Republican31
  • Republican31
Solve 3 – 2(b – 5) = 7. Or is the equation an Identity? Or if it has any solution at all? I want help to solve it more than the straight answer.
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
so you just want to solve for b right?
Republican31
  • Republican31
Yes. If it is solvable.
anonymous
  • anonymous
okay so you can start of by distributing the -2 into (b - 5) do you know how to do that?

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rhr12
  • rhr12
b=12
Republican31
  • Republican31
Yes. 3-2b+10=7, right?
anonymous
  • anonymous
yes okay so now you can combine the 3 and the 10 into a 13
anonymous
  • anonymous
also b does not =12 @rhr12
anonymous
  • anonymous
okay so now you should have -2b + 13 = 7
Republican31
  • Republican31
Okay so 13-2b=7. Then subtract 13 from both sides?
rhr12
  • rhr12
(3-2)*{b(12)-5}=7 1*7=7 7=7
rhr12
  • rhr12
i used a different formula but i also like your formula @watchpencilpaper
Republican31
  • Republican31
-2b = -6. So then divide -6 by -2, making b=3, correct?
Republican31
  • Republican31
@rhr12 that would make it an identity, correct? If it is correct, @watchpencilpaper?
Republican31
  • Republican31
If the equation is correct, I mean.
anonymous
  • anonymous
you cant subtract the 2 from the 3 before multiplying it by the (12-5) so its wrong
anonymous
  • anonymous
lets just continue solving the equation and then we can check our answer so we left of at -2b = -6 right?
Republican31
  • Republican31
Yes. b=3?
anonymous
  • anonymous
yes okay and we can check that by plugging it back into our equation \[3 - 2(b-5) = 7\] \[3 - 2((3)-5) = 7\] \[3 - 2(-2) = 7\] \[3 - (-4) = 7\] \[3 + 4 = 7\] \[7 = 7\]
Republican31
  • Republican31
Alright! Thank you!
anonymous
  • anonymous
yep no problem :D

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