## YumYum247 one year ago help Please!!!

1. YumYum247

2. YumYum247

How do i create the data table to plot the velocity time graph?

3. YumYum247

@Michele_Laino

4. YumYum247

......for both the runner and the car?

5. Michele_Laino

the velocity of the car is v=cost=4 m/sec whereas the velocity of the runner is v=a*t=0.5*t

6. YumYum247

ok what is "cost"?

7. Michele_Laino

|dw:1438445437066:dw|

8. Michele_Laino

"cost" stands for constant

9. YumYum247

ok but how do i make the data table to plot the points on the graph. and how did you know the graph looks like this????

10. Michele_Laino

since the function: $v = at$ is represented by a line which passes at the origin, in the (t, v) plane

11. YumYum247

i mean how did you make the graph without T(sec) Velocity m/sec 0 0 1 some number 2 some number

12. Michele_Laino

is the acceleration along of 20 seconds of time?

13. YumYum247

i don't know!!! :(

14. Michele_Laino

from your text I see that the runner accelerates for 20 seconds

15. YumYum247

yah....!!!

16. YumYum247

ok tell me how do i make the data table from velocity and average velocity???

17. Michele_Laino

ok so the graph of this function: $v\left( t \right) = at = 0.5t$ passes at point t=0, v=0 and passes at point t=20, v=0.5*20=10

18. YumYum247

yes....!!!!

19. YumYum247

i got that....

20. YumYum247

how do i figure out how far the runner will be in 1,2,3,4,5,6,7,8,9,10,11,12,13,14-20 secods

21. Michele_Laino

whereas the velocity of the car is constant the function v=4, is represented by the subsequent line: |dw:1438446099431:dw|

22. YumYum247

ok so that car will cover 4 meters every second...got that.

23. Michele_Laino

yes!

24. YumYum247

what about the runner tho :(

25. Michele_Laino

the space traveled by the runner, is given by the subsequent formula: $\Large s\left( t \right) = \frac{1}{2}a{t^2}$

26. YumYum247

i want to make a proper data table for both the car and the runner and plot those point on to the graph so it looks pretty neat.

27. YumYum247

what does "s" stand for?

28. Michele_Laino

"s(t)" stands for space as function of time

29. YumYum247

never learned about that in physics.. so can i use that formula to figure out the velocity of the runner at any given time???

30. Michele_Laino

in order to make a table, you have to consider these times: t=1 t=2 t=3 t=4 t=5 ... t=20 and compute the corresponding spaces, using this formula: $\Large s\left( t \right) = \frac{1}{2}a{t^2} = \frac{1}{2} \times 0.5{t^2} = \frac{{{t^2}}}{4}$

31. Michele_Laino

that is the graph for runner. In order to make a table for car, you have to consider the same times, namely: =1 t=2 t=3 t=4 t=5 ... t=20 and then you have to compute the distance using the subsequent formula: $\Large s\left( t \right) = 4t$

32. YumYum247

so what does s(t) = 4t means tho???

33. Michele_Laino

s(t)=4t, it is the space traveled by the car at time t

34. YumYum247

so 4 meters?

35. Michele_Laino

no, it is: 4*t where t is the time

36. Michele_Laino

for example, at t=2, we have: $s\left( 2 \right) = 4 \times 2 = 8$

37. YumYum247

yah but at 1 second, the runner covered 4meters right since 4X1sec = 4m?????

38. Michele_Laino

the car travelled 4*1= 4 meters, whereas the runner travelled 1/4= 0.25 meters

39. YumYum247

ok so the example that you gave me a second ago was for whome, the runner or the car.....???? car?

40. YumYum247

ok let me try and i'll get back to you......Thank you and bless you!!! :)

41. Michele_Laino

more explanation: $\Large \begin{gathered} spac{e_{car}} = 4 \times t \hfill \\ \hfill \\ spac{e_{runner}} = \frac{{{t^2}}}{4} \hfill \\ \end{gathered}$

42. YumYum247

ok i got it...Thanks make gotta wite the formula down.... Peace :)

43. Michele_Laino

:)

44. YumYum247

:)

45. YumYum247

ok i didn't quite get this.....Space runner = t^2/4 because i'm not getting the same number here....|dw:1438459291397:dw|

46. YumYum247

@Michele_Laino

47. YumYum247

oh never mind now i see that......i thought you wrote something else.... Cheers!!!!

48. YumYum247

buddy there is something wrong here, the runner reaches a velocity of 100m/sec in 20 sec.....doesn't sound right to me

49. YumYum247

the answer key suggest 10m/sec at 20 sec.

50. YumYum247

@Elsa213 help plz

51. YumYum247

@sweetburger

52. YumYum247

i need to know how do i make data-table from average velocity in m/sec2

53. YumYum247

@nincompoop

54. YumYum247

@nincompoop

55. nincompoop

you were given the information already

56. YumYum247

i want to know how do i make a data table of average velocity.......

57. nincompoop

|dw:1438452273488:dw|

58. nincompoop

i keep telling you, your AVERAGE VELOCITY IS your slope

59. YumYum247

but how do i know how far will the runner be in let's say 7 sec????

60. nincompoop

|dw:1438452404287:dw|

61. nincompoop

that is the point when you actually SOLVE it :)

62. YumYum247

yes yes yes!!! :D

63. nincompoop

Mary Jesus, Joseph, Muhammad

64. YumYum247

the car is no problem, it's going at 4m/sec

65. nincompoop

and?

66. nincompoop

what does that mean

67. YumYum247

i can figure out how far the car will be at any given time but i'm not so sure about the runner tho???

68. nincompoop

what does 4m/s mean? that means that your distance is 4 meters per 1 sec so in your plot for 1 sec you put distance at 4

69. YumYum247

ok let me ask you a question.....how far will the runner be in 7 seconds????

70. nincompoop

that is when you solve it do you know that acceleration is the change in VELOCITY/time ?

71. YumYum247

it means the car is convering 4meters every sec. so o nthe velocity time graph it's just be a flat straight line

72. YumYum247

|dw:1438452675130:dw|

73. YumYum247

so acceleration = Velocity/time

74. YumYum247

|dw:1438452731926:dw|

75. YumYum247

so by 20 sec, the runner have covered 0.025m????what??????????