help please!

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- anonymous

help please!

- schrodinger

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- anonymous

- Astrophysics

What's the question?

- anonymous

im gonna post it now, give me a sec :)

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## More answers

- anonymous

Kelly was building a bed for her dollhouse. She used her bed, which is 4 feet × 6 feet, as a guide. She scaled down the dimensions of her bed by a factor 1 over 5. What are the dimensions of the model bed she built?
0.8 foot × 1.2 feet
0.4 foot × 0.6 foot
0.08 foot × 0.12 foot
0.04 foot × 0.06 foot

- anonymous

- Astrophysics

|dw:1438409758922:dw| just multiply the dimensions by 1/5.

- Michele_Laino

hint:
you have to multiply the dimensions of the bed of Kelly by a factor 1/5= 0.2

- anonymous

so i do...
4 x 1.5 and 6 x 1.5?

- Astrophysics

It's 1/5 not 1.5

- Michele_Laino

hint:
4*(0.2)=...
6*(0.2)=...

- anonymous

ok so i divide it
4 / 1/5 .. like that?

- Michele_Laino

hint:
4*(1/5)=...?
6*(1/5)=...?

- Astrophysics

\[4 \times \frac{ 1 }{ 5 } = \frac{ 4 }{ 5 } ft\] do so similarly with the other, but you could also do it the way Michele has showed you \[\frac{ 1 }{ 5 } = 0.2\] so you can do 4*(0.2) and 6*(0.2)

- anonymous

oh ok :)

- anonymous

i got 0.8 and 1.2

- Astrophysics

Yeah

- anonymous

ok yay!

- anonymous

next question :)

- anonymous

The seventh-grade class is building target areas for a PE activity. The bases for the game will be circular in shape. The diameter of each circle is 5 feet. Approximately how many square feet of the turf need to be painted for a base circle? Use 3.14 for π and round your answer to the nearest tenth.
15.7 square feet
19.6 square feet
42.8 square feet
78.6 square feet

- Astrophysics

Ok so draw a diagram and label it first

- anonymous

how

- anonymous

- anonymous

i got 9.4

- anonymous

- anonymous

Im thinking it's
6ft∗π
it's 9.4 6ft*pi/2=9.42=9.4
@Astrophysics

- Astrophysics

Where is the 6ft coming from? Do you really think that is true, check your answer choices, it's not even an option

- anonymous

no i think the answer is 9.4

- Astrophysics

You're just looking for the area of a circle \[A = \pi r^2\] where r is the radius, which is half the diameter.

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