starting to understand this math thing .

- anonymous

You should tell your instructor that you can't solve this using the elimination method. You've talked to some other people who have done university maths, and they can't solve it using the elimination method or the substitution method. When both of these equations are shown on a graph, there is no point where the two lines intersect - so no real values of x and y where both equations are solved. So the equations are ok on their own, but there is no solution.

- anonymous

Ok great , Thank you soo much !! You're awesome ! Helped me a lot

- anonymous

you can have a look at the graphs on dismiss.com, i've also posted the picture showing the two lines don't intersect

- anonymous

screenshot here.

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- anonymous

any other time you're trying to check your simultaneous equations, you can write them in and check them here too - its great if you're a visual learner

- anonymous

Yes ! I am actually a visual learner do this will definitely help me .

- anonymous

Do you have time for another question ? Last one

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