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anonymous

  • one year ago

Where is the first derivative of y = 3xe−x equal to 0?

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  1. anonymous
    • one year ago
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    okay so iv got the derivative (-3e^(-x))(x-1)

  2. jim_thompson5910
    • one year ago
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    So they gave you \[\Large y = 3xe^{-x}\] right?

  3. anonymous
    • one year ago
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    yes

  4. jim_thompson5910
    • one year ago
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    I'm getting \[\Large \frac{dy}{dx} = -3e^{-x}(x-1)\] as well

  5. jim_thompson5910
    • one year ago
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    now set dy/dx equal to 0 and solve for x

  6. anonymous
    • one year ago
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    yea well thats what i cant do

  7. jim_thompson5910
    • one year ago
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    \[\Large \frac{dy}{dx} = -3e^{-x}(x-1)\] \[\Large 0 = -3e^{-x}(x-1)\] \[\Large -3e^{-x} = 0 \text{ or } x-1 = 0\]

  8. jim_thompson5910
    • one year ago
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    I'm using the idea A*B = 0 means either A = 0 or B = 0

  9. geerky42
    • one year ago
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    Does that make sense? @Jdosio

  10. anonymous
    • one year ago
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    okay sorry just fell asleep in my desk yes iv got it thank you verry much:D

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