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YumYum247

  • one year ago

help Please!!!

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  1. YumYum247
    • one year ago
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  2. YumYum247
    • one year ago
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    How do i create the data table to plot the velocity time graph?

  3. YumYum247
    • one year ago
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    @Michele_Laino

  4. YumYum247
    • one year ago
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    ......for both the runner and the car?

  5. Michele_Laino
    • one year ago
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    the velocity of the car is v=cost=4 m/sec whereas the velocity of the runner is v=a*t=0.5*t

  6. YumYum247
    • one year ago
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    ok what is "cost"?

  7. Michele_Laino
    • one year ago
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    |dw:1438445437066:dw|

  8. Michele_Laino
    • one year ago
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    "cost" stands for constant

  9. YumYum247
    • one year ago
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    ok but how do i make the data table to plot the points on the graph. and how did you know the graph looks like this????

  10. Michele_Laino
    • one year ago
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    since the function: \[v = at\] is represented by a line which passes at the origin, in the (t, v) plane

  11. YumYum247
    • one year ago
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    i mean how did you make the graph without T(sec) Velocity m/sec 0 0 1 some number 2 some number

  12. Michele_Laino
    • one year ago
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    is the acceleration along of 20 seconds of time?

  13. YumYum247
    • one year ago
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    i don't know!!! :(

  14. Michele_Laino
    • one year ago
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    from your text I see that the runner accelerates for 20 seconds

  15. YumYum247
    • one year ago
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    yah....!!!

  16. YumYum247
    • one year ago
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    ok tell me how do i make the data table from velocity and average velocity???

  17. Michele_Laino
    • one year ago
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    ok so the graph of this function: \[v\left( t \right) = at = 0.5t\] passes at point t=0, v=0 and passes at point t=20, v=0.5*20=10

  18. YumYum247
    • one year ago
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    yes....!!!!

  19. YumYum247
    • one year ago
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    i got that....

  20. YumYum247
    • one year ago
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    how do i figure out how far the runner will be in 1,2,3,4,5,6,7,8,9,10,11,12,13,14-20 secods

  21. Michele_Laino
    • one year ago
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    whereas the velocity of the car is constant the function v=4, is represented by the subsequent line: |dw:1438446099431:dw|

  22. YumYum247
    • one year ago
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    ok so that car will cover 4 meters every second...got that.

  23. Michele_Laino
    • one year ago
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    yes!

  24. YumYum247
    • one year ago
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    what about the runner tho :(

  25. Michele_Laino
    • one year ago
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    the space traveled by the runner, is given by the subsequent formula: \[\Large s\left( t \right) = \frac{1}{2}a{t^2}\]

  26. YumYum247
    • one year ago
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    i want to make a proper data table for both the car and the runner and plot those point on to the graph so it looks pretty neat.

  27. YumYum247
    • one year ago
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    what does "s" stand for?

  28. Michele_Laino
    • one year ago
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    "s(t)" stands for space as function of time

  29. YumYum247
    • one year ago
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    never learned about that in physics.. so can i use that formula to figure out the velocity of the runner at any given time???

  30. Michele_Laino
    • one year ago
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    in order to make a table, you have to consider these times: t=1 t=2 t=3 t=4 t=5 ... t=20 and compute the corresponding spaces, using this formula: \[\Large s\left( t \right) = \frac{1}{2}a{t^2} = \frac{1}{2} \times 0.5{t^2} = \frac{{{t^2}}}{4}\]

  31. Michele_Laino
    • one year ago
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    that is the graph for runner. In order to make a table for car, you have to consider the same times, namely: =1 t=2 t=3 t=4 t=5 ... t=20 and then you have to compute the distance using the subsequent formula: \[\Large s\left( t \right) = 4t\]

  32. YumYum247
    • one year ago
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    so what does s(t) = 4t means tho???

  33. Michele_Laino
    • one year ago
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    s(t)=4t, it is the space traveled by the car at time t

  34. YumYum247
    • one year ago
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    so 4 meters?

  35. Michele_Laino
    • one year ago
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    no, it is: 4*t where t is the time

  36. Michele_Laino
    • one year ago
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    for example, at t=2, we have: \[s\left( 2 \right) = 4 \times 2 = 8\]

  37. YumYum247
    • one year ago
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    yah but at 1 second, the runner covered 4meters right since 4X1sec = 4m?????

  38. Michele_Laino
    • one year ago
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    the car travelled 4*1= 4 meters, whereas the runner travelled 1/4= 0.25 meters

  39. YumYum247
    • one year ago
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    ok so the example that you gave me a second ago was for whome, the runner or the car.....???? car?

  40. YumYum247
    • one year ago
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    ok let me try and i'll get back to you......Thank you and bless you!!! :)

  41. Michele_Laino
    • one year ago
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    more explanation: \[\Large \begin{gathered} spac{e_{car}} = 4 \times t \hfill \\ \hfill \\ spac{e_{runner}} = \frac{{{t^2}}}{4} \hfill \\ \end{gathered} \]

  42. YumYum247
    • one year ago
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    ok i got it...Thanks make gotta wite the formula down.... Peace :)

  43. Michele_Laino
    • one year ago
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    :)

  44. YumYum247
    • one year ago
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    :)

  45. YumYum247
    • one year ago
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    ok i didn't quite get this.....Space runner = t^2/4 because i'm not getting the same number here....|dw:1438459291397:dw|

  46. YumYum247
    • one year ago
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    @Michele_Laino

  47. YumYum247
    • one year ago
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    oh never mind now i see that......i thought you wrote something else.... Cheers!!!!

  48. YumYum247
    • one year ago
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    buddy there is something wrong here, the runner reaches a velocity of 100m/sec in 20 sec.....doesn't sound right to me

  49. YumYum247
    • one year ago
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    the answer key suggest 10m/sec at 20 sec.

  50. YumYum247
    • one year ago
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    @Elsa213 help plz

  51. YumYum247
    • one year ago
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    @sweetburger

  52. YumYum247
    • one year ago
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    i need to know how do i make data-table from average velocity in m/sec2

  53. YumYum247
    • one year ago
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    @nincompoop

  54. YumYum247
    • one year ago
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    @nincompoop

  55. nincompoop
    • one year ago
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    you were given the information already

  56. YumYum247
    • one year ago
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    i want to know how do i make a data table of average velocity.......

  57. nincompoop
    • one year ago
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    |dw:1438452273488:dw|

  58. nincompoop
    • one year ago
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    i keep telling you, your AVERAGE VELOCITY IS your slope

  59. YumYum247
    • one year ago
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    but how do i know how far will the runner be in let's say 7 sec????

  60. nincompoop
    • one year ago
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    |dw:1438452404287:dw|

  61. nincompoop
    • one year ago
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    that is the point when you actually SOLVE it :)

  62. YumYum247
    • one year ago
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    yes yes yes!!! :D

  63. nincompoop
    • one year ago
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    Mary Jesus, Joseph, Muhammad

  64. YumYum247
    • one year ago
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    the car is no problem, it's going at 4m/sec

  65. nincompoop
    • one year ago
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    and?

  66. nincompoop
    • one year ago
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    what does that mean

  67. YumYum247
    • one year ago
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    i can figure out how far the car will be at any given time but i'm not so sure about the runner tho???

  68. nincompoop
    • one year ago
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    what does 4m/s mean? that means that your distance is 4 meters per 1 sec so in your plot for 1 sec you put distance at 4

  69. YumYum247
    • one year ago
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    ok let me ask you a question.....how far will the runner be in 7 seconds????

  70. nincompoop
    • one year ago
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    that is when you solve it do you know that acceleration is the change in VELOCITY/time ?

  71. YumYum247
    • one year ago
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    it means the car is convering 4meters every sec. so o nthe velocity time graph it's just be a flat straight line

  72. YumYum247
    • one year ago
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    |dw:1438452675130:dw|

  73. YumYum247
    • one year ago
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    so acceleration = Velocity/time

  74. YumYum247
    • one year ago
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    |dw:1438452731926:dw|

  75. YumYum247
    • one year ago
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    so by 20 sec, the runner have covered 0.025m????what??????????

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