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anonymous
 one year ago
If k(x) = x^2 +5 determine....
anonymous
 one year ago
If k(x) = x^2 +5 determine....

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So you are just finding the inverse of the function.dw:1438389821508:dw Just change y to x. And change x to y.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it would look like this. dw:1438389905113:dw Now, you need to make the equation like this: \[\huge y=mx+b\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its inverse is not a function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So then I have to solve for y again once I flip it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes. dw:1438390190217:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wouldn't there be negatives for y^2 and x?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438390277946:dw Oh wait never mind I see what you did. So did I do this right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@sourwing : just showing him the steps to find the inverse; @200205650 and my bad, I didn't check the graph first. Obviously the inverse is not a function because the function, in the first place didn't pass the horizontal test. :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So when you solve for y it still isn't a function?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First, you need to check the graph of the function. If it passed the horizontal test, then you will flip the x and y, then solve for y to find the inverse.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait a sec, I'll post the graph of the function to show the horizontal test. :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438390702847:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So that is the graph and when you draw a horizontal in the graph, it should only pass at one point. If not, then the inverse is not a function. dw:1438390756334:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh it touches more than 1 point on the line right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It passes TWO points, which means it is not a onetoone function and its inverse is not a function. dw:1438390808998:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. So if it isn't a function how can I make an inverse out of the equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can say that the inverse is not a function. That's it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No problem! :) I hope I was clear and you understood what I said. :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ya I understood. :) Btw I'm a girl not a guy lol.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0"just showing him the steps to find the inverse" (that's why I said that)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh sorry, my bad. :D
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