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YumYum247
 one year ago
help Please!!!
YumYum247
 one year ago
help Please!!!

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0How do i create the data table to plot the velocity time graph?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0......for both the runner and the car?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the velocity of the car is v=cost=4 m/sec whereas the velocity of the runner is v=a*t=0.5*t

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438445437066:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2"cost" stands for constant

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok but how do i make the data table to plot the points on the graph. and how did you know the graph looks like this????

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2since the function: \[v = at\] is represented by a line which passes at the origin, in the (t, v) plane

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i mean how did you make the graph without T(sec) Velocity m/sec 0 0 1 some number 2 some number

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2is the acceleration along of 20 seconds of time?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2from your text I see that the runner accelerates for 20 seconds

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok tell me how do i make the data table from velocity and average velocity???

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2ok so the graph of this function: \[v\left( t \right) = at = 0.5t\] passes at point t=0, v=0 and passes at point t=20, v=0.5*20=10

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0how do i figure out how far the runner will be in 1,2,3,4,5,6,7,8,9,10,11,12,13,1420 secods

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2whereas the velocity of the car is constant the function v=4, is represented by the subsequent line: dw:1438446099431:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok so that car will cover 4 meters every second...got that.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0what about the runner tho :(

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the space traveled by the runner, is given by the subsequent formula: \[\Large s\left( t \right) = \frac{1}{2}a{t^2}\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i want to make a proper data table for both the car and the runner and plot those point on to the graph so it looks pretty neat.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0what does "s" stand for?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2"s(t)" stands for space as function of time

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0never learned about that in physics.. so can i use that formula to figure out the velocity of the runner at any given time???

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2in order to make a table, you have to consider these times: t=1 t=2 t=3 t=4 t=5 ... t=20 and compute the corresponding spaces, using this formula: \[\Large s\left( t \right) = \frac{1}{2}a{t^2} = \frac{1}{2} \times 0.5{t^2} = \frac{{{t^2}}}{4}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2that is the graph for runner. In order to make a table for car, you have to consider the same times, namely: =1 t=2 t=3 t=4 t=5 ... t=20 and then you have to compute the distance using the subsequent formula: \[\Large s\left( t \right) = 4t\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0so what does s(t) = 4t means tho???

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2s(t)=4t, it is the space traveled by the car at time t

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2no, it is: 4*t where t is the time

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2for example, at t=2, we have: \[s\left( 2 \right) = 4 \times 2 = 8\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0yah but at 1 second, the runner covered 4meters right since 4X1sec = 4m?????

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2the car travelled 4*1= 4 meters, whereas the runner travelled 1/4= 0.25 meters

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok so the example that you gave me a second ago was for whome, the runner or the car.....???? car?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok let me try and i'll get back to you......Thank you and bless you!!! :)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2more explanation: \[\Large \begin{gathered} spac{e_{car}} = 4 \times t \hfill \\ \hfill \\ spac{e_{runner}} = \frac{{{t^2}}}{4} \hfill \\ \end{gathered} \]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok i got it...Thanks make gotta wite the formula down.... Peace :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok i didn't quite get this.....Space runner = t^2/4 because i'm not getting the same number here....dw:1438459291397:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0oh never mind now i see that......i thought you wrote something else.... Cheers!!!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0buddy there is something wrong here, the runner reaches a velocity of 100m/sec in 20 sec.....doesn't sound right to me

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0the answer key suggest 10m/sec at 20 sec.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i need to know how do i make datatable from average velocity in m/sec2

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0you were given the information already

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i want to know how do i make a data table of average velocity.......

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438452273488:dw

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0i keep telling you, your AVERAGE VELOCITY IS your slope

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but how do i know how far will the runner be in let's say 7 sec????

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438452404287:dw

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0that is the point when you actually SOLVE it :)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0Mary Jesus, Joseph, Muhammad

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0the car is no problem, it's going at 4m/sec

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0what does that mean

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i can figure out how far the car will be at any given time but i'm not so sure about the runner tho???

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0what does 4m/s mean? that means that your distance is 4 meters per 1 sec so in your plot for 1 sec you put distance at 4

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0ok let me ask you a question.....how far will the runner be in 7 seconds????

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0that is when you solve it do you know that acceleration is the change in VELOCITY/time ?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0it means the car is convering 4meters every sec. so o nthe velocity time graph it's just be a flat straight line

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438452675130:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0so acceleration = Velocity/time

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438452731926:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0so by 20 sec, the runner have covered 0.025m????what??????????
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