YumYum247
  • YumYum247
help Please!!!
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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YumYum247
  • YumYum247
YumYum247
  • YumYum247
How do i create the data table to plot the velocity time graph?
YumYum247
  • YumYum247
@Michele_Laino

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YumYum247
  • YumYum247
......for both the runner and the car?
Michele_Laino
  • Michele_Laino
the velocity of the car is v=cost=4 m/sec whereas the velocity of the runner is v=a*t=0.5*t
YumYum247
  • YumYum247
ok what is "cost"?
Michele_Laino
  • Michele_Laino
|dw:1438445437066:dw|
Michele_Laino
  • Michele_Laino
"cost" stands for constant
YumYum247
  • YumYum247
ok but how do i make the data table to plot the points on the graph. and how did you know the graph looks like this????
Michele_Laino
  • Michele_Laino
since the function: \[v = at\] is represented by a line which passes at the origin, in the (t, v) plane
YumYum247
  • YumYum247
i mean how did you make the graph without T(sec) Velocity m/sec 0 0 1 some number 2 some number
Michele_Laino
  • Michele_Laino
is the acceleration along of 20 seconds of time?
YumYum247
  • YumYum247
i don't know!!! :(
Michele_Laino
  • Michele_Laino
from your text I see that the runner accelerates for 20 seconds
YumYum247
  • YumYum247
yah....!!!
YumYum247
  • YumYum247
ok tell me how do i make the data table from velocity and average velocity???
Michele_Laino
  • Michele_Laino
ok so the graph of this function: \[v\left( t \right) = at = 0.5t\] passes at point t=0, v=0 and passes at point t=20, v=0.5*20=10
YumYum247
  • YumYum247
yes....!!!!
YumYum247
  • YumYum247
i got that....
YumYum247
  • YumYum247
how do i figure out how far the runner will be in 1,2,3,4,5,6,7,8,9,10,11,12,13,14-20 secods
Michele_Laino
  • Michele_Laino
whereas the velocity of the car is constant the function v=4, is represented by the subsequent line: |dw:1438446099431:dw|
YumYum247
  • YumYum247
ok so that car will cover 4 meters every second...got that.
Michele_Laino
  • Michele_Laino
yes!
YumYum247
  • YumYum247
what about the runner tho :(
Michele_Laino
  • Michele_Laino
the space traveled by the runner, is given by the subsequent formula: \[\Large s\left( t \right) = \frac{1}{2}a{t^2}\]
YumYum247
  • YumYum247
i want to make a proper data table for both the car and the runner and plot those point on to the graph so it looks pretty neat.
YumYum247
  • YumYum247
what does "s" stand for?
Michele_Laino
  • Michele_Laino
"s(t)" stands for space as function of time
YumYum247
  • YumYum247
never learned about that in physics.. so can i use that formula to figure out the velocity of the runner at any given time???
Michele_Laino
  • Michele_Laino
in order to make a table, you have to consider these times: t=1 t=2 t=3 t=4 t=5 ... t=20 and compute the corresponding spaces, using this formula: \[\Large s\left( t \right) = \frac{1}{2}a{t^2} = \frac{1}{2} \times 0.5{t^2} = \frac{{{t^2}}}{4}\]
Michele_Laino
  • Michele_Laino
that is the graph for runner. In order to make a table for car, you have to consider the same times, namely: =1 t=2 t=3 t=4 t=5 ... t=20 and then you have to compute the distance using the subsequent formula: \[\Large s\left( t \right) = 4t\]
YumYum247
  • YumYum247
so what does s(t) = 4t means tho???
Michele_Laino
  • Michele_Laino
s(t)=4t, it is the space traveled by the car at time t
YumYum247
  • YumYum247
so 4 meters?
Michele_Laino
  • Michele_Laino
no, it is: 4*t where t is the time
Michele_Laino
  • Michele_Laino
for example, at t=2, we have: \[s\left( 2 \right) = 4 \times 2 = 8\]
YumYum247
  • YumYum247
yah but at 1 second, the runner covered 4meters right since 4X1sec = 4m?????
Michele_Laino
  • Michele_Laino
the car travelled 4*1= 4 meters, whereas the runner travelled 1/4= 0.25 meters
YumYum247
  • YumYum247
ok so the example that you gave me a second ago was for whome, the runner or the car.....???? car?
YumYum247
  • YumYum247
ok let me try and i'll get back to you......Thank you and bless you!!! :)
Michele_Laino
  • Michele_Laino
more explanation: \[\Large \begin{gathered} spac{e_{car}} = 4 \times t \hfill \\ \hfill \\ spac{e_{runner}} = \frac{{{t^2}}}{4} \hfill \\ \end{gathered} \]
YumYum247
  • YumYum247
ok i got it...Thanks make gotta wite the formula down.... Peace :)
Michele_Laino
  • Michele_Laino
:)
YumYum247
  • YumYum247
:)
YumYum247
  • YumYum247
ok i didn't quite get this.....Space runner = t^2/4 because i'm not getting the same number here....|dw:1438459291397:dw|
YumYum247
  • YumYum247
@Michele_Laino
YumYum247
  • YumYum247
oh never mind now i see that......i thought you wrote something else.... Cheers!!!!
YumYum247
  • YumYum247
buddy there is something wrong here, the runner reaches a velocity of 100m/sec in 20 sec.....doesn't sound right to me
YumYum247
  • YumYum247
the answer key suggest 10m/sec at 20 sec.
YumYum247
  • YumYum247
@Elsa213 help plz
YumYum247
  • YumYum247
@sweetburger
YumYum247
  • YumYum247
i need to know how do i make data-table from average velocity in m/sec2
YumYum247
  • YumYum247
@nincompoop
YumYum247
  • YumYum247
@nincompoop
nincompoop
  • nincompoop
you were given the information already
YumYum247
  • YumYum247
i want to know how do i make a data table of average velocity.......
nincompoop
  • nincompoop
|dw:1438452273488:dw|
nincompoop
  • nincompoop
i keep telling you, your AVERAGE VELOCITY IS your slope
YumYum247
  • YumYum247
but how do i know how far will the runner be in let's say 7 sec????
nincompoop
  • nincompoop
|dw:1438452404287:dw|
nincompoop
  • nincompoop
that is the point when you actually SOLVE it :)
YumYum247
  • YumYum247
yes yes yes!!! :D
nincompoop
  • nincompoop
Mary Jesus, Joseph, Muhammad
YumYum247
  • YumYum247
the car is no problem, it's going at 4m/sec
nincompoop
  • nincompoop
and?
nincompoop
  • nincompoop
what does that mean
YumYum247
  • YumYum247
i can figure out how far the car will be at any given time but i'm not so sure about the runner tho???
nincompoop
  • nincompoop
what does 4m/s mean? that means that your distance is 4 meters per 1 sec so in your plot for 1 sec you put distance at 4
YumYum247
  • YumYum247
ok let me ask you a question.....how far will the runner be in 7 seconds????
nincompoop
  • nincompoop
that is when you solve it do you know that acceleration is the change in VELOCITY/time ?
YumYum247
  • YumYum247
it means the car is convering 4meters every sec. so o nthe velocity time graph it's just be a flat straight line
YumYum247
  • YumYum247
|dw:1438452675130:dw|
YumYum247
  • YumYum247
so acceleration = Velocity/time
YumYum247
  • YumYum247
|dw:1438452731926:dw|
YumYum247
  • YumYum247
so by 20 sec, the runner have covered 0.025m????what??????????

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