anonymous
  • anonymous
ABCD is a parallelogram. Its diagonal, AC, is 18 inches long and forms a 20° angle with the base of the parallelogram. Angle ABC is 130°. What is the length of the parallelogram’s base, AB? 8.0 in 11.7 in 27.6 in 40.3 in
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
https://gmcprep.owschools.com/media/g_geo_ccss_2014/11/geo_10_a_16_assess_media_7.gif
anonymous
  • anonymous
@pooja195
anonymous
  • anonymous
@rhr12

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anonymous
  • anonymous
@wolf1728
rhr12
  • rhr12
do you know the area of the parallelogram?
wolf1728
  • wolf1728
We can say that the half angle located at the upper right would be 30 degrees. We have 2 angles and an included side so we can use the Law of Sines
1 Attachment
rhr12
  • rhr12
we can eliminate 40 and 26. the confusion is 8 or 11.7.
wolf1728
  • wolf1728
I drew a new diagram
1 Attachment
anonymous
  • anonymous
11.7?
rhr12
  • rhr12
11.7 i guess
anonymous
  • anonymous
thats ehat i had first but i wasnt ture so i asked yall
rhr12
  • rhr12
is that wrong? I had never did something like that. MAybe @wolf1728 will take you to the end
wolf1728
  • wolf1728
Angle B is 130 degrees side b is 18 inches Angle C is 30 degrees side C = (sin(C) * b)/sin B side C = .5 * 18 / 0.76604 side C = 11.7487337476
wolf1728
  • wolf1728
Well I guess it is 11.7 and you've got the proof right there! :-)

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