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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    @ganeshie8

  2. anonymous
    • one year ago
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    could you please do both? Thanks

  3. rhr12
    • one year ago
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    sorry for the wrong try for last question. Not enough brave to try another one.

  4. anonymous
    • one year ago
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    can someone please help?

  5. anonymous
    • one year ago
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    @SiggitySwoogity

  6. anonymous
    • one year ago
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    The last question is D. but would you want me to explain how to get that?

  7. anonymous
    • one year ago
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    Did you need the first question too?

  8. anonymous
    • one year ago
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    @jcoury

  9. anonymous
    • one year ago
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    Scared bro. @rhr12

  10. anonymous
    • one year ago
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    yes

  11. anonymous
    • one year ago
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    Yes to both questions?

  12. anonymous
    • one year ago
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    yes

  13. anonymous
    • one year ago
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    think the first one is A

  14. anonymous
    • one year ago
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    Question 6:\[\frac{ x^2-15x+56 }{ x-7 }\]

  15. anonymous
    • one year ago
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    Yes that's what I thought too.

  16. anonymous
    • one year ago
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    \[\frac{ (x-7)(x-8) }{ x-7 }\]

  17. anonymous
    • one year ago
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    Do you know how I got to that step?

  18. anonymous
    • one year ago
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    yes

  19. anonymous
    • one year ago
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    |dw:1438449674703:dw|

  20. anonymous
    • one year ago
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    what about this? Simplify completely quantity 12 x plus 36 over quantity x squared minus 4 x minus 21 and find the restrictions on the variable.

  21. anonymous
    • one year ago
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    Cancel the (x-7) and you get (x-8) which is D.

  22. anonymous
    • one year ago
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    Can you show that as an equation or picture? It's easier to understand that way. :)

  23. anonymous
    • one year ago
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    1 Attachment
  24. anonymous
    • one year ago
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    |dw:1438449862391:dw|

  25. anonymous
    • one year ago
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    Answer A.

  26. anonymous
    • one year ago
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    It can't be positive 7 since the denominator will turn 0 making the answer not available or 0.

  27. anonymous
    • one year ago
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    Did you get that?

  28. anonymous
    • one year ago
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    @jcoury

  29. anonymous
    • one year ago
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    What do you mean?

  30. anonymous
    • one year ago
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    abcd

  31. anonymous
    • one year ago
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    A

  32. anonymous
    • one year ago
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    Are they the same kind of questions?

  33. anonymous
    • one year ago
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    Let me see them.

  34. anonymous
    • one year ago
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  35. anonymous
    • one year ago
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    Okay hold on.

  36. anonymous
    • one year ago
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    Ya I am

  37. anonymous
    • one year ago
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    okay i gtg just do all of the steps for the problems and i'll look at them when i come back

  38. anonymous
    • one year ago
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    Alright

  39. anonymous
    • one year ago
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    A. for the question above Question 9.\[\frac{ 5x^2-21x-20 }{ 5x^2-16x-16 }\]\[\frac{ (x-5)(5x+4) }{ (x-4)(5x+4) }\]\[\frac{ (x-5) }{ (x-4) }\]

  40. anonymous
    • one year ago
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    Question 9:\[\frac{ 2x^2+20x+32 }{ x^2-2x-80 }\]\[\frac{ 2(x^2+10x+16) }{ x^2-2x-80 }\]\[\frac{ 2(x+8)(x+2) }{ (x-10)(x+8) }\]\[\frac{ 2(x+2) }{ (x-10) }\]

  41. anonymous
    • one year ago
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    \[\frac{ 2x^2+16x+30 }{ 5x^2+13x-6 }\]\[\frac{ 2(x^2+8x+15) }{ 5x^2+13x-6 }\]\[\frac{ 2(x+3)(x+5) }{ (x+3)(5x-2) }\]\[\frac{ 2(x+5) }{ (5x-2) }\]This is the question that is by itself in the picture. Hope this helps! :)

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