anonymous
  • anonymous
Find the length of the missing side of the triangle below. https://static.k12.com/eli/bb/259/4_25245/2_17293_3_25248/8b7911af6ff4046b03fa260fbecdad8100849773/media/e820732dc346f40000f5bacf183f7cb97174b7c1/mediaasset_774323_1.gif 116 117 188 119
Geometry
chestercat
  • chestercat
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anonymous
  • anonymous
What do you think? You can use Sine Law to solve this since this is a SAA triangle
anonymous
  • anonymous
You can solve using \( \huge \frac{\sin 56}{100} = \frac{\sin 76}{x} \)
anonymous
  • anonymous
thank you

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anonymous
  • anonymous
YW. I assume you got it?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
Good Job!!!!
anonymous
  • anonymous
I will finish it out just for fun :-) You can solve using \( \huge \frac{\sin 56}{100} = \frac{\sin 76}{x} \) \( \huge 100 * \frac{\sin 56}{100} = \frac{ \sin 76}{x} * 100\) \( \huge \sin 56 = \frac{100sin 76}{x} \) \( \huge x* \sin 56 = \frac{100\sin 76}{x} * x\) \( \huge x* \sin 56 = 100\sin 76\) \( \huge x\sin 56 = 100\sin 76\) \( \huge \frac{x\sin 56}{\sin 56} = \frac{100\sin 76}{\sin56}\) \( \huge x = \frac{100\sin 76}{\sin56}\) \( \huge x = 117\)

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