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zeesbrat3
 one year ago
A particle moves along the xaxis with position function s(t) = xe^x. How many times in the interval [−5, 5] is the velocity equal to 0?
zeesbrat3
 one year ago
A particle moves along the xaxis with position function s(t) = xe^x. How many times in the interval [−5, 5] is the velocity equal to 0?

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1you mean \(s(t) = te^t\) ??

zeesbrat3
 one year ago
Best ResponseYou've already chosen the best response.0I suppose, I just copied the question honestly. @IrishBoy123

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1if you do mean: \(\large s(t)=te^t\) then \(\large v(t) = \dot s(t)=\frac{d}{dt}( te^t)\) use product rule and set it to zero to find when the things is at rest

zeesbrat3
 one year ago
Best ResponseYou've already chosen the best response.0so find the derivative?

zeesbrat3
 one year ago
Best ResponseYou've already chosen the best response.0I tried doing what we did but that didn't work, but doing what he just said makes sense. I got 0 as a solution

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1maybe your function is like this: \[\Large s\left( t \right) = t{e^{  t}}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1sorry, if I compute the first derivative, I got this: \[\Large \frac{{d\left( {t{e^t}} \right)}}{{dt}} = \left( {t + 1} \right){e^t}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so we have to solve this algebraic equation: \[\Large \left( {t + 1} \right){e^t} = 0\]

zeesbrat3
 one year ago
Best ResponseYou've already chosen the best response.0I got 1 as a solution

zeesbrat3
 one year ago
Best ResponseYou've already chosen the best response.0Awesome! Thank you for your help!!
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