anonymous
  • anonymous
It takes 0.225 seconds/revolution for a body of mass of 25 grams to rotate a circle with a radius of 15 cm. What is the centripetal force acting on that body?
Mathematics
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anonymous
  • anonymous
It takes 0.225 seconds/revolution for a body of mass of 25 grams to rotate a circle with a radius of 15 cm. What is the centripetal force acting on that body?
Mathematics
schrodinger
  • schrodinger
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welshfella
  • welshfella
force = m w r^2 F is in Newtons . mass in kgs and r in meters w = the angular velocity in radians / sec you can work this out from the given speed in revs / sec.
anonymous
  • anonymous
how can I convert seconds/revolution to radians/sec?
welshfella
  • welshfella
1 rev = 2 pi radians it travels 2 pi radians in 0.225 secs so in 1 second it travels 2 pi / 0.225 radians

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welshfella
  • welshfella
w = 8.89 pi rads/sec
anonymous
  • anonymous
5x10^(-3) ?
welshfella
  • welshfella
now you need to convert 25 gms to kgs and 15 cms to meters.
welshfella
  • welshfella
what is 5x10^-3 ?
anonymous
  • anonymous
the answer for the centripetal force?
welshfella
  • welshfella
hmm..
welshfella
  • welshfella
not quite - you need to multiply that by pi
anonymous
  • anonymous
sorry i forgot to put pi, is it 0.0157?
welshfella
  • welshfella
yes thats in newtons
welshfella
  • welshfella
you can write it as 1.57 * 10^-2 N
anonymous
  • anonymous
the answer is not in the choices :(
anonymous
  • anonymous
i know other formulas maybe we can try that :)
welshfella
  • welshfella
oh - maybe i've gone wrong somewhere - its been a while since i did these what are the choices?
anonymous
  • anonymous
\[T = 2\pi(r) \over v\]
anonymous
  • anonymous
0.731 N, 749.47 N, 187.368 dynes, 2,924 N
Jhannybean
  • Jhannybean
Isn't centripetal force \[\sf F_c = \frac{ mv^2}{r}\]
welshfella
  • welshfella
yes where v = linear velocity
anonymous
  • anonymous
Jhannybean
  • Jhannybean
since centripetal acceleration = \(\sf a_c = \dfrac{v^2}{r}\)
Jhannybean
  • Jhannybean
cool, I still remember \(\checkmark\) haha
welshfella
  • welshfella
yea my memory has failed me here I should have checked
welshfella
  • welshfella
i was too confident lol!
anonymous
  • anonymous
\[T = \frac{ (2\pi(r)) }{ v }\]
anonymous
  • anonymous
|dw:1438464437672:dw|
anonymous
  • anonymous
is it correct?
welshfella
  • welshfella
my original equation should have been m w^2 r so F = 0.025 * (8.89pi)^2 * 0.15
anonymous
  • anonymous
oh it's 2.924 thank you :D
welshfella
  • welshfella
= 2.925 N
anonymous
  • anonymous
Can you help me with another problem ? :)
welshfella
  • welshfella
2.924
welshfella
  • welshfella
well i only have 10 minutes but see what i can do
anonymous
  • anonymous
thank you :)

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