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anonymous

  • one year ago

HELP MEDALS N FAN!! 1.)find the explicit rule for the nth term of the sequence 4, -4, 4, -4, ... an= 4 1^(n-1) an= 4 1^(n+1) an= 4 (-1)^n an= 4 (-1)^(n-1) 2.) find the explicit rule for the nth term of a geometric sequence where the second and fifth terms are 40 and 5000, respectively an= 8 5^(n-2) an= 8 5^(n+3) an= 8 5^(n-1) an= 8 5^(n+1)

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  1. anonymous
    • one year ago
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    @amoodarya @Astrophysics

  2. amoodarya
    • one year ago
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    4 *( ?) =-4 -4 *(?)= +4

  3. amoodarya
    • one year ago
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    \[4,-4,4,-4,...\\a_n=4*(-1)^{n-1}\]

  4. welshfella
    • one year ago
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    yep thats a geometric series

  5. anonymous
    • one year ago
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    #2??

  6. anonymous
    • one year ago
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    @surjithayer

  7. welshfella
    • one year ago
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    first thin find the value of the common ratio r fifth term = ar^4 and second term = ar ar^4 / ar = r^3 so r^3 = 5000/40 find r

  8. welshfella
    • one year ago
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    can you do that r^3 = 125 r = ?

  9. anonymous
    • one year ago
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    its like 10.7

  10. anonymous
    • one year ago
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    an= 8 5^(n-1) is this one right

  11. welshfella
    • one year ago
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    no 5*5*5 = 125

  12. welshfella
    • one year ago
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    r = 5

  13. anonymous
    • one year ago
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    oh duh

  14. anonymous
    • one year ago
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    is it 5^(n-1)

  15. welshfella
    • one year ago
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    now you need to find the first term which is 40/5

  16. welshfella
    • one year ago
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    first term * 5^(n-1)

  17. anonymous
    • one year ago
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    so i was right?

  18. welshfella
    • one year ago
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    yes 8* 5^(n-1)

  19. anonymous
    • one year ago
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    thank u @welshfella !!!!

  20. welshfella
    • one year ago
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    yw

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