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anonymous
 one year ago
check attachment below thanks!
anonymous
 one year ago
check attachment below thanks!

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Set it up as you would a equation of a line graph

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2yx>0 and y1>0 solve for y.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Solve for y for both of the equations they gave you then we can graph it out yx >0 what do you get if you solve for y?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2No...I mean yx>0 > y>x

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Now do the same for y1>0 what do you get

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Yes, so we have our equations \[y>x ~~~ \text{and}~~~y>1\] so that should be pretty easy to graph, what does y>x mean?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Think of it as such, how would you graph y = x?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Think about it, you should be able to answer this at this stage, make a table of values if you have to.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could i graph y=x like that @Astrophysics ??

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I don't understand what 0,1 mean? Could you use the draw tool

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok so you see the graphs on the answers? would i put my point in 0,1?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2I mean, I'm just asking you what y = x graph looks like, what would you get if you made just a table of values, meaning plug random points in x, and get a output of y. You can draw it here dw:1438424373597:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so wait I'm just picking 1 random x point and 1 random y point?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Should I try explaining?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1easy way....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1just equate both the graphs =0 instead of > or<

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Then search two points (any) which satisfies 1st equation to draw its graph...

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1You will see (0,0) and (2,2) satisfies... so draw a line between these two points

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Now for the second equation its just y=1

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Drawing both the graph gives.... ___ as the answer (You guess)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Well, lets stop right there for a second. I think the problem is everyone is just giving him answers as we did for the previous problem, and they are not learning anything which is very troubling. So before we jump ahead you should be able to graph y = x, the way to do this is, we can make a table of values...you can do this with any function/ graph, what ever. dw:1438424828710:dw since our function is y = x, that means every value we plug in for x will give us the same value for y right? So these are our points for the x,y axis we graph them using (x,y) where x is the horizontal line and y is the vertical line, so if we plug in the points we should get this graph dw:1438424926208:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0they have already covered the fact that the inequality signs can be replaced with = signs. They already got y = x and y = 1. I don't get what the issue is (rant over)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my issue is that the shaded part on the answers confuses me about which answer to pick

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438425016070:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Please read everything I've provided, it will help you tremendously.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0pick a test point and see if it satisfies both . If it does it gets shaded. well pick a test point on y = x y = 1 test points are unnecessary

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Its easy combine both the equation...... y=x is in the first option. ITs not in the second option... Common.... you can do it. Do as @Astrophysics has told......

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0Your explanations are fine @Astrophysics and @arindameducationusc

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Thank you @UsukiDoll

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2We're all here to help you, you should take advantage of this, if you don't understand something, just ask. Getting the right answer isn't that important, but the process is, that's the point of all problems.

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1@Astrophysics Right! Ask any conceptual doubt @dom4958 anytime....

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0another example. for yx > 0 y1>0 let x = 0, and y = 1 only one inequality is satisfied. so let x = 3 and y = 4 plug those values in for yx > 0 and y1>0 to see if both inequalities are true

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0let x = 2 and y = 4 plug those values in for yx > 0 and y1>0 to see if both inequalities are true x=3 and y = 4 were off boundary
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