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anonymous
 one year ago
Hey guys I need help with Elimination method of
4y+2x=18
3x+6y=26
anonymous
 one year ago
Hey guys I need help with Elimination method of 4y+2x=18 3x+6y=26

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what do you have to find?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have to solve using the elimination method.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What you need to do to start with is arrange one of the equations into the form y=... or x=... and then substitute it into the other equation. which one would you like to start with?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So far I know I multiply 3 to the top equation And 2 to the bottom equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cool, do you know why you do this multiplication?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have 3*2x+4y=18*3 Equals 6x+4y=54

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The point is to eliminate one of the x's or y's from the equation, then it makes it easy to solve it right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You multiply the whole equations so that you get the same number of x or the same number of y on each line, then they can cancel each other out.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so if you multiply the top by 3, you get 12y+6x=54 and the bottom by 2 you get 6x 12y = 52

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0which is where you were at.. still following?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok I know for the 2nd equation they cancel out 2*3x+6y=26*2 Equals 6x+6y=24y And they cancel out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait I'm wrong aren't i..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah i'm just trying to follow your math, hold on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this one is tricky because both the x's and y's cancel each other out. are you sure you have it written down right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you sure its elimination? substitution would be much easier

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It says "solve using the elimination method"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you able to help me ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it has me stumped. can you show me whole of the question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it looks like it says substitution up the top

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok, so the way i can see this working if you start back with this: so if you multiply the top by 3, you get 12y+ 6x = 54 and the bottom by 2 you get 6x 12y = 52 you followed up to this point right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My conclusion is that there is no solution. I'll post my working shortly.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok because I am so confused lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0uploaded below. perhaps there is a typo in the question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wow . Ok , so is that what I tell my instructor ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to draw graphs?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not really .. I'm sorry I'm just now starting to understand this math thing .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You should tell your instructor that you can't solve this using the elimination method. You've talked to some other people who have done university maths, and they can't solve it using the elimination method or the substitution method. When both of these equations are shown on a graph, there is no point where the two lines intersect  so no real values of x and y where both equations are solved. So the equations are ok on their own, but there is no solution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok great , Thank you soo much !! You're awesome ! Helped me a lot

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can have a look at the graphs on dismiss.com, i've also posted the picture showing the two lines don't intersect

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0any other time you're trying to check your simultaneous equations, you can write them in and check them here too  its great if you're a visual learner

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes ! I am actually a visual learner do this will definitely help me .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you have time for another question ? Last one
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