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anonymous
 one year ago
Write the equation of a hyperbola with foci at (1, 1) and (5, 1) and vertices at (0, 1) and (4, 1).
anonymous
 one year ago
Write the equation of a hyperbola with foci at (1, 1) and (5, 1) and vertices at (0, 1) and (4, 1).

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438439956276:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438440031354:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0YOur hyperbola is dw:1438440092246:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hence , the center (h, k) = (2,1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The vertices (h+a, k) and (ha, k) , and your vertice is (0,1) , and (4,1) That is h+a = 0 and ha = 4 That give us a =2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{red}{a=2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we have formula to find it out, it says c^2 = a^2 + b^2, then \(b^2= c^2 a^2\) from above, we have h =2, to find c, we have (h+c, k) and (hc,k) are foci h+c =5 hc =1 that gives us c =3 so b^2 = 3^2 2^2 = 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\color {red}{a^2 =4}\) \(\color{blue}{b^2 =5}\) \(\color{green}{h= 2}\) \(\color{orange}{k =1}\) Plug all in formula \(\dfrac{(x\color{green}{h})^2}{\color{red}{a^2}}\dfrac{(y\color{orange}{k})^2}{\color{blue}{b^2}}=1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0really appreciate it. thank you
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