## anonymous one year ago .

1. anonymous

@ganeshie8

2. anonymous

could you please do both? Thanks

3. rhr12

sorry for the wrong try for last question. Not enough brave to try another one.

4. anonymous

5. anonymous

@SiggitySwoogity

6. anonymous

The last question is D. but would you want me to explain how to get that?

7. anonymous

Did you need the first question too?

8. anonymous

@jcoury

9. anonymous

Scared bro. @rhr12

10. anonymous

yes

11. anonymous

Yes to both questions?

12. anonymous

yes

13. anonymous

think the first one is A

14. anonymous

Question 6:$\frac{ x^2-15x+56 }{ x-7 }$

15. anonymous

Yes that's what I thought too.

16. anonymous

$\frac{ (x-7)(x-8) }{ x-7 }$

17. anonymous

Do you know how I got to that step?

18. anonymous

yes

19. anonymous

|dw:1438449674703:dw|

20. anonymous

what about this? Simplify completely quantity 12 x plus 36 over quantity x squared minus 4 x minus 21 and find the restrictions on the variable.

21. anonymous

Cancel the (x-7) and you get (x-8) which is D.

22. anonymous

Can you show that as an equation or picture? It's easier to understand that way. :)

23. anonymous

24. anonymous

|dw:1438449862391:dw|

25. anonymous

26. anonymous

It can't be positive 7 since the denominator will turn 0 making the answer not available or 0.

27. anonymous

Did you get that?

28. anonymous

@jcoury

29. anonymous

What do you mean?

30. anonymous

abcd

31. anonymous

A

32. anonymous

Are they the same kind of questions?

33. anonymous

Let me see them.

34. anonymous

35. anonymous

Okay hold on.

36. anonymous

Ya I am

37. anonymous

okay i gtg just do all of the steps for the problems and i'll look at them when i come back

38. anonymous

Alright

39. anonymous

A. for the question above Question 9.$\frac{ 5x^2-21x-20 }{ 5x^2-16x-16 }$$\frac{ (x-5)(5x+4) }{ (x-4)(5x+4) }$$\frac{ (x-5) }{ (x-4) }$

40. anonymous

Question 9:$\frac{ 2x^2+20x+32 }{ x^2-2x-80 }$$\frac{ 2(x^2+10x+16) }{ x^2-2x-80 }$$\frac{ 2(x+8)(x+2) }{ (x-10)(x+8) }$$\frac{ 2(x+2) }{ (x-10) }$

41. anonymous

$\frac{ 2x^2+16x+30 }{ 5x^2+13x-6 }$$\frac{ 2(x^2+8x+15) }{ 5x^2+13x-6 }$$\frac{ 2(x+3)(x+5) }{ (x+3)(5x-2) }$$\frac{ 2(x+5) }{ (5x-2) }$This is the question that is by itself in the picture. Hope this helps! :)