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anonymous
 one year ago
It takes 0.225 seconds/revolution for a body of mass of 25 grams to rotate a circle with a radius of 15 cm. What is the centripetal force acting on that body?
anonymous
 one year ago
It takes 0.225 seconds/revolution for a body of mass of 25 grams to rotate a circle with a radius of 15 cm. What is the centripetal force acting on that body?

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welshfella
 one year ago
Best ResponseYou've already chosen the best response.1force = m w r^2 F is in Newtons . mass in kgs and r in meters w = the angular velocity in radians / sec you can work this out from the given speed in revs / sec.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how can I convert seconds/revolution to radians/sec?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.11 rev = 2 pi radians it travels 2 pi radians in 0.225 secs so in 1 second it travels 2 pi / 0.225 radians

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1w = 8.89 pi rads/sec

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1now you need to convert 25 gms to kgs and 15 cms to meters.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer for the centripetal force?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1not quite  you need to multiply that by pi

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry i forgot to put pi, is it 0.0157?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1yes thats in newtons

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1you can write it as 1.57 * 10^2 N

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer is not in the choices :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know other formulas maybe we can try that :)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1oh  maybe i've gone wrong somewhere  its been a while since i did these what are the choices?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[T = 2\pi(r) \over v\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.00.731 N, 749.47 N, 187.368 dynes, 2,924 N

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0Isn't centripetal force \[\sf F_c = \frac{ mv^2}{r}\]

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1yes where v = linear velocity

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0since centripetal acceleration = \(\sf a_c = \dfrac{v^2}{r}\)

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.0cool, I still remember \(\checkmark\) haha

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1yea my memory has failed me here I should have checked

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1i was too confident lol!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[T = \frac{ (2\pi(r)) }{ v }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1438464437672:dw

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1my original equation should have been m w^2 r so F = 0.025 * (8.89pi)^2 * 0.15

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh it's 2.924 thank you :D

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with another problem ? :)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.1well i only have 10 minutes but see what i can do
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