anonymous
  • anonymous
Hey guys I need help with Elimination method of 4y+2x=18 3x+6y=26
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
what do you have to find?
anonymous
  • anonymous
I have to solve using the elimination method.
anonymous
  • anonymous
What you need to do to start with is arrange one of the equations into the form y=... or x=... and then substitute it into the other equation. which one would you like to start with?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
So far I know I multiply 3 to the top equation And -2 to the bottom equation
anonymous
  • anonymous
cool, do you know why you do this multiplication?
anonymous
  • anonymous
I have 3*2x+4y=18*3 Equals 6x+4y=54
anonymous
  • anonymous
No ..I don't :/
anonymous
  • anonymous
The point is to eliminate one of the x's or y's from the equation, then it makes it easy to solve it right?
anonymous
  • anonymous
Ok I got you .
anonymous
  • anonymous
You multiply the whole equations so that you get the same number of x or the same number of y on each line, then they can cancel each other out.
anonymous
  • anonymous
so if you multiply the top by 3, you get 12y+6x=54 and the bottom by -2 you get -6x -12y = -52
anonymous
  • anonymous
which is where you were at.. still following?
anonymous
  • anonymous
Ok I know for the 2nd equation they cancel out -2*3x+6y=26*-2 Equals 6x+6y=24y And they cancel out
anonymous
  • anonymous
Wait I'm wrong aren't i..
anonymous
  • anonymous
yeah i'm just trying to follow your math, hold on
anonymous
  • anonymous
this one is tricky because both the x's and y's cancel each other out. are you sure you have it written down right?
anonymous
  • anonymous
Yes question #4
1 Attachment
anonymous
  • anonymous
are you sure its elimination? substitution would be much easier
anonymous
  • anonymous
It says "solve using the elimination method"
anonymous
  • anonymous
Are you able to help me ?
anonymous
  • anonymous
it has me stumped. can you show me whole of the question?
anonymous
  • anonymous
it looks like it says substitution up the top
anonymous
  • anonymous
Question # 4
1 Attachment
anonymous
  • anonymous
ok, so the way i can see this working if you start back with this: so if you multiply the top by 3, you get 12y+ 6x = 54 and the bottom by -2 you get -6x -12y = -52 you followed up to this point right?
anonymous
  • anonymous
My conclusion is that there is no solution. I'll post my working shortly.
anonymous
  • anonymous
Ok because I am so confused lol
anonymous
  • anonymous
uploaded below. perhaps there is a typo in the question.
anonymous
  • anonymous
Oh wow . Ok , so is that what I tell my instructor ?
anonymous
  • anonymous
do you know how to draw graphs?
anonymous
  • anonymous
Not really .. I'm sorry I'm just now starting to understand this math thing .
anonymous
  • anonymous
You should tell your instructor that you can't solve this using the elimination method. You've talked to some other people who have done university maths, and they can't solve it using the elimination method or the substitution method. When both of these equations are shown on a graph, there is no point where the two lines intersect - so no real values of x and y where both equations are solved. So the equations are ok on their own, but there is no solution.
anonymous
  • anonymous
Ok great , Thank you soo much !! You're awesome ! Helped me a lot
anonymous
  • anonymous
you can have a look at the graphs on dismiss.com, i've also posted the picture showing the two lines don't intersect
anonymous
  • anonymous
screenshot here.
anonymous
  • anonymous
any other time you're trying to check your simultaneous equations, you can write them in and check them here too - its great if you're a visual learner
anonymous
  • anonymous
Yes ! I am actually a visual learner do this will definitely help me .
anonymous
  • anonymous
Do you have time for another question ? Last one

Looking for something else?

Not the answer you are looking for? Search for more explanations.