Where is the first derivative of y = 3xe−x equal to 0?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Where is the first derivative of y = 3xe−x equal to 0?

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

okay so iv got the derivative (-3e^(-x))(x-1)
So they gave you \[\Large y = 3xe^{-x}\] right?
yes

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I'm getting \[\Large \frac{dy}{dx} = -3e^{-x}(x-1)\] as well
now set dy/dx equal to 0 and solve for x
yea well thats what i cant do
\[\Large \frac{dy}{dx} = -3e^{-x}(x-1)\] \[\Large 0 = -3e^{-x}(x-1)\] \[\Large -3e^{-x} = 0 \text{ or } x-1 = 0\]
I'm using the idea A*B = 0 means either A = 0 or B = 0
Does that make sense? @Jdosio
okay sorry just fell asleep in my desk yes iv got it thank you verry much:D

Not the answer you are looking for?

Search for more explanations.

Ask your own question