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So you are just finding the inverse of the function.|dw:1438389821508:dw| Just change y to x. And change x to y.
So it would look like this. |dw:1438389905113:dw| Now, you need to make the equation like this: \[\huge y=mx+b\]
Are you there?
its inverse is not a function
So then I have to solve for y again once I flip it.
Wouldn't there be negatives for y^2 and x?
|dw:1438390277946:dw| Oh wait never mind I see what you did. So did I do this right?
@sourwing : just showing him the steps to find the inverse; @200205650 and my bad, I didn't check the graph first. Obviously the inverse is not a function because the function, in the first place didn't pass the horizontal test. :D
So when you solve for y it still isn't a function?
First, you need to check the graph of the function. If it passed the horizontal test, then you will flip the x and y, then solve for y to find the inverse.
Wait a sec, I'll post the graph of the function to show the horizontal test. :)
So that is the graph and when you draw a horizontal in the graph, it should only pass at one point. If not, then the inverse is not a function. |dw:1438390756334:dw|
Oh it touches more than 1 point on the line right?
It passes TWO points, which means it is not a one-to-one function and its inverse is not a function. |dw:1438390808998:dw|
Yes, you're right.
Okay. So if it isn't a function how can I make an inverse out of the equation?
You can say that the inverse is not a function. That's it.
Oh okay thanks!
No problem! :) I hope I was clear and you understood what I said. :D
Ya I understood. :) Btw I'm a girl not a guy lol.
"just showing him the steps to find the inverse" (that's why I said that)
Oh sorry, my bad. :D
It's okay :)