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anonymous
 one year ago
check attachment below thanks!
anonymous
 one year ago
check attachment below thanks!

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UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1First. we need this equation in y = mx+b form Next, pick a test point.. say (0,0) letting x = 0 and y = 0 and plug it into the inequality . If the inequality holds, then it's true and (0,0) is shaded. If the inequality doesn't hold, then it's false and (0,0) won't be shaded Third, let x = 1,2,3, and solve for y to gain more points to plot Finally, compare the graph to the picture

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1ok. let's have x = 0 and y = 0 plug those values into the choices you are given which of these inequalities are true?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll I'm sorry i just went full retard. I'm reading everything youre telling me, but nothing is making sense I'm so sorry

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1I'll do an example picking a test point of (0,0) and the inequality x3y>5 we have 03(0) > 5 00>5 0>5 and that doesn't make sense at all. so throw that inequality out

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1there's one more inequality that needs to go. which one is it?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1no that inequality holds true 0 is less than 5

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1dude . x3y < 5 is a true inequality when the test point is (0,0) so that stays. It's just that there are two of them out there and we need to know which inequality is the same as the picture

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so we either have x3y <5 or x2y <5 we know that the test point (0,0) is true so that test point is shaded.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait wouldn't the answer be what i just mentioned? x  3y < 5

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1prove that it's correct.... I'm not even done explaining things and this is out of the blue.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh. no i didn't do anything. i just have strong feelings for that choice. somethings just telling me thats it.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so when you have this on a test, what are you going to do? You can't just guess.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll thats true. I'm sorry for interrupting you. can you help me figure it out??

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1anyway changing it to y = mx+b form x3y =5 \[3y=5x\] \[y = \frac{5}{3}+\frac{x}{3} \] \[y = \frac{x}{3} +(\frac{5}{3})\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1and for x2y < 5 just change signs to = and then we need y =mx+b form again x2y=5 2y=5x \[y=\frac{5}{2}+\frac{x}{2}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1so which colored line is above the 2 in the yaxis?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1it was x3y<5 lucky guess

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you serious?! wow thanks. i had a feeling lol

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1yeah but I've outlined the process for manual solving (except for graphing because there is no way that I was doing that by hand)
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