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anonymous

  • one year ago

ABCD is a parallelogram. Its diagonal, AC, is 18 inches long and forms a 20° angle with the base of the parallelogram. Angle ABC is 130°. What is the length of the parallelogram’s base, AB? 8.0 in 11.7 in 27.6 in 40.3 in

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  1. anonymous
    • one year ago
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    https://gmcprep.owschools.com/media/g_geo_ccss_2014/11/geo_10_a_16_assess_media_7.gif

  2. anonymous
    • one year ago
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    @pooja195

  3. anonymous
    • one year ago
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    @rhr12

  4. anonymous
    • one year ago
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    @wolf1728

  5. rhr12
    • one year ago
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    do you know the area of the parallelogram?

  6. wolf1728
    • one year ago
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    We can say that the half angle located at the upper right would be 30 degrees. We have 2 angles and an included side so we can use the Law of Sines

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  7. rhr12
    • one year ago
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    we can eliminate 40 and 26. the confusion is 8 or 11.7.

  8. wolf1728
    • one year ago
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    I drew a new diagram

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  9. anonymous
    • one year ago
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    11.7?

  10. rhr12
    • one year ago
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    11.7 i guess

  11. anonymous
    • one year ago
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    thats ehat i had first but i wasnt ture so i asked yall

  12. rhr12
    • one year ago
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    is that wrong? I had never did something like that. MAybe @wolf1728 will take you to the end

  13. wolf1728
    • one year ago
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    Angle B is 130 degrees side b is 18 inches Angle C is 30 degrees side C = (sin(C) * b)/sin B side C = .5 * 18 / 0.76604 side C = 11.7487337476

  14. wolf1728
    • one year ago
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    Well I guess it is 11.7 and you've got the proof right there! :-)

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