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this might look a lot better than what I drew ~
Is that all the information they give you?
yea ~ I put up the actual picture to make sure you see the clear model ~.
I get confused with this, when the shapes do not have all the info. sine and tan i get all confused
Ok, so we know that both triangles are similar
I would assume that 6/(x-9) = x/6
use sine rule
alright sine , but im always confused on which numbers or variables to use
summon SOHCAHTOA !
Sin = opp/hyp Cos = adj/hyp Tan = opp/adj
opposite and hypotenuse ~~~ alright
sine rule = sin(A)/a = sin(B)/b = sin(C)/c 1st triangle we have sin(90)/9= 2nd triangle we have sin(90)/6=
so we use the angle that is at A ?? it said shape ABC and find X and y
i just started this chapter, so its all new to me still
i started the stuff for ya by putting sin(90)/9
you use the 90 degrees the whole time right ?? just making sure. I thought you would have to use the other angle
it can change depends on situation
well we have to find x and y , so whats the situation call for ?
alright, I just want to know how to tell which angle to use, I thought i would have to use the other one since it can reach both x and y but I guess im wrong. Im just super confused
wait lemme redraw your question to show it to you better
what type of triangle is this ?? 30 60 90 ?
idk but dont assume
did you take both shapes from the original model for the question ?
yea i split them out
so you can see all the triangles
ohh alright ~
which one ??
if thats the case this is easy
but its not
which one ?? im confused
idk i just put in the numbers, the largest triangle isnt 45/45/90
oh so the one with the 6 ~
or the lonesome 6 i mean
you can try that
ok ? try what ?? the sine equation ?? on which numbers ?
i vaguely remember 45 45 90 ~
for 45/45/90 the its 6^2+6^2 = ??? (Pythagoras theorem)
24 ?? ~
wait I got it wrong or did you round it down ?? The ^ did the mean multiply or ?
ohhh ~ should have put that earlier, I thought you meant multiply
so the adjacent side is 8.4 ?
for a 45/45/90 triangle, length of opposite=length of adjacent
i thought the hypotenuse was 6 already. ~ we are focusing on the smaller shape right??
Then its like this\[6^2 = 2a^2\]
|dw:1438398529080:dw| are we doing this shape ? you confused me soo much.
you should get 4.24
but he hypotenuse is 6 already,
lol guess i look at the wrong stuff earler
ohh hahah ~ i do that to~
you see the placement of that lone 6 triangle, the adjacent + 9 is x
so x = 4.24+9
wait where did the 9 come from ?? the original one had only 6 the one I first posted
now you look at the big one
the original figure
but we never found the adjacent side ?? what was it ? and can you show me the step by step equation till you got the answer so im not as confused you keep appearing with answers
ands its confusing me
.... i have never seen 2a^2 ever mentioned in a problem
|dw:1438399124678:dw|you know pythagoras is \[a^2+b^2=c^2\]for a 45/45/90 triangle a=b
yea I have seen that , soo the side oppisite of 6 on the smaller shape is 4.2 ?? i would add that to 9 to get x since x is the line BC~
13.2 ~ ?
now use pythagoras to find y
ok then ~~ can you piece the equation together so i can try to work it out
6 ?? i thought it was a 9 ??
so the opposite side of 6 is = ?
use the stuff i show you earlier
the theorom ? yeaa i know how to solve that , but iM just saying where did the 6 . the side was never defined and the 9 was suppose to be in here i thought
if you look at the big triangle you see the 6 is at the bottom
and the x is the whole line segment, since you split it up you would have to use the nine i thought.
you mean abc?? without the diagonal cutting it off in the middle ?
oh ! should have said that this whole time i thought you took two shapes cut off by the diagonal since they make two different shapes.