## anonymous one year ago check attachment below thanks!

1. anonymous

2. anonymous

3. Astrophysics

Set it up as you would a equation of a line graph

4. Astrophysics

y-x>0 and y-1>0 solve for y.

5. anonymous

0?

6. Astrophysics

What do you mean

7. Astrophysics

Solve for y for both of the equations they gave you then we can graph it out y-x >0 what do you get if you solve for y?

8. anonymous

y=1 ?

9. Astrophysics

No...I mean y-x>0 -> y>x

10. Astrophysics

Now do the same for y-1>0 what do you get

11. anonymous

y>1

12. Astrophysics

Yes, so we have our equations $y>x ~~~ \text{and}~~~y>1$ so that should be pretty easy to graph, what does y>x mean?

13. Astrophysics

Think of it as such, how would you graph y = x?

14. Astrophysics

Think about it, you should be able to answer this at this stage, make a table of values if you have to.

15. anonymous

0,1

16. Astrophysics

Huh?

17. anonymous

could i graph y=x like that @Astrophysics ??

18. Astrophysics

I don't understand what 0,1 mean? Could you use the draw tool

19. anonymous

ok so you see the graphs on the answers? would i put my point in 0,1?

20. Astrophysics

I mean, I'm just asking you what y = x graph looks like, what would you get if you made just a table of values, meaning plug random points in x, and get a output of y. You can draw it here |dw:1438424373597:dw|

21. anonymous

so wait I'm just picking 1 random x point and 1 random y point?

22. arindameducationusc

Should I try explaining?

23. arindameducationusc

easy way....

24. arindameducationusc

just equate both the graphs =0 instead of > or<

25. arindameducationusc

Then search two points (any) which satisfies 1st equation to draw its graph...

26. arindameducationusc

You will see (0,0) and (2,2) satisfies... so draw a line between these two points

27. arindameducationusc

Now for the second equation its just y=1

28. arindameducationusc

Drawing both the graph gives.... ___ as the answer (You guess)

29. arindameducationusc

@dom4958

30. Astrophysics

Well, lets stop right there for a second. I think the problem is everyone is just giving him answers as we did for the previous problem, and they are not learning anything which is very troubling. So before we jump ahead you should be able to graph y = x, the way to do this is, we can make a table of values...you can do this with any function/ graph, what ever. |dw:1438424828710:dw| since our function is y = x, that means every value we plug in for x will give us the same value for y right? So these are our points for the x,y axis we graph them using (x,y) where x is the horizontal line and y is the vertical line, so if we plug in the points we should get this graph |dw:1438424926208:dw|

31. UsukiDoll

they have already covered the fact that the inequality signs can be replaced with = signs. They already got y = x and y = 1. I don't get what the issue is (rant over)

32. anonymous

my issue is that the shaded part on the answers confuses me about which answer to pick

33. Astrophysics

|dw:1438425016070:dw|

34. Astrophysics

35. UsukiDoll

pick a test point and see if it satisfies both . If it does it gets shaded. well pick a test point on y = x y = 1 test points are unnecessary

36. arindameducationusc

Its easy combine both the equation...... y=x is in the first option. ITs not in the second option... Common.... you can do it. Do as @Astrophysics has told......

37. UsukiDoll

Your explanations are fine @Astrophysics and @arindameducationusc

38. arindameducationusc

Thank you @UsukiDoll

39. Astrophysics

We're all here to help you, you should take advantage of this, if you don't understand something, just ask. Getting the right answer isn't that important, but the process is, that's the point of all problems.

40. arindameducationusc

@Astrophysics Right! Ask any conceptual doubt @dom4958 anytime....

41. UsukiDoll

another example. for y-x > 0 y-1>0 let x = 0, and y = 1 only one inequality is satisfied. so let x = 3 and y = 4 plug those values in for y-x > 0 and y-1>0 to see if both inequalities are true

42. UsukiDoll

let x = 2 and y = 4 plug those values in for y-x > 0 and y-1>0 to see if both inequalities are true x=3 and y = 4 were off boundary