anonymous
  • anonymous
~Will give medal to the person who helps ~ Given ABC find the values of x and y. In your final answer, include all of your calculations. ~(picture will be below)~
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1438394980022:dw|
anonymous
  • anonymous
this might look a lot better than what I drew ~
1 Attachment
anonymous
  • anonymous
this might look a lot better than what I drew ~

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anonymous
  • anonymous
Is that all the information they give you?
anonymous
  • anonymous
yea ~ I put up the actual picture to make sure you see the clear model ~.
anonymous
  • anonymous
I get confused with this, when the shapes do not have all the info. sine and tan i get all confused
anonymous
  • anonymous
Ok, so we know that both triangles are similar
anonymous
  • anonymous
I would assume that 6/(x-9) = x/6
anonymous
  • anonymous
use sine rule
anonymous
  • anonymous
alright sine , but im always confused on which numbers or variables to use
anonymous
  • anonymous
summon SOHCAHTOA !
anonymous
  • anonymous
Sin = opp/hyp Cos = adj/hyp Tan = opp/adj
anonymous
  • anonymous
opposite and hypotenuse ~~~ alright
anonymous
  • anonymous
sine rule = sin(A)/a = sin(B)/b = sin(C)/c 1st triangle we have sin(90)/9= 2nd triangle we have sin(90)/6=
anonymous
  • anonymous
so we use the angle that is at A ?? it said shape ABC and find X and y
anonymous
  • anonymous
i just started this chapter, so its all new to me still
anonymous
  • anonymous
i started the stuff for ya by putting sin(90)/9
anonymous
  • anonymous
|dw:1438396237922:dw|
anonymous
  • anonymous
|dw:1438396318981:dw|
anonymous
  • anonymous
you use the 90 degrees the whole time right ?? just making sure. I thought you would have to use the other angle
anonymous
  • anonymous
it can change depends on situation
anonymous
  • anonymous
well we have to find x and y , so whats the situation call for ?
anonymous
  • anonymous
alright, I just want to know how to tell which angle to use, I thought i would have to use the other one since it can reach both x and y but I guess im wrong. Im just super confused
anonymous
  • anonymous
wait lemme redraw your question to show it to you better
anonymous
  • anonymous
alright,
anonymous
  • anonymous
|dw:1438396632826:dw|
anonymous
  • anonymous
|dw:1438396694436:dw|
anonymous
  • anonymous
what type of triangle is this ?? 30 60 90 ?
anonymous
  • anonymous
idk but dont assume
anonymous
  • anonymous
alright ~
anonymous
  • anonymous
did you take both shapes from the original model for the question ?
anonymous
  • anonymous
yea i split them out
anonymous
  • anonymous
so you can see all the triangles
anonymous
  • anonymous
ohh alright ~
anonymous
  • anonymous
which one ??
anonymous
  • anonymous
if thats the case this is easy
anonymous
  • anonymous
but its not
anonymous
  • anonymous
which one ?? im confused
anonymous
  • anonymous
idk i just put in the numbers, the largest triangle isnt 45/45/90
anonymous
  • anonymous
oh so the one with the 6 ~
anonymous
  • anonymous
or the lonesome 6 i mean
anonymous
  • anonymous
you can try that
anonymous
  • anonymous
ok ? try what ?? the sine equation ?? on which numbers ?
anonymous
  • anonymous
i vaguely remember 45 45 90 ~
anonymous
  • anonymous
for 45/45/90 the its 6^2+6^2 = ??? (Pythagoras theorem)
anonymous
  • anonymous
24 ?? ~
anonymous
  • anonymous
8.4
anonymous
  • anonymous
wait I got it wrong or did you round it down ?? The ^ did the mean multiply or ?
anonymous
  • anonymous
\[\sqrt{6^2+6^2}=8.48528\]
anonymous
  • anonymous
ohhh ~ should have put that earlier, I thought you meant multiply
anonymous
  • anonymous
so the adjacent side is 8.4 ?
anonymous
  • anonymous
hypotenuse
anonymous
  • anonymous
for a 45/45/90 triangle, length of opposite=length of adjacent
anonymous
  • anonymous
i thought the hypotenuse was 6 already. ~ we are focusing on the smaller shape right??
anonymous
  • anonymous
Then its like this\[6^2 = 2a^2\]
anonymous
  • anonymous
|dw:1438398529080:dw| are we doing this shape ? you confused me soo much.
anonymous
  • anonymous
yea
anonymous
  • anonymous
you should get 4.24
anonymous
  • anonymous
but he hypotenuse is 6 already,
anonymous
  • anonymous
lol guess i look at the wrong stuff earler
anonymous
  • anonymous
ohh hahah ~ i do that to~
anonymous
  • anonymous
you see the placement of that lone 6 triangle, the adjacent + 9 is x
anonymous
  • anonymous
so x = 4.24+9
anonymous
  • anonymous
wait where did the 9 come from ?? the original one had only 6 the one I first posted
anonymous
  • anonymous
now you look at the big one
anonymous
  • anonymous
the original figure
anonymous
  • anonymous
but we never found the adjacent side ?? what was it ? and can you show me the step by step equation till you got the answer so im not as confused you keep appearing with answers
anonymous
  • anonymous
ands its confusing me
anonymous
  • anonymous
\[6^2=2a^2\]\[36=2a^2\]\[18=a^2\]\[\sqrt{18}=a\]\[a=\sqrt{18}=4.2426\]
anonymous
  • anonymous
.... i have never seen 2a^2 ever mentioned in a problem
anonymous
  • anonymous
|dw:1438399124678:dw|you know pythagoras is \[a^2+b^2=c^2\]for a 45/45/90 triangle a=b
anonymous
  • anonymous
yea I have seen that , soo the side oppisite of 6 on the smaller shape is 4.2 ?? i would add that to 9 to get x since x is the line BC~
anonymous
  • anonymous
yea
anonymous
  • anonymous
13.2 ~ ?
anonymous
  • anonymous
yup
anonymous
  • anonymous
now use pythagoras to find y
anonymous
  • anonymous
ok then ~~ can you piece the equation together so i can try to work it out
anonymous
  • anonymous
\[c^2-a^2=b^2\]\[13.24^2-6^2=y^2\]
anonymous
  • anonymous
6 ?? i thought it was a 9 ??
anonymous
  • anonymous
|dw:1438399694247:dw|
anonymous
  • anonymous
|dw:1438399695601:dw|
anonymous
  • anonymous
so the opposite side of 6 is = ?
anonymous
  • anonymous
use the stuff i show you earlier
anonymous
  • anonymous
the theorom ? yeaa i know how to solve that , but iM just saying where did the 6 . the side was never defined and the 9 was suppose to be in here i thought
anonymous
  • anonymous
if you look at the big triangle you see the 6 is at the bottom
anonymous
  • anonymous
and the x is the whole line segment, since you split it up you would have to use the nine i thought.
anonymous
  • anonymous
you mean abc?? without the diagonal cutting it off in the middle ?
anonymous
  • anonymous
yea
anonymous
  • anonymous
oh ! should have said that this whole time i thought you took two shapes cut off by the diagonal since they make two different shapes.

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