## anonymous one year ago A football quarterback has 2 more chances to throw a touchdown before his team is forced to punt the ball. He misses the receiver on the first throw 30% of the time. When his first throw is incomplete, he misses the receiver on the second throw 10% of the time. What is the probability of not throwing the ball to a receiver on either throw?

1. anonymous

I'm supposed to use conditional probability but I'm not sure which percent is which part of the equation

2. kropot72

Let A be the event he misses on the first throw. Then P(A) = 0.3. If he misses on the first throw, let B be the event he misses on the second throw. Then P(B|A) = 0.1. $\large P(A\cap B)=P(A)\times P(B|A)=0.3\times0.1$