anonymous
  • anonymous
HELP MEDALS N FAN!! 1.)find the explicit rule for the nth term of the sequence 4, -4, 4, -4, ... an= 4 1^(n-1) an= 4 1^(n+1) an= 4 (-1)^n an= 4 (-1)^(n-1) 2.) find the explicit rule for the nth term of a geometric sequence where the second and fifth terms are 40 and 5000, respectively an= 8 5^(n-2) an= 8 5^(n+3) an= 8 5^(n-1) an= 8 5^(n+1)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
amoodarya
  • amoodarya
4 *( ?) =-4 -4 *(?)= +4
amoodarya
  • amoodarya
\[4,-4,4,-4,...\\a_n=4*(-1)^{n-1}\]

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welshfella
  • welshfella
yep thats a geometric series
anonymous
  • anonymous
#2??
anonymous
  • anonymous
welshfella
  • welshfella
first thin find the value of the common ratio r fifth term = ar^4 and second term = ar ar^4 / ar = r^3 so r^3 = 5000/40 find r
welshfella
  • welshfella
can you do that r^3 = 125 r = ?
anonymous
  • anonymous
its like 10.7
anonymous
  • anonymous
an= 8 5^(n-1) is this one right
welshfella
  • welshfella
no 5*5*5 = 125
welshfella
  • welshfella
r = 5
anonymous
  • anonymous
oh duh
anonymous
  • anonymous
is it 5^(n-1)
welshfella
  • welshfella
now you need to find the first term which is 40/5
welshfella
  • welshfella
first term * 5^(n-1)
anonymous
  • anonymous
so i was right?
welshfella
  • welshfella
yes 8* 5^(n-1)
anonymous
  • anonymous
thank u @welshfella !!!!
welshfella
  • welshfella
yw

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