~Will give medal to the person who helps ~
Given ABC find the values of x and y. In your final answer, include all of your calculations.
~(picture will be below)~

- anonymous

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- anonymous

|dw:1438394980022:dw|

- anonymous

this might look a lot better than what I drew ~

##### 1 Attachment

- anonymous

this might look a lot better than what I drew ~

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- anonymous

Is that all the information they give you?

- anonymous

yea ~ I put up the actual picture to make sure you see the clear model ~.

- anonymous

I get confused with this, when the shapes do not have all the info. sine and tan i get all confused

- anonymous

Ok, so we know that both triangles are similar

- anonymous

I would assume that 6/(x-9) = x/6

- anonymous

use sine rule

- anonymous

alright sine , but im always confused on which numbers or variables to use

- anonymous

summon SOHCAHTOA !

- anonymous

Sin = opp/hyp
Cos = adj/hyp
Tan = opp/adj

- anonymous

opposite and hypotenuse ~~~ alright

- anonymous

sine rule = sin(A)/a = sin(B)/b = sin(C)/c
1st triangle we have sin(90)/9=
2nd triangle we have sin(90)/6=

- anonymous

so we use the angle that is at A ?? it said shape ABC and find X and y

- anonymous

i just started this chapter, so its all new to me still

- anonymous

i started the stuff for ya by putting sin(90)/9

- anonymous

|dw:1438396237922:dw|

- anonymous

|dw:1438396318981:dw|

- anonymous

you use the 90 degrees the whole time right ?? just making sure. I thought you would have to use the other angle

- anonymous

it can change depends on situation

- anonymous

well we have to find x and y , so whats the situation call for ?

- anonymous

alright, I just want to know how to tell which angle to use, I thought i would have to use the other one since it can reach both x and y but I guess im wrong. Im just super confused

- anonymous

wait lemme redraw your question to show it to you better

- anonymous

alright,

- anonymous

|dw:1438396632826:dw|

- anonymous

|dw:1438396694436:dw|

- anonymous

what type of triangle is this ?? 30 60 90 ?

- anonymous

idk but dont assume

- anonymous

alright ~

- anonymous

did you take both shapes from the original model for the question ?

- anonymous

yea i split them out

- anonymous

so you can see all the triangles

- anonymous

ohh alright ~

- anonymous

which one ??

- anonymous

if thats the case this is easy

- anonymous

but its not

- anonymous

which one ?? im confused

- anonymous

idk i just put in the numbers, the largest triangle isnt 45/45/90

- anonymous

oh so the one with the 6 ~

- anonymous

or the lonesome 6 i mean

- anonymous

you can try that

- anonymous

ok ? try what ?? the sine equation ?? on which numbers ?

- anonymous

i vaguely remember 45 45 90 ~

- anonymous

for 45/45/90 the its 6^2+6^2 = ??? (Pythagoras theorem)

- anonymous

24 ?? ~

- anonymous

8.4

- anonymous

wait I got it wrong or did you round it down ?? The ^ did the mean multiply or ?

- anonymous

\[\sqrt{6^2+6^2}=8.48528\]

- anonymous

ohhh ~ should have put that earlier, I thought you meant multiply

- anonymous

so the adjacent side is 8.4 ?

- anonymous

hypotenuse

- anonymous

for a 45/45/90 triangle, length of opposite=length of adjacent

- anonymous

i thought the hypotenuse was 6 already. ~ we are focusing on the smaller shape right??

- anonymous

Then its like this\[6^2 = 2a^2\]

- anonymous

|dw:1438398529080:dw| are we doing this shape ? you confused me soo much.

- anonymous

yea

- anonymous

you should get 4.24

- anonymous

but he hypotenuse is 6 already,

- anonymous

lol guess i look at the wrong stuff earler

- anonymous

ohh hahah ~ i do that to~

- anonymous

you see the placement of that lone 6 triangle, the adjacent + 9 is x

- anonymous

so x = 4.24+9

- anonymous

wait where did the 9 come from ?? the original one had only 6 the one I first posted

- anonymous

now you look at the big one

- anonymous

the original figure

- anonymous

but we never found the adjacent side ?? what was it ? and can you show me the step by step equation till you got the answer so im not as confused you keep appearing with answers

- anonymous

ands its confusing me

- anonymous

\[6^2=2a^2\]\[36=2a^2\]\[18=a^2\]\[\sqrt{18}=a\]\[a=\sqrt{18}=4.2426\]

- anonymous

.... i have never seen 2a^2 ever mentioned in a problem

- anonymous

|dw:1438399124678:dw|you know pythagoras is \[a^2+b^2=c^2\]for a 45/45/90 triangle a=b

- anonymous

yea I have seen that , soo the side oppisite of 6 on the smaller shape is 4.2 ?? i would add that to 9 to get x since x is the line BC~

- anonymous

yea

- anonymous

13.2 ~ ?

- anonymous

yup

- anonymous

now use pythagoras to find y

- anonymous

ok then ~~ can you piece the equation together so i can try to work it out

- anonymous

\[c^2-a^2=b^2\]\[13.24^2-6^2=y^2\]

- anonymous

6 ?? i thought it was a 9 ??

- anonymous

|dw:1438399694247:dw|

- anonymous

|dw:1438399695601:dw|

- anonymous

so the opposite side of 6 is = ?

- anonymous

use the stuff i show you earlier

- anonymous

the theorom ? yeaa i know how to solve that , but iM just saying where did the 6 . the side was never defined and the 9 was suppose to be in here i thought

- anonymous

if you look at the big triangle you see the 6 is at the bottom

- anonymous

and the x is the whole line segment, since you split it up you would have to use the nine i thought.

- anonymous

you mean abc?? without the diagonal cutting it off in the middle ?

- anonymous

yea

- anonymous

oh ! should have said that this whole time i thought you took two shapes cut off by the diagonal since they make two different shapes.

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