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anonymous
 one year ago
Just wanted to check my answers if they are right. (See below)
anonymous
 one year ago
Just wanted to check my answers if they are right. (See below)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.01.)\[\frac{ x4 }{ x^23x4 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My answer: \[\frac{ 1 }{ (x+1) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks! 2.) \[\frac{ x^38 }{ x2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My answer:\[(x+2)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think u can simplify more than that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would I simplify that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't think I factored the numerator right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0start by putting the 8 into 2^3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and use the difference of cubes which is \[a^3−b^3=(a−b)(a^2+ab+b^2)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it will get you \[(x−2)(x^2+(x)(2)+2^2)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Simplify 2^2 to 4 and regroup terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (x−2)(x^2+2x+4) }{ x2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now just cancel the x2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ya I got it. Wasn't that the same answer I got?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I wrote the same answer.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x^2+2x +4 \neq (x+2)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ya sorry about that. Just noticed.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would have to use the quadratic formula for this right?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.0\(a^3b^3=(xa)(a^2+ab+b^2)\) \(x^32^3=(x2)(x^2+2x+2^2)=x^2+2x+4\) \(\Large\frac{x^38}{x2}=\frac{x^22^3}{x2}=\frac{(x2)(x^2+2x+4)}{x2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ya I got that so far. Thanks!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 2\pm \sqrt{2^24(1)(4)} }{ 2(1) }\]\[\frac{ 2\pm \sqrt{416} }{ 2 }\]\[\frac{ 2\pm \sqrt{12} }{ 2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The answer is going to have an i?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.0Yes. That's why it cant be factored. If you get complex numbers when factoring, then the polynomial is irreducible. x^2+2x+4 is a prime polynomial.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So I don't have to simplify that then? Do I just put x^2+2x+4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright thanks! 3.)\[\frac{ 5x }{ x^225 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My answer:\[\frac{ 1 }{ x+5 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04.) \[\frac{ x^24x32 }{ x^216 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My answer:\[\frac{ x8 }{ x4 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks! What about #4?
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