## anonymous one year ago ~Will give medal to the person who helps ~ Given ABC find the values of x and y. In your final answer, include all of your calculations. ~(picture will be below)~

1. anonymous

|dw:1438394980022:dw|

2. anonymous

this might look a lot better than what I drew ~

3. anonymous

this might look a lot better than what I drew ~

4. anonymous

Is that all the information they give you?

5. anonymous

yea ~ I put up the actual picture to make sure you see the clear model ~.

6. anonymous

I get confused with this, when the shapes do not have all the info. sine and tan i get all confused

7. anonymous

Ok, so we know that both triangles are similar

8. anonymous

I would assume that 6/(x-9) = x/6

9. anonymous

use sine rule

10. anonymous

alright sine , but im always confused on which numbers or variables to use

11. anonymous

summon SOHCAHTOA !

12. anonymous

13. anonymous

opposite and hypotenuse ~~~ alright

14. anonymous

sine rule = sin(A)/a = sin(B)/b = sin(C)/c 1st triangle we have sin(90)/9= 2nd triangle we have sin(90)/6=

15. anonymous

so we use the angle that is at A ?? it said shape ABC and find X and y

16. anonymous

i just started this chapter, so its all new to me still

17. anonymous

i started the stuff for ya by putting sin(90)/9

18. anonymous

|dw:1438396237922:dw|

19. anonymous

|dw:1438396318981:dw|

20. anonymous

you use the 90 degrees the whole time right ?? just making sure. I thought you would have to use the other angle

21. anonymous

it can change depends on situation

22. anonymous

well we have to find x and y , so whats the situation call for ?

23. anonymous

alright, I just want to know how to tell which angle to use, I thought i would have to use the other one since it can reach both x and y but I guess im wrong. Im just super confused

24. anonymous

wait lemme redraw your question to show it to you better

25. anonymous

alright,

26. anonymous

|dw:1438396632826:dw|

27. anonymous

|dw:1438396694436:dw|

28. anonymous

what type of triangle is this ?? 30 60 90 ?

29. anonymous

idk but dont assume

30. anonymous

alright ~

31. anonymous

did you take both shapes from the original model for the question ?

32. anonymous

yea i split them out

33. anonymous

so you can see all the triangles

34. anonymous

ohh alright ~

35. anonymous

which one ??

36. anonymous

if thats the case this is easy

37. anonymous

but its not

38. anonymous

which one ?? im confused

39. anonymous

idk i just put in the numbers, the largest triangle isnt 45/45/90

40. anonymous

oh so the one with the 6 ~

41. anonymous

or the lonesome 6 i mean

42. anonymous

you can try that

43. anonymous

ok ? try what ?? the sine equation ?? on which numbers ?

44. anonymous

i vaguely remember 45 45 90 ~

45. anonymous

for 45/45/90 the its 6^2+6^2 = ??? (Pythagoras theorem)

46. anonymous

24 ?? ~

47. anonymous

8.4

48. anonymous

wait I got it wrong or did you round it down ?? The ^ did the mean multiply or ?

49. anonymous

$\sqrt{6^2+6^2}=8.48528$

50. anonymous

ohhh ~ should have put that earlier, I thought you meant multiply

51. anonymous

so the adjacent side is 8.4 ?

52. anonymous

hypotenuse

53. anonymous

for a 45/45/90 triangle, length of opposite=length of adjacent

54. anonymous

i thought the hypotenuse was 6 already. ~ we are focusing on the smaller shape right??

55. anonymous

Then its like this$6^2 = 2a^2$

56. anonymous

|dw:1438398529080:dw| are we doing this shape ? you confused me soo much.

57. anonymous

yea

58. anonymous

you should get 4.24

59. anonymous

but he hypotenuse is 6 already,

60. anonymous

lol guess i look at the wrong stuff earler

61. anonymous

ohh hahah ~ i do that to~

62. anonymous

you see the placement of that lone 6 triangle, the adjacent + 9 is x

63. anonymous

so x = 4.24+9

64. anonymous

wait where did the 9 come from ?? the original one had only 6 the one I first posted

65. anonymous

now you look at the big one

66. anonymous

the original figure

67. anonymous

but we never found the adjacent side ?? what was it ? and can you show me the step by step equation till you got the answer so im not as confused you keep appearing with answers

68. anonymous

ands its confusing me

69. anonymous

$6^2=2a^2$$36=2a^2$$18=a^2$$\sqrt{18}=a$$a=\sqrt{18}=4.2426$

70. anonymous

.... i have never seen 2a^2 ever mentioned in a problem

71. anonymous

|dw:1438399124678:dw|you know pythagoras is $a^2+b^2=c^2$for a 45/45/90 triangle a=b

72. anonymous

yea I have seen that , soo the side oppisite of 6 on the smaller shape is 4.2 ?? i would add that to 9 to get x since x is the line BC~

73. anonymous

yea

74. anonymous

13.2 ~ ?

75. anonymous

yup

76. anonymous

now use pythagoras to find y

77. anonymous

ok then ~~ can you piece the equation together so i can try to work it out

78. anonymous

$c^2-a^2=b^2$$13.24^2-6^2=y^2$

79. anonymous

6 ?? i thought it was a 9 ??

80. anonymous

|dw:1438399694247:dw|

81. anonymous

|dw:1438399695601:dw|

82. anonymous

so the opposite side of 6 is = ?

83. anonymous

use the stuff i show you earlier

84. anonymous

the theorom ? yeaa i know how to solve that , but iM just saying where did the 6 . the side was never defined and the 9 was suppose to be in here i thought

85. anonymous

if you look at the big triangle you see the 6 is at the bottom

86. anonymous

and the x is the whole line segment, since you split it up you would have to use the nine i thought.

87. anonymous

you mean abc?? without the diagonal cutting it off in the middle ?

88. anonymous

yea

89. anonymous

oh ! should have said that this whole time i thought you took two shapes cut off by the diagonal since they make two different shapes.