ABC is a triangle in which ∠A = 60o, AB = 3 cm and AC = 4 cm. If BD is the perpendicular from B to the side AC, what is the length of BD?

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ABC is a triangle in which ∠A = 60o, AB = 3 cm and AC = 4 cm. If BD is the perpendicular from B to the side AC, what is the length of BD?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Triangle ABD is a 30-60-90 triangle where the hypotenuse AB = 3. Multiply the hypotenuse by \(\frac{ \sqrt 3 }{ 2 }\) to get the side opposite the 60° angle, BD. A 30-60-90 triangle is included in the drawing for your future reference |dw:1438408834225:dw|
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use, sqrt(3)/2=perpendicular/ base and x^2+a^2=3^2 You will get the perpendicular which is the answer...
3^2+4^2=3^2=5-9=4

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