If k(x) = x^2 +5 determine....

- anonymous

If k(x) = x^2 +5 determine....

- chestercat

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- anonymous

\[k ^{-1}(x)\]

- anonymous

So you are just finding the inverse of the function.|dw:1438389821508:dw|
Just change y to x. And change x to y.

- anonymous

So it would look like this. |dw:1438389905113:dw| Now, you need to make the equation like this: \[\huge y=mx+b\]

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- anonymous

Are you there?

- anonymous

Oh sorry!

- anonymous

its inverse is not a function

- anonymous

So then I have to solve for y again once I flip it.

- anonymous

Yes. |dw:1438390190217:dw|

- anonymous

Wouldn't there be negatives for y^2 and x?

- anonymous

|dw:1438390277946:dw| Oh wait never mind I see what you did. So did I do this right?

- anonymous

@sourwing : just showing him the steps to find the inverse; @200205650 and my bad, I didn't check the graph first. Obviously the inverse is not a function because the function, in the first place didn't pass the horizontal test. :D

- anonymous

So when you solve for y it still isn't a function?

- anonymous

First, you need to check the graph of the function. If it passed the horizontal test, then you will flip the x and y, then solve for y to find the inverse.

- anonymous

Wait a sec, I'll post the graph of the function to show the horizontal test. :)

- anonymous

Okay

- anonymous

|dw:1438390702847:dw|

- anonymous

So that is the graph and when you draw a horizontal in the graph, it should only pass at one point. If not, then the inverse is not a function. |dw:1438390756334:dw|

- anonymous

Oh it touches more than 1 point on the line right?

- anonymous

It passes TWO points, which means it is not a one-to-one function and its inverse is not a function. |dw:1438390808998:dw|

- anonymous

Yes, you're right.

- anonymous

Okay. So if it isn't a function how can I make an inverse out of the equation?

- anonymous

You can say that the inverse is not a function. That's it.

- anonymous

Oh okay thanks!

- anonymous

No problem! :) I hope I was clear and you understood what I said. :D

- anonymous

Ya I understood. :) Btw I'm a girl not a guy lol.

- anonymous

"just showing him the steps to find the inverse" (that's why I said that)

- anonymous

- anonymous

Oh sorry, my bad. :D

- anonymous

It's okay :)

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