help Please!!!

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How do i create the data table to plot the velocity time graph?

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Other answers:

......for both the runner and the car?
the velocity of the car is v=cost=4 m/sec whereas the velocity of the runner is v=a*t=0.5*t
ok what is "cost"?
|dw:1438445437066:dw|
"cost" stands for constant
ok but how do i make the data table to plot the points on the graph. and how did you know the graph looks like this????
since the function: \[v = at\] is represented by a line which passes at the origin, in the (t, v) plane
i mean how did you make the graph without T(sec) Velocity m/sec 0 0 1 some number 2 some number
is the acceleration along of 20 seconds of time?
i don't know!!! :(
from your text I see that the runner accelerates for 20 seconds
yah....!!!
ok tell me how do i make the data table from velocity and average velocity???
ok so the graph of this function: \[v\left( t \right) = at = 0.5t\] passes at point t=0, v=0 and passes at point t=20, v=0.5*20=10
yes....!!!!
i got that....
how do i figure out how far the runner will be in 1,2,3,4,5,6,7,8,9,10,11,12,13,14-20 secods
whereas the velocity of the car is constant the function v=4, is represented by the subsequent line: |dw:1438446099431:dw|
ok so that car will cover 4 meters every second...got that.
yes!
what about the runner tho :(
the space traveled by the runner, is given by the subsequent formula: \[\Large s\left( t \right) = \frac{1}{2}a{t^2}\]
i want to make a proper data table for both the car and the runner and plot those point on to the graph so it looks pretty neat.
what does "s" stand for?
"s(t)" stands for space as function of time
never learned about that in physics.. so can i use that formula to figure out the velocity of the runner at any given time???
in order to make a table, you have to consider these times: t=1 t=2 t=3 t=4 t=5 ... t=20 and compute the corresponding spaces, using this formula: \[\Large s\left( t \right) = \frac{1}{2}a{t^2} = \frac{1}{2} \times 0.5{t^2} = \frac{{{t^2}}}{4}\]
that is the graph for runner. In order to make a table for car, you have to consider the same times, namely: =1 t=2 t=3 t=4 t=5 ... t=20 and then you have to compute the distance using the subsequent formula: \[\Large s\left( t \right) = 4t\]
so what does s(t) = 4t means tho???
s(t)=4t, it is the space traveled by the car at time t
so 4 meters?
no, it is: 4*t where t is the time
for example, at t=2, we have: \[s\left( 2 \right) = 4 \times 2 = 8\]
yah but at 1 second, the runner covered 4meters right since 4X1sec = 4m?????
the car travelled 4*1= 4 meters, whereas the runner travelled 1/4= 0.25 meters
ok so the example that you gave me a second ago was for whome, the runner or the car.....???? car?
ok let me try and i'll get back to you......Thank you and bless you!!! :)
more explanation: \[\Large \begin{gathered} spac{e_{car}} = 4 \times t \hfill \\ \hfill \\ spac{e_{runner}} = \frac{{{t^2}}}{4} \hfill \\ \end{gathered} \]
ok i got it...Thanks make gotta wite the formula down.... Peace :)
:)
:)
ok i didn't quite get this.....Space runner = t^2/4 because i'm not getting the same number here....|dw:1438459291397:dw|
oh never mind now i see that......i thought you wrote something else.... Cheers!!!!
buddy there is something wrong here, the runner reaches a velocity of 100m/sec in 20 sec.....doesn't sound right to me
the answer key suggest 10m/sec at 20 sec.
@Elsa213 help plz
i need to know how do i make data-table from average velocity in m/sec2
you were given the information already
i want to know how do i make a data table of average velocity.......
|dw:1438452273488:dw|
i keep telling you, your AVERAGE VELOCITY IS your slope
but how do i know how far will the runner be in let's say 7 sec????
|dw:1438452404287:dw|
that is the point when you actually SOLVE it :)
yes yes yes!!! :D
Mary Jesus, Joseph, Muhammad
the car is no problem, it's going at 4m/sec
and?
what does that mean
i can figure out how far the car will be at any given time but i'm not so sure about the runner tho???
what does 4m/s mean? that means that your distance is 4 meters per 1 sec so in your plot for 1 sec you put distance at 4
ok let me ask you a question.....how far will the runner be in 7 seconds????
that is when you solve it do you know that acceleration is the change in VELOCITY/time ?
it means the car is convering 4meters every sec. so o nthe velocity time graph it's just be a flat straight line
|dw:1438452675130:dw|
so acceleration = Velocity/time
|dw:1438452731926:dw|
so by 20 sec, the runner have covered 0.025m????what??????????

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