## anonymous one year ago check attachment below thanks!

1. anonymous

2. UsukiDoll

First. we need this equation in y = mx+b form Next, pick a test point.. say (0,0) letting x = 0 and y = 0 and plug it into the inequality . If the inequality holds, then it's true and (0,0) is shaded. If the inequality doesn't hold, then it's false and (0,0) won't be shaded Third, let x = 1,2,3, and solve for y to gain more points to plot Finally, compare the graph to the picture

3. UsukiDoll

ok. let's have x = 0 and y = 0 plug those values into the choices you are given which of these inequalities are true?

4. anonymous

@UsukiDoll I'm sorry i just went full retard. I'm reading everything youre telling me, but nothing is making sense I'm so sorry

5. UsukiDoll

I'll do an example picking a test point of (0,0) and the inequality x-3y>5 we have 0-3(0) > 5 0-0>5 0>5 and that doesn't make sense at all. so throw that inequality out

6. UsukiDoll

there's one more inequality that needs to go. which one is it?

7. anonymous

x - 3y < 5

8. UsukiDoll

no that inequality holds true 0 is less than 5

9. marigirl

yes

10. UsukiDoll

dude . x-3y < 5 is a true inequality when the test point is (0,0) so that stays. It's just that there are two of them out there and we need to know which inequality is the same as the picture

11. UsukiDoll

so we either have x-3y <5 or x-2y <5 we know that the test point (0,0) is true so that test point is shaded.

12. anonymous

wait wouldn't the answer be what i just mentioned? x - 3y < 5

13. UsukiDoll

prove that it's correct.... I'm not even done explaining things and this is out of the blue.

14. anonymous

oh. no i didn't do anything. i just have strong feelings for that choice. somethings just telling me thats it.

15. UsukiDoll

so when you have this on a test, what are you going to do? You can't just guess.

16. anonymous

@UsukiDoll thats true. I'm sorry for interrupting you. can you help me figure it out??

17. UsukiDoll

anyway changing it to y = mx+b form x-3y =5 $-3y=5-x$ $y = \frac{5}{-3}+\frac{-x}{-3}$ $y = \frac{x}{3} +(\frac{-5}{3})$

18. UsukiDoll

and for x-2y < 5 just change signs to = and then we need y =mx+b form again x-2y=5 -2y=5-x $y=\frac{-5}{2}+\frac{x}{2}$

19. UsukiDoll

20. UsukiDoll

so which colored line is above the -2 in the y-axis?

21. UsukiDoll

it was x-3y<5 lucky guess

22. anonymous

are you serious?! wow thanks. i had a feeling lol

23. UsukiDoll

yeah but I've outlined the process for manual solving (except for graphing because there is no way that I was doing that by hand)

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