Republican31
  • Republican31
(4n-6p)/p = pm/p for m
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Republican31
  • Republican31
Please note I just corrected a mistake in it.
anonymous
  • anonymous
What do u need to do?
anonymous
  • anonymous
Solve for m?

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Republican31
  • Republican31
Yes solve for M. Sorry for not responding.
anonymous
  • anonymous
\[\frac{ (4n-6p) }{ p }=\frac{ pm }{ p }\]\[p(\frac{ (4n-6p )}{ p })=(\frac{ p m }{ p })p\]\[4n-6p=p m\]\[\frac{(4n-6p) }{ p }=m\] There's your answer. Do you understand that?
anonymous
  • anonymous
From the 3rd step to the 4th step I divided the whole equation by p.
Republican31
  • Republican31
Yes, I think so. Just so you know the original problem was http://curriculum.kcdistancelearning.com/courses/ALG1x-FN-A08/a/exams/exam_E-Free_Response_Exam/img34.gif But I did what I could to simplify it, from when I asked it earlier and only got a partial response.
anonymous
  • anonymous
You put pm/p
anonymous
  • anonymous
But alright did you want me to solve this one for you or did you understand how to get it?
Republican31
  • Republican31
I understand it I think. It makes sense from the other concepts I've learned and been helped with in other questions. Is that still the answer for the original problem, in case I did something wrong originally?
anonymous
  • anonymous
Which problem? The one from the link or the one I just did?
anonymous
  • anonymous
What did you get for the problem you sent with the link? I'll check it for you.
Republican31
  • Republican31
The link. The link is the actual problem, from the beginning. But I tried to simplify it. I had asked this question with the original problem earlier, but people suddenly stopped responding without solving, so I took as far as they got and continued here. Maybe it's not correct.
anonymous
  • anonymous
Oh wait I don't have to actually. You still get the same answer as the problem I showed you. :)
Republican31
  • Republican31
Yay! Thank you SOOOO much!
anonymous
  • anonymous
Your welcome! :)

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