anonymous
  • anonymous
1.) Find the area of a regular hexagon with an apothem 10.4 yards long and a side 12 yards long. Round your answer to the nearest tenth. My answer: 312square yards. Is that correct? 2.) Question is: A park in a subdivision is triangular-shaped. Two adjacent sides of the park are 533 feet and 525 feet. The angle between the sides is 53 degrees. Find the area of the park to the nearest square foot. My answer: 111739.09. Is that correct?
Mathematics
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anonymous
  • anonymous
1.) Find the area of a regular hexagon with an apothem 10.4 yards long and a side 12 yards long. Round your answer to the nearest tenth. My answer: 312square yards. Is that correct? 2.) Question is: A park in a subdivision is triangular-shaped. Two adjacent sides of the park are 533 feet and 525 feet. The angle between the sides is 53 degrees. Find the area of the park to the nearest square foot. My answer: 111739.09. Is that correct?
Mathematics
schrodinger
  • schrodinger
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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rhr12
  • rhr12
find the area of each of the 6 equilateral triangles making up the hexagon Each side of triangle = 12 yards { by the way, first check apothem length because it is our altitude ) tan 30 = (1/2)(12)/apothem apothem = 6/tan 30 = 10.4 - sure enough, whew } so area of triangle = (1/2)(base)(apothem) = .5 * 12 * 10.4 = 62.4 so 6 of them is 6*62.4 = 374 yd^2
rhr12
  • rhr12
That's what i got
rhr12
  • rhr12
= 111739 square feet

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rhr12
  • rhr12
Thats i got for the second one.
rhr12
  • rhr12
U r correct for the second one. But i got a different answer for the first one
anonymous
  • anonymous
Alright. Thank you.
anonymous
  • anonymous
How did you get the second one?
anonymous
  • anonymous
rhr12
  • rhr12
Area = (1/2)(533 ft)(525 ft) sin(53) = 111739 square feet
anonymous
  • anonymous
Alright. Thank you
anonymous
  • anonymous
@Michele_Laino is this information correct?
anonymous
  • anonymous
that rhr put
Michele_Laino
  • Michele_Laino
question #1 perimeter=6*12=72 yards, so: \[\Large \begin{gathered} area = \frac{{perimeter \times apothem}}{2} = \hfill \\ \hfill \\ = \frac{{10.4 \times 72}}{2} = 374.4 \hfill \\ \end{gathered} \]
Michele_Laino
  • Michele_Laino
question#2 the requested area is: \[\Large Area = \frac{1}{2} \times 533 \times 525 \times \sin 53 = 111,739.0907\]
Michele_Laino
  • Michele_Laino
so, the second answer is correct!
anonymous
  • anonymous
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  • anonymous
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