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anonymous

  • one year ago

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  1. rhr12
    • one year ago
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    Help for what?

  2. anonymous
    • one year ago
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    @welshfella

  3. rhr12
    • one year ago
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    Easy prb. Hold on. Lemme take a look

  4. welshfella
    • one year ago
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    first you need to factor x^2 + 12x + 35 the factors will look like (x + a)(x + b) where a*b = 35 and a + b = 12 so can you work out the values of a and b are?

  5. welshfella
    • one year ago
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    factor 35

  6. anonymous
    • one year ago
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    7 and 5?

  7. welshfella
    • one year ago
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    right good now we need to factor the denominator

  8. rhr12
    • one year ago
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    X2+11/3 for the first one

  9. welshfella
    • one year ago
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    3x + 15

  10. anonymous
    • one year ago
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    what 3x +15?

  11. anonymous
    • one year ago
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    oh nevermind

  12. anonymous
    • one year ago
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    3(x+5)?

  13. welshfella
    • one year ago
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    3x + 15 factors to what?

  14. anonymous
    • one year ago
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    3(x+5)?

  15. welshfella
    • one year ago
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    right so we have (x + 5)( x + 7) ----------- 3 ( x + 5)

  16. anonymous
    • one year ago
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    so x+7/3 right?

  17. rhr12
    • one year ago
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    Get it?

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  18. welshfella
    • one year ago
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    right

  19. anonymous
    • one year ago
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    @rhr12 i think you are wrong

  20. rhr12
    • one year ago
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    My bad. Its not possible

  21. anonymous
    • one year ago
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    @welshfella what about the next one?

  22. rhr12
    • one year ago
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    Sorry.

  23. welshfella
    • one year ago
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    No that is wrong rhrh12 you cannot divide those terms because the top and bottom are sums not products

  24. anonymous
    • one year ago
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    @welshfella what about the next one?

  25. anonymous
    • one year ago
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    isn't the next one b?

  26. welshfella
    • one year ago
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    that's easy factor 2x - 12 then simplify

  27. anonymous
    • one year ago
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    b?

  28. welshfella
    • one year ago
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    yes

  29. anonymous
    • one year ago
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    the third one?

  30. welshfella
    • one year ago
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    easy also factor 4x + 16

  31. anonymous
    • one year ago
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    4(x+4)

  32. welshfella
    • one year ago
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    right now simplify 4(x + 4) ------ 6

  33. anonymous
    • one year ago
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    not sure what i do next

  34. welshfella
    • one year ago
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    what is a common factor of 4 and 6?

  35. anonymous
    • one year ago
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    2

  36. anonymous
    • one year ago
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    isn't it B also?

  37. welshfella
    • one year ago
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    right so divide 4 and 6 by 2

  38. welshfella
    • one year ago
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    |dw:1438446007131:dw|

  39. anonymous
    • one year ago
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    isn't it B?

  40. welshfella
    • one year ago
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    no

  41. anonymous
    • one year ago
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    a?

  42. welshfella
    • one year ago
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    yes

  43. welshfella
    • one year ago
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    you divide top and bottom by 2 to get 2 / 3

  44. anonymous
    • one year ago
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    can i ask you a few more?

  45. welshfella
    • one year ago
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    well one more

  46. anonymous
    • one year ago
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  47. welshfella
    • one year ago
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    then hopefully you can do the rest yourself thats the best way to learn - practice them yourself

  48. welshfella
    • one year ago
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    factoring 4x^2 - 7x + 3 is a bit more difficult than those with x^2 only

  49. welshfella
    • one year ago
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    you know that the letters a and b must be -3 and -1 because they product is + 3 and you need -7x in the middle

  50. welshfella
    • one year ago
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    so its 4x and x as first part of the 2 bracketes |dw:1438446430986:dw|

  51. welshfella
    • one year ago
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    so top part is (4x - 3)x - 1)

  52. anonymous
    • one year ago
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    okay

  53. welshfella
    • one year ago
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    the bottom part is easier you need 2 numbers whose product is -6 and whose sum is + 5

  54. anonymous
    • one year ago
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    6 and -1

  55. welshfella
    • one year ago
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    so it must be -6 and + 1 or +6 and -1

  56. welshfella
    • one year ago
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    you are right so we have (4x - 3)(x - 1) ------------ (x + 6)(x - 1)

  57. anonymous
    • one year ago
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    x-1 cancel so its D right?

  58. welshfella
    • one year ago
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    yes correct

  59. anonymous
    • one year ago
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    thanks

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