anonymous
  • anonymous
Not looking for direct answers, just a little help. I understand that QU is parallel to RT. But I am being asked what further information will prove that RST is similar to QSU by the SSS similarity theorem.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
|dw:1438393572942:dw|
jim_thompson5910
  • jim_thompson5910
pull the triangles apart to get |dw:1438393633317:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

jim_thompson5910
  • jim_thompson5910
look at the given proportion which sides are being referenced?
anonymous
  • anonymous
Rs and Qs
jim_thompson5910
  • jim_thompson5910
that's half of the proportion |dw:1438394377896:dw|
jim_thompson5910
  • jim_thompson5910
the other part is RT/QU |dw:1438394417461:dw|
jim_thompson5910
  • jim_thompson5910
so which pair of sides is missing?
anonymous
  • anonymous
US and TS, i believe..
jim_thompson5910
  • jim_thompson5910
yes, so if we know this \[\Large \frac{RS}{QS} = \frac{RT}{QU} = \frac{TS}{US}\] then we can use the SSS similarity theorem to prove the triangles similar
jim_thompson5910
  • jim_thompson5910
notice how the numerators correspond to the smaller triangle the denominators correspond to the larger triangle
anonymous
  • anonymous
oooh, I think I understand now
jim_thompson5910
  • jim_thompson5910
I'm glad it's making sense
anonymous
  • anonymous
I got B, I'm thinking it's correct because of the two sets of sides that were not mentioned was in the option, and those are the sides that I happened to say
jim_thompson5910
  • jim_thompson5910
I can't see all of the answer choices
anonymous
  • anonymous
jim_thompson5910
  • jim_thompson5910
correct. It's B

Looking for something else?

Not the answer you are looking for? Search for more explanations.