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ganeshie8
 one year ago
show that \(\sin(x)+\sin(x120^{\circ})+\sin(x240^{\circ})=0\)
ganeshie8
 one year ago
show that \(\sin(x)+\sin(x120^{\circ})+\sin(x240^{\circ})=0\)

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1my roomate and i are arguing about electric motors and im looking for some geometric explanation for this..

Empty
 one year ago
Best ResponseYou've already chosen the best response.2what's true for x=0 is always true no matter how you rotate it

Empty
 one year ago
Best ResponseYou've already chosen the best response.2\[e^{i x}(e^{i 2 \pi / 3} +e^{i 2 \pi 2/ 3} +e^{i 2 \pi 3/ 3}) =0\] the real part of that

Empty
 one year ago
Best ResponseYou've already chosen the best response.2imaginary part I mean, whatever, both are zero haha

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2it is a three phase system

rhr12
 one year ago
Best ResponseYou've already chosen the best response.2x + 120 = t sin(t  120) + sin(t) + sin(t + 120) = 0 sin(t)cos(120)  sin(120)cos(t) + sin(t) + sin(t)cos(120) + sin(120)cos(t) = 0 2 * cos(120) * sin(t) + sin(t) = 0 sin(t) * (2 * cos(120) + 1) = 0 sin(t) * (2 * (1/2) + 1) = 0 sin(t) * (1 + 1) = 0 sin(t) * 0 = 0 So, sin(t) can equal pretty much anything t = x + 120 sin(x + 120) can be anything x + 120 can be anything x can be anything There are no wrong solutions for this one.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1Yes he is saying delta/star and some bs which i have no idea about... but it makes sense to think in terms of roots of unity as Empty wa suggesting.. (if im interepreting correctly..)

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2dw:1438447767342:dw

Empty
 one year ago
Best ResponseYou've already chosen the best response.2x and y components of vectors are linearly independent in 2D. So in order for vectors to be in equilibrium in 2D their components must be in equilibrium too. That's what I'm saying

Empty
 one year ago
Best ResponseYou've already chosen the best response.2complex numbers are just a cute representation of 2d vectors I am so used to just thinking with them I forget other people aren't

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dw:1438448479126:dw

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1welcome to the club @ruhan11
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