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anonymous

  • one year ago

If k(x) = x^2 +5 determine....

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  1. anonymous
    • one year ago
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    \[k ^{-1}(x)\]

  2. anonymous
    • one year ago
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    So you are just finding the inverse of the function.|dw:1438389821508:dw| Just change y to x. And change x to y.

  3. anonymous
    • one year ago
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    So it would look like this. |dw:1438389905113:dw| Now, you need to make the equation like this: \[\huge y=mx+b\]

  4. anonymous
    • one year ago
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    Are you there?

  5. anonymous
    • one year ago
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    Oh sorry!

  6. anonymous
    • one year ago
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    its inverse is not a function

  7. anonymous
    • one year ago
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    So then I have to solve for y again once I flip it.

  8. anonymous
    • one year ago
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    Yes. |dw:1438390190217:dw|

  9. anonymous
    • one year ago
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    Wouldn't there be negatives for y^2 and x?

  10. anonymous
    • one year ago
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    |dw:1438390277946:dw| Oh wait never mind I see what you did. So did I do this right?

  11. anonymous
    • one year ago
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    @sourwing : just showing him the steps to find the inverse; @200205650 and my bad, I didn't check the graph first. Obviously the inverse is not a function because the function, in the first place didn't pass the horizontal test. :D

  12. anonymous
    • one year ago
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    So when you solve for y it still isn't a function?

  13. anonymous
    • one year ago
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    First, you need to check the graph of the function. If it passed the horizontal test, then you will flip the x and y, then solve for y to find the inverse.

  14. anonymous
    • one year ago
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    Wait a sec, I'll post the graph of the function to show the horizontal test. :)

  15. anonymous
    • one year ago
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    Okay

  16. anonymous
    • one year ago
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    |dw:1438390702847:dw|

  17. anonymous
    • one year ago
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    So that is the graph and when you draw a horizontal in the graph, it should only pass at one point. If not, then the inverse is not a function. |dw:1438390756334:dw|

  18. anonymous
    • one year ago
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    Oh it touches more than 1 point on the line right?

  19. anonymous
    • one year ago
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    It passes TWO points, which means it is not a one-to-one function and its inverse is not a function. |dw:1438390808998:dw|

  20. anonymous
    • one year ago
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    Yes, you're right.

  21. anonymous
    • one year ago
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    Okay. So if it isn't a function how can I make an inverse out of the equation?

  22. anonymous
    • one year ago
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    You can say that the inverse is not a function. That's it.

  23. anonymous
    • one year ago
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    Oh okay thanks!

  24. anonymous
    • one year ago
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    No problem! :) I hope I was clear and you understood what I said. :D

  25. anonymous
    • one year ago
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    Ya I understood. :) Btw I'm a girl not a guy lol.

  26. anonymous
    • one year ago
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    "just showing him the steps to find the inverse" (that's why I said that)

  27. anonymous
    • one year ago
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    @mathway

  28. anonymous
    • one year ago
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    Oh sorry, my bad. :D

  29. anonymous
    • one year ago
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    It's okay :)

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